过滤javascript中不存在的txt字符串的一部分
过滤javascript中不存在的txt字符串的一部分
提问于 2018-10-03 16:58:53
我在一个geojson多边形文件中有不同组合的属性，比如:星期一-星期五或者星期二-星期五或者星期二，星期三，星期五或者星期一，清华或者星期三等等。
我需要的是在Leaflet中显示在文本字符串中没有值"Mon“(星期一)的多边形。我怎么才能过滤掉呢？我正在用这个代码做其他过滤...
var non_mon = new L.layerGroup();
$.getJSON("..data/polygons.geojson", function(json) {
var vectorGrid = L.vectorGrid.slicer(json, {
maxZoom: 20,
rendererFactory: L.svg.tile,
vectorTileLayerStyles: {
sliced: function(properties, zoom){
var dayint = properties.Days_1
if (dayint = "does not have Mån" ){
return{
weight: 0.5,
color: '#ffffff',
opacity: 1,
fill: true,
fillColor: '#ff0000',
stroke: true,
fillOpacity: 0.6
}
} else {
return {
weight: 0,
fill: false,
stroke: false
}
}
}},
interactive: true,
})
.on('click', function(e) {
var properties = e.layer.properties;
L.popup()
.setContent(
"<b>Weekdays</b>" + '\xa0\xa0' + properties.Days_1 + '</b>' +
"<br>Date from: " + '<i>' + properties.Date + '</i>' )
.setLatLng(e.latlng)
.openOn(map);
})
vectorGrid.addTo(non_mon)
}) 这就是GeoJSON的外观
{ "type": "Feature", "properties": { "Days_1": "Mån-Fre" },
{ "type": "Feature", "properties": { "Days_1": "Tis-Fre" },
{ "type": "Feature", "properties": { "Days_1": "Ons-Fre" },
{ "type": "Feature", "properties": { "Days_1": "Tors,Fre" },
{ "type": "Feature", "properties": { "Days_1": "Mån,Ons,Fre" },
{ "type": "Feature", "properties": { "Days_1": "Tis,Ons-Fre" },
{ "type": "Feature", "properties": { "Days_1": "Ons,Tors" },
{ "type": "Feature", "properties": { "Days_1": "Mån" },
{ "type": "Feature", "properties": { "Days_1": "Tis" },
{ "type": "Feature", "properties": { "Days_1": "Ons" },
{ "type": "Feature", "properties": { "Days_1": "Tors" },
{ "type": "Feature", "properties": { "Days_1": "Fre" },
{ "type": "Feature", "properties": { "Days_1": "Tis-Tors" },
{ "type": "Feature", "properties": { "Days_1": "Mån-Tors" },
{ "type": "Feature", "properties": { "Days_1": "Ons,Fre" },
{ "type": "Feature", "properties": { "Days_1": null },回答 1
Stack Overflow用户
发布于 2018-10-04 03:05:09
好了，你想要过滤所有'Days_1‘属性不包含字符串’Mn‘的行。你可以这样做：
var geoJson = [...]; // Your GeoJSON
// After this function call 'filtered' contains the filtered list of GeoJSON features
var filtered = geoJson.filter(
function(element) {
// We are only interested in elements which do not contain 'Mån'
return element.indexOf("Mån") != -1;
}
);在本例中，我们使用了数组原型的“filter”方法部分。filter方法将为数组中的每个元素调用传递的函数。然后，可以返回true以保留该元素，或返回false以过滤该元素。最终结果将以新数组的形式返回。
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原文链接：
https://stackoverflow.com/questions/52623315
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