blocks|key|4008207|text|这是一个单元测试，它可以做你想做的事情。我不得不稍微格式化一下你的输入字符串。您应该能够以最少的更改为您完成此工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4008208|import+org.junit.Test;

import+java.time.LocalDate;
import+java.time.LocalTime;
import+java.time.format.DateTimeFormatter;
import+java.util.ArrayList;
import+java.util.HashMap;
import+java.util.List;
import+java.util.Map;

/**
+*+@author+Dr.+Parameter
+*/
public+class+TimeParser+{

++++private+final+DateTimeFormatter+formatter+=+DateTimeFormatter.ofPattern("k:mm");

++++@Test
++++public+void+test(){

++++++++//+Test+input
++++++++String+times+=+"time1,+5:01,3:21,4:05,1:52,+time2,+2:11,6:35,2:00,5:00,+time3,+12:09,11:35,+9:02";

++++++++//+Set+up+Objects+used+to+collect
++++++++String+currentKey+=+"";
++++++++HashMap<String,+List<LocalTime>>+timeMap+=+new+HashMap();

++++++++//+Iterate+though+list
++++++++String[]+lineBreaks+=+times.split("\n");
++++++++for(String+line+:+lineBreaks){
++++++++++++String[]+csvBreaks+=+line.split(",");
++++++++++++for(String+csv+:+csvBreaks){

++++++++++++++++//try+to+parse+a+time+and+add+it+to+the+key+set,+add+a+new+key+if+there+is+a+failure
++++++++++++++++try+{
++++++++++++++++++++timeMap.get(currentKey).add(LocalTime.parse(csv.trim(),+formatter));
++++++++++++++++}+catch+(Exception+ex){
++++++++++++++++++++currentKey+=+csv;
++++++++++++++++++++timeMap.put(currentKey,+new+ArrayList<>());
++++++++++++++++}
++++++++++++}
++++++++}

++++++++//Print+result:
++++++++for(Map.Entry<String,+List<LocalTime>>+entry+:+timeMap.entrySet()){
++++++++++++System.out.println("times+for+key:+"+%2B+entry.getKey());
++++++++++++for(LocalTime+time+:+entry.getValue()){
++++++++++++++++System.out.println("\t"+%2B+time);
++++++++++++}
++++++++}
++++}
}|code-block|syntax|javascript|4008209|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here's a unit test which does what you want. I had to format your input string a little bit. You should be able to have this work for you with minimal changes. 

<pre><code>import org.junit.Test;

import java.time.LocalDate;
import java.time.LocalTime;
import java.time.format.DateTimeFormatter;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

/**
 * @author Dr. Parameter
 */
public class TimeParser {

 private final DateTimeFormatter formatter = DateTimeFormatter.ofPattern("k:mm");

 @Test
 public void test(){

 // Test input
 String times = "time1, 5:01,3:21,4:05,1:52, time2, 2:11,6:35,2:00,5:00, time3, 12:09,11:35, 9:02";

 // Set up Objects used to collect
 String currentKey = "";
 HashMap&lt;String, List&lt;LocalTime&gt;&gt; timeMap = new HashMap();

 // Iterate though list
 String[] lineBreaks = times.split("\n");
 for(String line : lineBreaks){
 String[] csvBreaks = line.split(",");
 for(String csv : csvBreaks){

 //try to parse a time and add it to the key set, add a new key if there is a failure
 try {
 timeMap.get(currentKey).add(LocalTime.parse(csv.trim(), formatter));
 } catch (Exception ex){
 currentKey = csv;
 timeMap.put(currentKey, new ArrayList&lt;&gt;());
 }
 }
 }

 //Print result:
 for(Map.Entry&lt;String, List&lt;LocalTime&gt;&gt; entry : timeMap.entrySet()){
 System.out.println("times for key: " + entry.getKey());
 for(LocalTime time : entry.getValue()){
 System.out.println("\t" + time);
 }
 }
 }
}
</code></pre>

blocks|key|4008244|text|下面是另一种更简单的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4008245|public+class+ReadTimes+{
++++private+Map<String,+List<String>>+timeLists+=+new+HashMap();
++++public+void+read_file()+{
++++++++try+{
++++++++++++Scanner+times+=+new+Scanner(new+File("times.csv"));
++++++++++++read_file(times);
++++++++}+catch+(Exception+e)+{
++++++++++++System.out.printf("Could+not+find+file\n");
++++++++}
++++}
++++public+void+read_file(Scanner+times)+{
++++++++String+label=null;
++++++++while+(times.hasNextLine())+{
++++++++++++String+time[]+=+times.nextLine().trim().split("[,+]%2B");
++++++++++++for+(String+timeString+:+time)+{
++++++++++++++++if+(timeString.startsWith("time"))+{
++++++++++++++++++++label+=+timeString;
++++++++++++++++++++timeLists.put(label,+new+ArrayList());
++++++++++++++++}+else+if+(label+!=+null)+{
++++++++++++++++++++timeLists.get(label).add(timeString);
++++++++++++++++}
++++++++++++}
++++++++}
++++++++//+dump+the+map+of+arraylists+for+demonstration+purposes...
++++++++for+(Entry<String,List<String>>+timeEntry+:+timeLists.entrySet())+{
++++++++++++System.out.println(timeEntry);
++++++++}
++++}

++++public+static+void+main(String[]+args)+{
++++++++ReadTimes+rt+=+new+ReadTimes();
++++++++rt.read_file();
++++}
}|code-block|syntax|javascript|4008246|给定问题中显示的输入数据，将生成以下输出：|4008247|time1=[5:01,+3:21,+4:05,+1:52]
time2=[2:11,+6:35,+2:00,+5:00]
time3=[12:09,+11:35,+9:02]|4008248|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Here's another simpler approach:

<pre><code>public class ReadTimes {
 private Map&lt;String, List&lt;String&gt;&gt; timeLists = new HashMap();
 public void read_file() {
 try {
 Scanner times = new Scanner(new File("times.csv"));
 read_file(times);
 } catch (Exception e) {
 System.out.printf("Could not find file\n");
 }
 }
 public void read_file(Scanner times) {
 String label=null;
 while (times.hasNextLine()) {
 String time[] = times.nextLine().trim().split("[, ]+");
 for (String timeString : time) {
 if (timeString.startsWith("time")) {
 label = timeString;
 timeLists.put(label, new ArrayList());
 } else if (label != null) {
 timeLists.get(label).add(timeString);
 }
 }
 }
 // dump the map of arraylists for demonstration purposes...
 for (Entry&lt;String,List&lt;String&gt;&gt; timeEntry : timeLists.entrySet()) {
 System.out.println(timeEntry);
 }
 }

 public static void main(String[] args) {
 ReadTimes rt = new ReadTimes();
 rt.read_file();
 }
}
</code></pre>

Given the input data shown in your question, the following output is produced:

<pre><code>time1=[5:01, 3:21, 4:05, 1:52]
time2=[2:11, 6:35, 2:00, 5:00]
time3=[12:09, 11:35, 9:02]
</code></pre>

blocks|key|4008300|text|因为你确定你想要3个字符串数组，下面的代码以"time“作为分隔符拆分初始字符串，删除开头的"1,+"，"2,+"，"3,+"，修剪并删除结尾的,，最后在删除所有空格后，以,作为分隔符拆分每一项，生成3个字符串数组。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4008301|++++String+times+=+"time1,+5:01,3:21,4:05,1:52,+time2,+2:11,6:35,2:00,5:00,+time3,+12:09,11:35,+9:02";

++++String[]+splitted+=+times.split("time");

++++//+exclude+0th+item+which+is+""
++++for+(int+i+=+1;+i+<+splitted.length;+i%2B%2B)+{
++++++++splitted[i]+=+splitted[i].trim();

++++++++int+index+=+splitted[i].indexOf("+");

++++++++if+(splitted[i].endsWith(","))
++++++++++++splitted[i]+=+splitted[i].substring(index+%2B+1,+splitted[i].length()+-+1);
++++++++else
++++++++++++splitted[i]+=+splitted[i].substring(index+%2B+1);

++++++++splitted[i]+=+splitted[i].replaceAll("+",+"");
++++}

++++try+{++//+just+in+case
++++++++String+time1[]+=+splitted[1].split(",");
++++++++System.out.println(Arrays.toString(time1));
++++++++String+time2[]+=+splitted[2].split(",");
++++++++System.out.println(Arrays.toString(time2));
++++++++String+time3[]+=+splitted[3].split(",");
++++++++System.out.println(Arrays.toString(time3));
++++}+catch+(Exception+e)+{
++++++++e.printStackTrace();
++++}|code-block|syntax|javascript|4008302|打印3个字符串数组：|4008303|[5:01,+3:21,+4:05,+1:52]
[2:11,+6:35,+2:00,+5:00]
[12:09,+11:35,+9:02]|4008304|entityMap^0|1A|5|1G|5|1M|5|20|1|2E|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|P|$]]

Since you are sure that you want exactly 3 string arrays, the below code splits the initial string with "time" as a delimeter, removes <code>"1, "</code>, <code>"2, "</code>, <code>"3, "</code> at the beginning, trims and removes <code>,</code> at the end and finally after removing all spaces splits every item with <code>,</code> as a delimeter producing 3 string arrays.

<pre><code> String times = "time1, 5:01,3:21,4:05,1:52, time2, 2:11,6:35,2:00,5:00, time3, 12:09,11:35, 9:02";

 String[] splitted = times.split("time");

 // exclude 0th item which is ""
 for (int i = 1; i &lt; splitted.length; i++) {
 splitted[i] = splitted[i].trim();

 int index = splitted[i].indexOf(" ");

 if (splitted[i].endsWith(","))
 splitted[i] = splitted[i].substring(index + 1, splitted[i].length() - 1);
 else
 splitted[i] = splitted[i].substring(index + 1);

 splitted[i] = splitted[i].replaceAll(" ", "");
 }

 try { // just in case
 String time1[] = splitted[1].split(",");
 System.out.println(Arrays.toString(time1));
 String time2[] = splitted[2].split(",");
 System.out.println(Arrays.toString(time2));
 String time3[] = splitted[3].split(",");
 System.out.println(Arrays.toString(time3));
 } catch (Exception e) {
 e.printStackTrace();
 }
</code></pre>

Prints the 3 string arrays:

<pre><code>[5:01, 3:21, 4:05, 1:52]
[2:11, 6:35, 2:00, 5:00]
[12:09, 11:35, 9:02]
</code></pre>

I have a list with a bunch of times in a file. My goal is to put all the times in their own string array called <code>time1</code>, <code>time2</code> and <code>time3</code>. The file looks like this:

<pre><code>time1, 5:01,3:21,4:05,1:52 time2, 2:11,6:35,2:00,5:00 time3, 12:09, 
11:35, 9:02
</code></pre>

I have tried splitting each line that I read in then turning it into tokens, separated by a comma. However, that does not seem to be a valid solution currently as the first element always begins with space, and the last element does not have a comma. I was wondering if anyone knew a workaround to this problem. 

Here's the code I have come up with so far:

<pre><code>public void read_file(){
try{
 times = new Scanner(new File("times.csv"));
 read_file();
}
catch(Exception e){
 System.out.printf("Could not find file\n");
} 
}
public void read_file(){

while(times.hasNextLine()){
 i++;
 String a = times.nextLine();
 String time[] = a.split(",");
 //would only add first 4 elements
 if(i &lt; 4){
 timeList1.add(time[i])
 }
}
}
</code></pre>

The problem here is that I do not know how to check for how many elements I have to keep going because the amount of times in the list is unpredictable. The only thing that stays the same is that there will always be 3 time lists called <code>time1</code>, <code>time2</code> and <code>time3</code>.

Read times from a File separated by comma and title in Java

我在一个文件里有一个列表，里面有很多次。我的目标是将所有的时间都放在它们自己的字符串数组中，分别称为time1、time2和time3。该文件如下所示：time1, 5:01,3:21,4:05,1:52 time2, 2:11,6:35,2:00,5:00 time3, 12:09, 11:35, 9:02我试着把读...

问在Java中从逗号和标题分隔的文件中读取时间
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