根据关键结果以优雅的方式抓取中间的x个结果
根据关键结果以优雅的方式抓取中间的x个结果
提问于 2018-06-09 05:47:34
我有一套产品。根据页面的状态，我显示一个产品，然后最多显示4个其他产品。产品的结果集可以是大于5个产品的任意大小。我想一直展示5种产品。如果可用，我想显示下面的2个产品(在结果集中)和上面的2个产品。
示例：
如果有10个结果，关键乘积是5。我想显示3,4,5,6,7。
如果有10个结果，关键乘积是9，我想显示6,7,8,9,10。
如果有10个结果，关键乘积是1。我想显示1,2,3,4,5。
现在我正在使用min()和max()和一些“IF”来解决这个问题，这需要大量的代码，当有一个优雅的解决方案时，我就是找不到它！下面是数组结果集示例
$similar_products = array(
array(
"id" => 1,
"title" => "Product One"
),
array(
"id" => 2,
"title" => "Product Two"
),
array(
"id" => 3,
"title" => "Product Three"
),
array(
"id" => 4,
"title" => "Product Four"
),
array(
"id" => 5,
"title" => "Product Five"
),
array(
"id" => 6,
"title" => "Product Six"
),
array(
"id" => 7,
"title" => "Product Seven"
),
array(
"id" => 8,
"title" => "Product Eight"
),
array(
"id" => 9,
"title" => "Product Nine"
),
array(
"id" => 10,
"title" => "Product Ten"
)
);
$i = 8; //change this value to test different key product array positions
$arrOut = array();
$floor = 0;
if($i <= 1) { //the key product is either in the first or second position in the array
$floor = 0;
$arrOut[] = $similar_products[0];
$arrOut[] = $similar_products[1];
$arrOut[] = $similar_products[2];
$arrOut[] = $similar_products[3];
$arrOut[] = $similar_products[4];
} elseif((count($similar_products)-1)-$i <= 1) { //the key product is either in the last or second to last in the array
$floor = count($similar_products)-5;
$arrOut[] = $similar_products[count($similar_products)-5];
$arrOut[] = $similar_products[count($similar_products)-4];
$arrOut[] = $similar_products[count($similar_products)-3];
$arrOut[] = $similar_products[count($similar_products)-2];
$arrOut[] = $similar_products[count($similar_products)-1];
} else { //otherwise, just grab two above and two below
$floor = $i-2;
$arrOut[] = $similar_products[$i-2];
$arrOut[] = $similar_products[$i-1];
$arrOut[] = $similar_products[$i];
$arrOut[] = $similar_products[$i+1];
$arrOut[] = $similar_products[$i+2];
}
$x = $floor; //set x, our counter, to the floor (floor = the very first output postion)
foreach($arrOut as $ao) {
if($x == $i) { //current key product
echo "<strong>" . $ao['id'] . ":" . $ao['title'] . "</strong><hr/>";
} else { //other NON key products
echo $ao['id'] . ":" . $ao['title'] . "<hr/>";
}
$x++;
}回答 2
Stack Overflow用户
回答已采纳
发布于 2018-06-12 03:02:05
如果你愿意，你可以删除变量config，把它压缩一下，使它成为一行;-)我不擅长这种东西，所以可能有更有效和/或更短的选择。
// Set array index, starts with 0
// If you need to find with specific ID, just find the index by the ID
$primaryIndex = 4;// change this number to test
// How many extra items to show
// Must be divisible by 2
$extraToShow = 4;
// Find total items available - 1 to work with array indexes
$maxIndex = count($similar_products) - 1;
// Find the slice start
$low = min($maxIndex - $extraToShow, max(0, $primaryIndex - 1 - $extraToShow / 2));
// Slice to needed
$items = array_slice($similar_products, $low, $extraToShow + 1);
var_dump($items);Stack Overflow用户
发布于 2018-06-09 06:30:56
<?php
// example code
$productKey = 7;
$resultsShown = 5;
$totalResults = 10;//num_rows()?
$limit = floor($resultsShown/2);
$min = $limit;
$max = $totalResults - $limit;
if($productKey<=$min){
for($i = 1;$i<=$resultsShown; $i++){
//Display result
echo $i;
}
}
else if($productKey>$max){
for( $i = $totalResults - $resultsShown+1; $i <=$totalResults;$i++){
//Display result
echo $i;
}}
else{
for( $i = $productKey - $limit; $i<=$productKey + $limit; $i++){
//Display result
echo $i;
}
}我还没有机会测试，因为我在移动设备上，但我能想到的最简单的方法是解决问题，同时让你有机会在未来改变这些固定的限制，不优雅，但看不到你现在有什么可比较的！
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原文链接：
https://stackoverflow.com/questions/50768792
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