blocks|key|3995716|text|我不确定这在enumerate环境中是否可行。一种简单的替代方法是使用tabular环境。在下面的示例中，等式的左侧和右侧包含在两个单独的列中，并在它们之间显示一个=。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3995717|\documentclass[12pt]{article}

\begin{document}
\begin{tabular}{l+r@{$=$}l}
++++Commutative+&+$a%2Bb$+&+$b%2Ba$+\\
++++Associative+&+$a%2B(b%2Bc)$+&+$(a%2Bb)%2Bc$+\\
++++Distributive+&+$a(b%2Bc)$+&+$ab%2Bac$+\\
\end{tabular}
\end{document}|code-block|syntax|javascript|3995718|​|3995719|📷|atomic|3995720|3995721|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/3eb83c5a818c2afb4d251dfa72131bde.png|imageAlt^0|6|9|Z|7|2A|1|0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]|$9|12|A|13|B|C]|$9|14|A|15|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|17|8|@]|D|@]|E|$]]|$1|M|3|N|5|O|7|18|8|@]|D|@$9|19|A|1A|1|1B]]|E|$]]|$1|P|3|L|5|6|7|1C|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X|Y|-4]]]]

I'm unsure if this is possible inside the <code>enumerate</code> environment. An easy alternative is to use a <code>tabular</code> environment instead. In the example below the left and right sides of the equation are contained in two separate columns, with an <code>=</code> appearing between them.

<pre><code>\documentclass[12pt]{article}

\begin{document}
\begin{tabular}{l r@{$=$}l}
 Commutative &amp; $a+b$ &amp; $b+a$ \\
 Associative &amp; $a+(b+c)$ &amp; $(a+b)+c$ \\
 Distributive &amp; $a(b+c)$ &amp; $ab+ac$ \\
\end{tabular}
\end{document}
</code></pre>

<a href="https://i.stack.imgur.com/ti44M.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/ti44M.png" alt="enter image description here"></a>

blocks|key|3995812|text|使用\eqmakebox[<tag>][<align>]+(来自eqparbox)，您可以将同一<tag>下的所有元素放在一个最大宽度的框中，并根据需要单独放置<align>段。下面我使用\eqmakebox[LHS][r]来确保所有标记为LHS的元素都是r对齐的。结果是围绕=对齐。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3995813|​|3995814|📷|atomic|3995815|3995816|\documentclass{article}

\usepackage{eqparbox}

\begin{document}

\begin{enumerate}
++\item[Commutative]++$++++++a+%2B+b+=+b+%2B+a++++++$
++\item[Associative]++$a+%2B+(b+%2B+c)+=+(a+%2B+b)+%2B+c$
++\item[Distributive]+$+++a(b+%2B+c)+=+ab+%2B+ac++++$
\end{enumerate}

\begin{enumerate}
++\item[Commutative]++$++++++\eqmakebox[LHS][r]{$a+%2B+b$}+=+b+%2B+a++++++$
++\item[Associative]++$\eqmakebox[LHS][r]{$a+%2B+(b+%2B+c)$}+=+(a+%2B+b)+%2B+c$
++\item[Distributive]+$+++\eqmakebox[LHS][r]{$a(b+%2B+c)$}+=+ab+%2B+ac++++$
\end{enumerate}

\end{document}|code-block|syntax|javascript|3995817|或者，您可以自己测量最宽的元素：|3995818|\newlength{\widestelement}
\settowidth{\widestelement}{$a+%2B+(b+%2B+c)$}|3995819|然后使用|3995820|\begin{enumerate}
++\item[Commutative]++$++++++\makebox[\widestelement][r]{$a+%2B+b$}+=+b+%2B+a++++++$
++\item[Associative]++$\makebox[\widestelement][r]{$a+%2B+(b+%2B+c)$}+=+(a+%2B+b)+%2B+c$
++\item[Distributive]+$+++\makebox[\widestelement][r]{$a(b+%2B+c)$}+=+ab+%2B+ac++++$
\end{enumerate}|3995821|entityMap|0|LINK|mutability|MUTABLE|url|//ctan.org/pkg/eqparbox|1|IMAGE|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/2a66abe708af4e9afcdab263e86241c0.png|imageAlt^0|2|Q|W|8|1C|5|28|7|2M|I|3C|3|3K|1|3U|1|W|8|0|0|0|0|1|1|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1C|8|@$9|1D|A|1E|B|C]|$9|1F|A|1G|B|C]|$9|1H|A|1I|B|C]|$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]|$9|1N|A|1O|B|C]|$9|1P|A|1Q|B|C]|$9|1R|A|1S|B|C]]|D|@$9|1T|A|1U|1|1V]]|E|$]]|$1|F|3|G|5|6|7|1W|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1X|8|@]|D|@$9|1Y|A|1Z|1|20]]|E|$]]|$1|K|3|G|5|6|7|21|8|@]|D|@]|E|$]]|$1|L|3|M|5|N|7|22|8|@]|D|@]|E|$O|P]]|$1|Q|3|R|5|6|7|23|8|@]|D|@]|E|$]]|$1|S|3|T|5|N|7|24|8|@]|D|@]|E|$O|P]]|$1|U|3|V|5|6|7|25|8|@]|D|@]|E|$]]|$1|W|3|X|5|N|7|26|8|@]|D|@]|E|$O|P]]|$1|Y|3|-4|5|6|7|27|8|@]|D|@]|E|$]]]|Z|$10|$5|11|12|13|E|$14|15]]|16|$5|17|12|18|E|$19|1A|1B|-4]]]]

Using <code>\eqmakebox[&lt;tag&gt;][&lt;align&gt;]</code> (from <a href="//ctan.org/pkg/eqparbox" rel="nofollow noreferrer"><code>eqparbox</code></a>) you can have all elements under the same <code>&lt;tag&gt;</code> be placed in a box of maximum width, together with individual <code>&lt;align&gt;</code>ment as needed. Below I has <code>\eqmakebox[LHS][r]</code> to ensure all elements tagged <code>LHS</code> is <code>r</code>ight-aligned. The result is alignment around the <code>=</code>.

<a href="https://i.stack.imgur.com/uwOOJ.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/uwOOJ.png" alt="enter image description here"></a>

<pre><code>\documentclass{article}

\usepackage{eqparbox}

\begin{document}

\begin{enumerate}
 \item[Commutative] $ a + b = b + a $
 \item[Associative] $a + (b + c) = (a + b) + c$
 \item[Distributive] $ a(b + c) = ab + ac $
\end{enumerate}

\begin{enumerate}
 \item[Commutative] $ \eqmakebox[LHS][r]{$a + b$} = b + a $
 \item[Associative] $\eqmakebox[LHS][r]{$a + (b + c)$} = (a + b) + c$
 \item[Distributive] $ \eqmakebox[LHS][r]{$a(b + c)$} = ab + ac $
\end{enumerate}

\end{document}
</code></pre>

Alternatively you can measure the widest element yourself:

<pre><code>\newlength{\widestelement}
\settowidth{\widestelement}{$a + (b + c)$}
</code></pre>

and then use

<pre><code>\begin{enumerate}
 \item[Commutative] $ \makebox[\widestelement][r]{$a + b$} = b + a $
 \item[Associative] $\makebox[\widestelement][r]{$a + (b + c)$} = (a + b) + c$
 \item[Distributive] $ \makebox[\widestelement][r]{$a(b + c)$} = ab + ac $
\end{enumerate}
</code></pre>

I am a beginner in latex.I have the following piece of latex code. The code is working fine but I want that all the equality operators of each equation should be aligned. How can it be done?

<pre><code>\begin{enumerate}
\item[Commutative] $a+b = b+a$
\item[Associative] $a+(b+c)=(a+b)+c$
\item[Distributive] $a(b+c)=ab+ac$
\end{enumerate}
</code></pre>

align latex equations

我是latex的初学者，我有下面这段latex代码。代码运行良好，但我希望每个等式的所有相等运算符都应该对齐。怎么做呢？\begin{enumerate}\item[Commutative] $a+b = b+a$\item[Associative] $a+(b+c)=(a+b)+c$\item[Distributiv...

问align latex方程
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