UIGestureRecognizer不向其他类发送操作
UIGestureRecognizer不向其他类发送操作
提问于 2018-06-10 02:05:16
我正在尝试从UIView类的UIGestureRecognizer向其父类的View Controller发送操作。
HomeViewController包含一个包含多个(5) OperationViews的视图。
OperationView扩展了UIView，如下所示：
class OperationView: UIView {
override func awakeFromNib() {
super.awakeFromNib()
// OperationView is on a view that has HomeViewController as it's controller in StoryBoard
let swipeGestureRecognizer = UISwipeGestureRecognizer(target: HomeViewController.self(), action: #selector(HomeViewController.operatorWasSwiped(_:)))
swipeGestureRecognizer.direction = .left
let tapGestureRecognizer = UITapGestureRecognizer(target: HomeViewController.self(), action: #selector(HomeViewController.operatorWasSwiped(_:)))
self.addGestureRecognizer(swipeGestureRecognizer)
self.addGestureRecognizer(tapGestureRecognizer)
}在HomeViewController中，我有一个应该由UIGestureRecognizers调用的函数：
@objc func operatorWasSwiped(_ sender : UIGestureRecognizer) {
if (sender.isKind(of: UITapGestureRecognizer.self)) { print("Tapped") }
else { print("Swiped") }
self.performSegue(withIdentifier: "segue1", sender: nil)
}但是，我没有得到任何东西。一点错误都没有。
我尝试使用HomeViewController上的IBOutlet将UIGestureRecognizer添加到每个OperationView中，如下所示：
view1.swipeGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view2.swipeGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view3.swipeGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view4.swipeGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view5.swipeGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view1.tapGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view2.tapGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view3.tapGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view4.tapGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view5.tapGestureRecognizer?.addTarget(self, action: #selector(operatorWasSwiped(_ :)))
view1.addGestureRecognizer(view1.swipeGestureRecognizer!)
view2.addGestureRecognizer(view2.swipeGestureRecognizer!)
view3.addGestureRecognizer(view3.swipeGestureRecognizer!)
view4.addGestureRecognizer(view4.swipeGestureRecognizer!)
view.addGestureRecognizer(view5.swipeGestureRecognizer!)
view1.addGestureRecognizer(view1.tapGestureRecognizer!)
view2.addGestureRecognizer(view2.tapGestureRecognizer!)
view3.addGestureRecognizer(view3.tapGestureRecognizer!)
view4.addGestureRecognizer(view4.tapGestureRecognizer!)
view5.addGestureRecognizer(view5.tapGestureRecognizer!)我在其中添加了：
var swipeGestureRecognizer: UISwipeGestureRecognizer?
var tapGestureRecognizer: UITapGestureRecognizer?为OperationView的变量创建类
这是可行的，但还远远谈不上优雅(想象一下，如果我不得不添加另一个view...kinda，这会使我之前的抽象失去意义)
知道是怎么回事吗？或者我错过了什么？
我使用的是Swift 4和Xcode 9
回答 1
Stack Overflow用户
回答已采纳
发布于 2018-06-10 03:12:39
您在方法中创建该手势，并且该手势可能仅在调用函数时位于该作用域中。所以从技术上讲，在你使用它之前它就消失了。因此，在方法之外创建该手势的实例可能会在视图存在的同时存在。如果这有意义的话。
更新:正如评论中指出的，我们确实需要父viewController的当前引用。
这样做怎么样？
class OperationView: UIView {
let swipeGestureRecognizer = UISwipeGestureRecognizer()
let tapGestureRecognizer = UITapGestureRecognizer()
override func awakeFromNib() {
super.awakeFromNib()
if let parentViewController = parentViewController {
swipeGestureRecognizer.addTarget(parentViewController, action: #selector(HomeViewController.operatorWasSwiped(_:)))
swipeGestureRecognizer.direction = .left
tapGestureRecognizer.addTarget(parentViewController, action: #selector(HomeViewController.operatorWasSwiped(_:)))
self.addGestureRecognizer(swipeGestureRecognizer)
self.addGestureRecognizer(tapGestureRecognizer)
}
}
}
extension UIView {
var parentViewController: UIViewController? {
var parentResponder: UIResponder? = self
while parentResponder != nil {
parentResponder = parentResponder!.next
if let viewController = parentResponder as? UIViewController {
return viewController
}
}
return nil
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50777148
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