数组中的Python Numba值
数组中的Python Numba值
提问于 2019-03-01 01:07:32
我正在尝试检查int8s的NumPy数组中是否有数字。我试过了，但不起作用。
from numba import njit
import numpy as np
@njit
def c(b):
return 9 in b
a = np.array((9, 10, 11), 'int8')
print(c(a))我得到的错误是
Invalid use of Function(<built-in function contains>) with argument(s) of type(s): (array(int8, 1d, C), Literal[int](9))
* parameterized
In definition 0:
All templates rejected with literals.
In definition 1:
All templates rejected without literals.
In definition 2:
All templates rejected with literals.
In definition 3:
All templates rejected without literals.
In definition 4:
All templates rejected with literals.
In definition 5:
All templates rejected without literals.
This error is usually caused by passing an argument of a type that is unsupported by the named function.
[1] During: typing of intrinsic-call at .\emptyList.py (6)我如何在保持性能的同时修复这个问题？将检查数组中的两个值，1和-1，长度为32项。它们不会排序。
回答 1
Stack Overflow用户
发布于 2021-04-20 19:03:56
这只是max9111的答案的一个微小的变化。稍短一点，并将要搜索的元素作为一个参数。一旦找到元素，它也会退出循环。
from numba import njit
@njit
def isin(val, arr):
for i in range(len(arr)):
if arr[i] == val:
return True
return False页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/54930852
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