添加列表的相邻元素
添加列表的相邻元素
提问于 2019-03-19 23:53:36
我需要在python中执行以下循环(在伪代码中，我正在学习python)
listOfNumbers = [1,2,3]
averagesOfNumbers = [0,0,0]
for i = 1 to 2
averagesOfNumbers [i] = (listOfNumbers [i] + listOfNumbers[i + 1]) / 2
end iaverageOfNumbers将看起来像1.5，2.5，0。
我如何在Python中做到这一点？
回答 5
Stack Overflow用户
发布于 2019-03-20 00:02:12
如果这是您要查找的内容，请查看代码：
List=[1,2,3]
avg=[0]*len(List)
for i in range(len(List)-1):
avg[i]=(List[i]+List[i+1])/2
print(avg)希望你拿到密码了。输出: 1.5,2.5,0
Stack Overflow用户
发布于 2019-03-20 00:03:28
这就是在Python中实现的方法：
listOfNumbers = [1,2,3]
averagesOfNumbers = [0,0,0]
# In Python, we start counting from 0.
# So, 2 means 0,1 and in total, that
# is 2 numbers.
for i in range(2):
averagesOfNumbers [i] = (listOfNumbers [i] + listOfNumbers[i + 1])/2
print(averagesOfNumbers)Stack Overflow用户
发布于 2019-03-20 00:01:10
我猜你想要做以下事情：
listOfNumbers = [1,2,3]
averagesOfNumbers = [0,0,0]
for i in range(len(listOfNumbers)-1):
averagesOfNumbers[i] = (listOfNumbers[i] + listOfNumbers[i+1]) / 2页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/55245100
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