Python:展平内部列表时保留外部列表
Python:展平内部列表时保留外部列表
提问于 2019-03-21 07:40:58
我有一个列表列表，看起来像这样。我想删除内部列表，保留外部列表。我不想把整个事情变成一个巨大的元素列表。
['100', ['ADDRESS', 'START', '100']]
['. TESTS PC FORWARD ADDRESSING']
['. TESTS BASE ADDRESSING']
['. TESTS PC BACKWARD ADDRESSING']
['100', ['NOW', '+LDB', '#BEGIN', 'load base register']]
['104', ['XXX', 'BASE', 'BEGIN', 'tell assembler']]
['104', ['YYY', 'LDA', 'BE', 'A <- (m..m+2)']]
['107', ['EN', 'RESW', '4']]
['113', ['BE', 'WORD', '2']]
['116', ['BEGIN', 'RESW', '1']]
['119', ['JUNK', 'RESW', '2200']]
['1ae1', ['THERE', 'RESW', '1']]
['1ae4', ['ZZZ', 'LDA', 'JUNK']]
['1ae7', ['MMM', 'STA', 'THERE']]
['1aea', ['', 'END', 'NOW']]我想要的是：
['100', 'ADDRESS', 'START', '100']
['. TESTS PC FORWARD ADDRESSING']
['. TESTS BASE ADDRESSING']
['. TESTS PC BACKWARD ADDRESSING']
['100', 'NOW', '+LDB', '#BEGIN', 'load base register']
['104', 'XXX', 'BASE', 'BEGIN', 'tell assembler']
['104', 'YYY', 'LDA', 'BE', 'A <- (m..m+2)']
['107', 'EN', 'RESW', '4']
['113', 'BE', 'WORD', '2']
['116', 'BEGIN', 'RESW', '1']
['119', 'JUNK', 'RESW', '2200']
['1ae1', 'THERE', 'RESW', '1']
['1ae4', 'ZZZ', 'LDA', 'JUNK']
['1ae7', 'MMM', 'STA', 'THERE']
['1aea', '', 'END', 'NOW']我的代码：newlist = [str(sublist[0]) + str(sublist[1:]) for sublist in final_file]
这段代码给出了这个输出，并不完全是我想要的：
100[['ADDRESS', 'START', '100']]
. TESTS PC FORWARD ADDRESSING[]
. TESTS BASE ADDRESSING[]
. TESTS PC BACKWARD ADDRESSING[]
100[['NOW', '+LDB', '#BEGIN', 'load base register']]
104[['XXX', 'BASE', 'BEGIN', 'tell assembler']]
104[['YYY', 'LDA', 'BE', 'A <- (m..m+2)']]
107[['EN', 'RESW', '4']]
113[['BE', 'WORD', '2']]
116[['BEGIN', 'RESW', '1']]
119[['JUNK', 'RESW', '2200']]
1ae1[['THERE', 'RESW', '1']]
1ae4[['ZZZ', 'LDA', 'JUNK']]
1ae7[['MMM', 'STA', 'THERE']]
1aea[['', 'END', 'NOW']]回答 3
Stack Overflow用户
发布于 2019-03-21 07:58:35
更新：
newlist = [[x[0]] + x[1] if len(x) >= 2 else x for x in final_file]这是可行的
Stack Overflow用户
发布于 2019-03-21 09:07:38
如果有问题的列表是；
a = [
['100', ['ADDRESS', 'START', '100']],
['. TESTS PC FORWARD ADDRESSING'],
['. TESTS BASE ADDRESSING'],
['. TESTS PC BACKWARD ADDRESSING'],
['100', ['NOW', '+LDB', '#BEGIN', 'load base register']],
['104', ['XXX', 'BASE', 'BEGIN', 'tell assembler']],
['104', ['YYY', 'LDA', 'BE', 'A <- (m..m+2)']],
['107', ['EN', 'RESW', '4']],
['113', ['BE', 'WORD', '2']],
['116', ['BEGIN', 'RESW', '1']],
['119', ['JUNK', 'RESW', '2200']],
['1ae1', ['THERE', 'RESW', '1']],
['1ae4', ['ZZZ', 'LDA', 'JUNK']],
['1ae7', ['MMM', 'STA', 'THERE']],
['1aea', ['', 'END', 'NOW']],
]一句话：
[sum([sub if isinstance(sub, list) else [sub] for sub in x], []) for x in a]如果你只想把它用于单独的列表，那么去掉外部循环；
sum([sub if isinstance(sub, list) else [sub] for sub in a[0]], [])Stack Overflow用户
发布于 2019-03-21 08:23:29
newlist = ['104', ['YYY', 'LDA', 'BE', 'A <- (m..m+2)']]
final = []
for n in newlist:
if type(n) == list:
for i in n:
final.append(i)
else:
final.append(n)
print(final)您可以检查元素的类型是否为list，如果是，则使用另一个循环将其解包并将其附加到新列表中。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/55271708
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