问用指定时间点截图接口，签名失败？

以下是代码，我在浏览器访问返回的url，返回 {"code":4100,"message":"\u8eab\u4efd\u8ba4\u8bc1\u5931\u8d25\uff0c\u7528\u6237\u8eab\u4efd\u9a8c\u8bc1\u5931\u8d25","codeDesc":"AuthFailure"}

请求帮助！！！！

@RequestMapping("/mediaProcess")

@ResponseBody

public String mediaProcess(@RequestParam String fileId)throws Exception{

TreeMap<String, Object> params =newTreeMap<String, Object>();// TreeMap可以自动排序 params.put("Action","CreateSnapshotByTimeOffset");// 公共参数 params.put("Nonce",newRandom().nextInt(java.lang.Integer.MAX_VALUE));// 公共参数

params.put("Timestamp", System.currentTimeMillis()/1000);// 公共参数

params.put("Version","2018-07-17");// 公共参数

params.put("Region","ap-beijing");// 公共参数

params.put("SecretId", FrontendPropertyConfigurer.getValue("showSecretId"));// 公共参数

params.put("definition",10);

params.put("FileId",fileId);

params.put("timeOffset.0",1);

String sign =sign(getStringToSign(params), FrontendPropertyConfigurer.getValue("showSecretKey"),"HmacSHA1"); params.put("Signature", sign);// 公共参数

String url =getUrl(params);

return url;

}

privatefinalstatic String CHARSET ="UTF-8";

publicstatic String sign(String s, String key, String method)throws Exception {

Mac mac = Mac.getInstance(method);

SecretKeySpec secretKeySpec =newSecretKeySpec(key.getBytes(CHARSET),

mac.getAlgorithm());

mac.init(secretKeySpec);

byte[] hash = mac.doFinal(s.getBytes(CHARSET));

return DatatypeConverter.printBase64Binary(hash);

}

publicstatic String getStringToSign(TreeMap<String, Object> params){

StringBuilder s2s =newStringBuilder("GETcvm.tencentcloudapi.com/?");

for(String k : params.keySet()){

s2s.append(k).append("=").append(params.get(k).toString()).append("&");

}

return s2s.toString().substring(0, s2s.length()-1);

}

publicstatic String getUrl(TreeMap<String, Object> params)throws UnsupportedEncodingException {

StringBuilder url =newStringBuilder("https://vod.api.qcloud.com/v2/index.php?");

for(String k : params.keySet()){

url.append(k).append("=").append(URLEncoder.encode(params.get(k).toString(), CHARSET)).append("&");

}

return url.toString().substring(0, url.length()-1);

}