C#treeView是一个代码,用于将子节点安排为其父节点的最后一个子节点

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我正在使用treeView在表单上的treeView中显示序列目录及其子目录和文件,我使用以下方法加载树视图

在表单加载:

        treeView1.Nodes.Clear();
        toolTip1.ShowAlways = true;
        LoadDirectory("C:\\Windows\\System32\\" + inventedName );  

和以下3种方法来加载目录和子目录和文件

    public void LoadDirectory(string Dir)
    {

        DirectoryInfo di = new DirectoryInfo(Dir);

        TreeNode tds = treeView1.Nodes.Add(di.Name);

        tds.Tag = di.FullName;
        //tds.StateImageIndex = 0;
        tds.ImageIndex = 0;
        tds.StateImageIndex = 0;
        tds.SelectedImageIndex = 0;
        LoadFiles(Dir, tds);
        LoadSubDirectories(Dir, tds);
    }

    private void LoadSubDirectories(string dir, TreeNode td)
    {

        string[] subdirectoryEntries = Directory.GetDirectories(dir);          

        // Loop through them to see if they have any other subdirectories  
        foreach (string subdirectory in subdirectoryEntries)
        {

            DirectoryInfo di = new DirectoryInfo(subdirectory);
            TreeNode tds = td.Nodes.Add(di.Name);
            renameNodes(tds);    
            //tds.StateImageIndex = 0;
            tds.Tag = di.FullName;
            tds.ImageIndex = 0;
            tds.StateImageIndex = 0;
            tds.SelectedImageIndex = 0;
            LoadFiles(subdirectory, tds);
            LoadSubDirectories(subdirectory, tds);

        }
    }

    private void LoadFiles(string dir, TreeNode td)
    {
        string[] Files = Directory.GetFiles(dir, "*.pdf");

        // Loop through them to see files  
        foreach (string file in Files)
        {
            FileInfo fi = new FileInfo(file);
            TreeNode tds = td.Nodes.Add(fi.Name);
            tds.Tag = fi.FullName;
            tds.ImageIndex = 1;
            tds.StateImageIndex = 1;
            tds.SelectedImageIndex = 1;

        }
    }

我的问题是子目录(文件夹)有特定的名称,我不能改变它,例如:

> root 
    > parent 
          > 1.0 xxx
          > 1.10 xxx
          > 1.2 xxx
          > 1.3 xxx 
          > 1.4 xxx
          > 1.5 xxx
          > 1.6 xxx
          > 1.7 xxx
          > 1.8 xxx
          > 1.9 xxx

但我需要它像那样

> root 
    > parent 
         > 1.0 xxx
         > 1.2 xxx
         > 1.3 xxx 
         > 1.4 xxx
         > 1.5 xxx
         > 1.6 xxx
         > 1.7 xxx
         > 1.8 xxx
         > 1.9 xxx
         > 1.10 xxx 

(1.10 xxx)必须在(1.9 xxx)子节点之后,并且我告诉我无法重命名将错误的文件夹是否有任何方式将其发送为最后一个子节点

谢谢你的帮助

提问于
用户回答回答于

使用IEquable做了一个非常类似的解决方案。在下面的代码中对文件名进行了排序以获得正确的解决方案

   public class Test
    {
        private void LoadFiles(string dir, TreeNode td)
        {
            string[] Files = Directory.GetFiles(dir, "*.pdf");
            Files = Files.Select(x => new MySort(x)).OrderBy(x => x).Select(x => x.filename).ToArray();

            // Loop through them to see files  
            foreach (string file in Files)
            {
                FileInfo fi = new FileInfo(file);
                TreeNode tds = td.Nodes.Add(fi.Name);
                tds.Tag = fi.FullName;
                tds.ImageIndex = 1;
                tds.StateImageIndex = 1;
                tds.SelectedImageIndex = 1;

            }
        }
    }
    public class MySort : IComparable
    {
        private string[] splitvalues { get; set; }
        public string filename { get; set; }

        public MySort(string filename)
        {
            this.filename = filename;
            splitvalues = filename.Split(new char[] { '.', ' ' }, StringSplitOptions.RemoveEmptyEntries).ToArray();

        }
        public int CompareTo(object other)
        {
            MySort otherMySort = (MySort)other;
            int min = Math.Min(this.splitvalues.Length, otherMySort.splitvalues.Length);

            for (int i = 0; i < min; i++)
            {
                string a = this.splitvalues[i];
                string b = otherMySort.splitvalues[i];

                if (a != b)
                {

                    int numberA = 0;
                    int numberB = 0;

                    if (int.TryParse(a, out numberA))
                    {
                        if (int.TryParse(b, out numberB))
                        {
                            int z = numberA.CompareTo(numberB);
                            //a & b are numbers
                            return numberA.CompareTo(numberB);
                        }
                        else
                        {
                            //a number b string
                            return -1;
                        }

                    }
                    else
                    {
                        if (int.TryParse(b, out numberB))
                        {
                            //a string b number
                            return 1;
                        }
                        else
                        {
                            // a string b string
                            return a.CompareTo(b);
                        }
                    }
                }
            }
            return splitvalues.Length.CompareTo(otherMySort.splitvalues.Length);

        }
    }

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