如何忽略delete关键字？
如何忽略delete关键字？
提问于 2019-05-15 03:25:46
我正在尝试创建一个包含命令别名和名称的数组，但是当存在带有delete的名称时，它会将最终数组中的值设为0
const commands = collection.reduce((all, command) => [...all, command.name, ...(command.aliases
? command.aliases.keys()
: [])], []);如何忽略delete关键字以在最终输出中获得单词delete而不是0？
一些示例输出
Collection [Map] {
'purge' => { name: 'purge',
description: 'Delete multiple messages at a time (up to 99).',
category: 'Admin',
usage: '<amount>',
examples: [ '5', '99' ],
aliases: [ 'delete' ],
args: true,
guildOnly: true,
execute: [Function: execute],
default:
{ name: 'purge',
description: 'Delete multiple messages at a time (up to 99).',
category: 'Admin',
usage: '<amount>',
examples: [Array],
aliases: [Array],
args: true,
guildOnly: true,
execute: [Function: execute] } },
'setjoin' => { name: 'setjoin',
description:
'Sets a message which will be sent when a new user joins the server.',
category: 'Admin',
usage: '<message>',
examples:
[ 'Welcome to the server {{member}}',
'User {{tag}} joined the server' ],
args: true,
guildOnly: true,
execute: [Function: execute],
default:
{ name: 'setjoin',
description:
'Sets a message which will be sent when a new user joins the server.',
category: 'Admin',
usage: '<message>',
examples: [Array],
args: true,
guildOnly: true,
execute: [Function: execute] } },回答 1
Stack Overflow用户
回答已采纳
发布于 2019-05-15 03:34:29
command.aliases是一个数组。对于purge命令，该阵列有一个键(0)和一个值('delete')。所以当你使用command.aliases.keys( )时，你得到的是数组的索引，而不是值。
只需使用数组本身(command.aliases)即可：
const commands = collection.reduce((all, command) => [...all, command.name, ...(command.aliases
? command.aliases
: [])], []);注意:这与关键字'delete'无关。对于任何别名，您都会得到相同的行为。
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原文链接：
https://stackoverflow.com/questions/56137302
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