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如何使用loadash/javascript嵌套多个groupby
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Stack Overflow用户
提问于 2019-05-19 10:12:47
回答 2查看 101关注 0票数 2

对任何能帮助我的人都要提前表示感谢。我正尝试在React Native中使用SectionList显示数据。我已经写了下面的代码来显示我想要实现的东西。常规的javascript解决方案将会起作用。我希望数据首先按日期分组在一起,在该日期内,我需要它们按位置分组。

重要的是它有一个标题和数据键,我有这种格式的数据:

代码语言:javascript
复制
[ { game_id: 1171,
    date: '2018-11-17',
    location: 'Plaza'
   },
  { game_id: 1189,
    date: '2018-11-17',
    location: 'Field - Kickball'
   },
   { game_id: 1489,
    date: '2018-11-16',
    location: 'Field - Kickball'
   },
   { game_id: 1488,
    date: '2018-11-16',
    location: 'Field - Soccer'
   }
]

我需要输出来显示:

代码语言:javascript
复制
data = [{
    title: "2018-11-17",
    data: [{
            title: "Field - Kickball",
            data: [{
                game_id: 1189,
                date: '2018-11-17',
                location: 'Field - Kickball'
            }]
        },
        {
            title: "Plaza",
            data: [{
                game_id: 1171,
                date: '2018-11-17',
                location: 'Plaza'
            }]
        }
    ]
    },
    {
        title: "2018-11-16",
        data: [{
                title: "Field - Kickball",
                data: [{
                    game_id: 1489,
                    date: '2018-11-16',
                    location: 'Field - Kickball'
                }]
            },
            {
                title: "Field - Soccer",
                data: [{
                    game_id: 1488,
                    date: '2018-11-16',
                    location: 'Field - Soccer'
                }]
            }
        ]
    }
]

我已经试过了

代码语言:javascript
复制
const games = [data here]
var groups = _(games)
.groupBy(x => x.date)
        .map(value => {
            return _.groupBy(value, 'location')
            .map(({key, value}) => ({title: key, data: value}))
        })

        .map((value, key) => {
            return ({title: value[Object.keys(value)[0]][0].date, data: value})
        })
EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2019-05-19 10:20:42

像这样使用reduce

代码语言:javascript
复制
const data = [{game_id:1171,date:'2016-11-17T05:00:00.000Z',time:'08:00:00',category:'Ch B Coed',background:'#FFFF00',textcolor:'#000000',bold:0,sport:'Newcomb',location:'Plaza',text:'COL2 vs. USA1 1171'},{game_id:1189,date:'2016-11-17T05:00:00.000Z',time:'08:50:00',category:'Ch A Coed',background:'#FF33CC',textcolor:'#000000',bold:0,sport:'Kickball',location:'Field - Kickball',text:'COL1 vs. USA1 1189'},{game_id:1489,date:'2016-2-17T05:00:00.000Z',time:'04:50:00',category:'Ch B Coed',background:'#FF33CC',textcolor:'#000000',bold:0,sport:'Kickball',location:'Field - Kickball',text:'COL2 vs. USA3 1489'}];

const res = Object.values(data.reduce((acc, { date, ...rest }) => acc[date] ? { ...acc, [date]: { ...acc[date], data: acc[date].data.concat({ date, ...rest })} } : { ...acc, [date]: { title: date, data: [{ date, ...rest }] }}, {}));

console.log(res);
代码语言:javascript
复制
.as-console-wrapper { max-height: 100% !important; top: auto; }

票数 1
EN

Stack Overflow用户

发布于 2019-05-19 16:23:28

如果我错过了什么,请原谅,但对我来说,这似乎可以通过Array.reduce以一种更简单的方式完成

代码语言:javascript
复制
let data = [{ game_id: 1171, date: '2016-11-17T05:00:00.000Z', time: '08:00:00', category: 'Ch B Coed', background: '#FFFF00', textcolor: '#000000', bold: 0, sport: 'Newcomb', location: 'Plaza', text: 'COL2 vs. USA1 1171' }, { game_id: 1189, date: '2016-11-17T05:00:00.000Z', time: '08:50:00', category: 'Ch A Coed', background: '#FF33CC', textcolor: '#000000', bold: 0, sport: 'Kickball', location: 'Field - Kickball', text: 'COL1 vs. USA1 1189' }, { game_id: 1489, date: '2016-2-17T05:00:00.000Z', time: '04:50:00', category: 'Ch B Coed', background: '#FF33CC', textcolor: '#000000', bold: 0, sport: 'Kickball', location: 'Field - Kickball', text: 'COL2 vs. USA3 1489' } ]

let result = data.reduce((r, c) => {
  r[c.date] = r[c.date] || {title: c.date, data: []}
  r[c.date].data = [...(r[c.date].data || []), c]
  return r
}, {})

console.log(Object.values(result))

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/56204235

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