如何过滤以任意元音开头的字符串？[python]
如何过滤以任意元音开头的字符串？[python]
提问于 2019-05-20 00:39:44
字符串是“banana”。我已经创建了所有的子串，现在想要过滤那些以元音开头或不以元音开头的子串。我想使用任何操作，但不知道如何使用它。
l = ['', 'an', 'anan', 'na', 'ana', 'n', 'a', 'anana', 'ba', 'b', 'ban', 'nan', 'banan', 'banana', 'nana', 'bana']
vowels = 'aeiou'
for word in l:
if word.startswith( any(vowels)): #this gives error
print("this word starts with vowel")
print(word)回答 2
Stack Overflow用户
发布于 2019-05-20 00:41:20
l = ['', 'an', 'anan', 'na', 'ana', 'n', 'a', 'anana', 'ba', 'b', 'ban', 'nan', 'banan', 'banana', 'nana', 'bana']
vowels = 'aeiou'
for word in l:
if any(word.startswith(v) for v in vowels):
print("this word starts with vowel")
print(word)Stack Overflow用户
发布于 2019-05-20 01:40:25
您可以将允许启动的tuple提供给.startswith
l = ['', 'an', 'anan', 'na', 'ana', 'n', 'a', 'anana', 'ba', 'b', 'ban', 'nan', 'banan', 'banana', 'nana', 'bana']
vowels = ('a','e','i','o','u')
for word in l:
if word.startswith(vowels):
print("this word starts with vowel")
print(word)输出：
this word starts with vowel
an
this word starts with vowel
anan
this word starts with vowel
ana
this word starts with vowel
a
this word starts with vowel
anana页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/56209912
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