我需要你的帮助!我有一个具有已知坐标的点,比如{x:5, y:4}
和对象数组,每个对象都表示点:
[{x:2,y:6},{x:14,y:10},{x:7,y:10},{x:11,y:6},{x:6,y:2}]
现在,我需要按距给定点的距离以升序对数组进行排序,如下所示:
[{x: 6, y: 2}, {x: 2, y: 6}, {x: 7, y: 10}, {x: 11, y: 6}, {x: 14, y: 10}]
我怎么才能用JS做到这一点呢?谢谢!
发布于 2019-05-20 23:23:58
我想,这可能行得通:
//reference point
const a = {x:5,y:4};
//array of points to sort
const points = [{x:2,y:6},{x:14,y:10},{x:7,y:10},{x:11,y:6},{x:6,y:2}];
//squared distance
const sqDist = (pointa, pointb) => (pointa.x-pointb.x)**2+(pointa.y-pointb.y)**2;
//sorting
const res = points.sort((pointa, pointb) => sqDist(a,pointa)-sqDist(a,pointb));
console.log(res);
.as-console-wrapper {
max-height: 100% !important;
top: 0;
}
发布于 2019-05-20 23:44:50
这是一个略短的版本,没有使用Math.sqrt
,因为它使用增量的平方和。
const
array = [{ x: 2, y: 6 }, { x: 14, y: 10 }, { x: 7, y: 10 }, { x: 11, y: 6 }, { x: 6, y: 2 }],
point = { x: 5, y: 4 };
array.sort((a, b) =>
(a.x - point.x) ** 2 + (a.y - point.y) ** 2 -
(b.x - point.x) ** 2 + (b.y - point.y) ** 2
);
console.log(array)
.as-console-wrapper { max-height: 100% !important; top: 0; }
https://stackoverflow.com/questions/56223861
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