将if etc语句转换为开关
将if etc语句转换为开关
提问于 2019-05-28 05:49:57
在将if-etc语句转换为开关时，我遇到了问题。我正在创建一个在C+中的Tic-Tac-脚趾游戏。我不确定如何在开关本身内使用2D数组矩阵。本练习的目的是单独切换。下面是我到目前为止是如何编写代码的代码。
switch (a)
{
case 1:
if(matrix[0][0] == '1')
matrix[0][0] = player_1;
else
{
cout << "Field is already in use. Try again" << endl;
input(); //Calling function input to prompt user to key in value again and again
}
break;
case 2:
if(matrix[0][1] == '2')
matrix[0][1] = player_1;
else {
cout << "Field is already in use. Try again" << endl;
input(); //Calling function input to prompt user to key in value again and again
}
break;
case 3:
if(matrix[0][2] == '3')
matrix[0][2] = player_1;
else {
cout << "Field is already in use. Try again" << endl;
input(); //Calling function input to prompt user to key in value again and again
}
break;
case 4:
if(matrix[1][0] == '4')
matrix[1][0] = player_1;
else {
cout << "Field is already in use. Try again" << endl;
input(); //Calling function input to prompt user to key in value again and again
}
break;
case 5:
if(matrix[1][1] == '5')
matrix[1][1] = player_1;
else {
cout << "Field is already in use. Try again" << endl;
input();//Calling function input to prompt user to key in value again and again
}
break;
case 6:
if(matrix[1][2] == '6')
matrix[1][2] = player_1;
else {
cout << "Field is already in use. Try again" << endl;
input();//Calling function input to prompt user to key in value again and again
}
break;
case 7:
if(matrix[2][0] == '7')
matrix[2][0] = player_1;
else {
cout << "Field is already in use.Try again" << endl;
input();//Calling function input to prompt user to key in value again and again
}
break;
case 8:
if(matrix[2][1] == '8')
matrix[2][1] = player_1;
else {
cout << "Field is already in use. Try again" << endl;
input();//Calling function input to prompt user to key in value again and again
}
break;
case 9:
if(matrix[2][2] == '9')
matrix[2][2] = player_1;
else {
cout << "Field is already in use. Try again" << endl;
input();//Calling function input to prompt user to key in value again and again
}
break;
default:
cout << "Number inputted doesn't exist. Please try again" << endl;
input(); //Calling function input to prompt user to key in value again and again
}回答 1
Stack Overflow用户
发布于 2019-05-28 15:34:26
如果必须使用switch，可以通过以下方式计算位置（行和列）来简化代码switch：
int row = 0;
int column = 0;
bool position_is_valid = true;
switch (a)
{
case 1: row = 0; column = 0; break;
case 2: row = 0; column = 1; break;
case 3: row = 0; column = 2; break;
case 4: row = 1; column = 0; break;
case 5: row = 1; column = 1; break;
case 6: row = 1; column = 2; break;
case 7: row = 2; column = 0; break;
case 8: row = 2; column = 1; break;
case 9: row = 2; column = 2; break;
default: position_is_valid = false; break;
}
if (position_is_valid)
{
if (matrix[row][column]) == '0' + a)
{
matrix[row][column] = player1;
}
else
{
std::cout << "Position is not empty.\n";
}
}
else
{
std::cout << "Position is invalid.\n";
}
通常，如果您重复代码或查看模式，则可以简化代码或简化设计。
编辑1：更多代码switch
您可以将空框字符的计算添加到开关中：
char empty_field_value = ' ';
switch (a)
{
case 1: row = 0; column = 0; empty_field_value = '1'; break;
case 2: row = 0; column = 1; empty_field_value = '2'; break;
case 3: row = 0; column = 2; empty_field_value = '3'; break;
case 4: row = 1; column = 0; empty_field_value = '4'; break;
case 5: row = 1; column = 1; empty_field_value = '5'; break;
case 6: row = 1; column = 2; empty_field_value = '6'; break;
case 7: row = 2; column = 0; empty_field_value = '7'; break;
case 8: row = 2; column = 1; empty_field_value = '8'; break;
case 9: row = 2; column = 2; empty_field_value = '9'; break;
default: position_is_valid = false; break;
}
if (position_is_valid)
{
if (matrix[row][column]) == empty_field_value)
{
matrix[row][column] = player1;
}
else
{
std::cout << "Position is not empty.\n";
}
}
else
{
std::cout << "Position is invalid.\n";
}
我建议不要将if语句放入switch，因为它们不依赖于switch值。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/-100006836
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