blocks|key|4684223|text|因为您已经获得了Uri。现在，您必须在getBitmap()中传递该Uri以获取位图并使用该位图。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4684224|Uri+imageUri+=+intent.getData();
Bitmap+bitmap+=+MediaStore.Images.Media.getBitmap(this.getContentResolver(),imageUri);
Imageview+my_img_view+=+(Imageview+)+findViewById+(R.id.my_img_view);
my_img_view.setImageBitmap(bitmap);|code-block|syntax|javascript|4684225|entityMap^0|J|B|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

As you have already get the Uri. Now you have to pass that Uri in <code>getBitmap()</code> to get bitmap and use that bitmap.

<pre><code>Uri imageUri = intent.getData();
Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(),imageUri);
Imageview my_img_view = (Imageview ) findViewById (R.id.my_img_view);
my_img_view.setImageBitmap(bitmap);
</code></pre>

blocks|key|4684175|text|为了从uri获取位图，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4684176|Bitmap++mBitmap+=+Media.getBitmap(this.getContentResolver(),+uri);|code-block|syntax|javascript|4684177|希望这对你有帮助。|4684178|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

For getting bitmap from uri,

<pre><code>Bitmap mBitmap = Media.getBitmap(this.getContentResolver(), uri);
</code></pre>

Hope this helps you.

blocks|key|178155|text|Retrive+bitmap+from+uri.....

public+static+Bitmap+decodeUriToBitmap(Context+mContext,+Uri+sendUri)+{
++++++++Bitmap+getBitmap+=+null;
++++++++try+{
++++++++++++InputStream+image_stream;
++++++++++++try+{
++++++++++++++++image_stream+=+mContext.getContentResolver().openInputStream(sendUri);
++++++++++++++++getBitmap+=+BitmapFactory.decodeStream(image_stream);
++++++++++++}+catch+(FileNotFoundException+e)+{
++++++++++++++++e.printStackTrace();
++++++++++++}
++++++++}+catch+(Exception+e)+{
++++++++++++e.printStackTrace();
++++++++}
++++++++return+getBitmap;
++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|178156|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>Retrive bitmap from uri.....

public static Bitmap decodeUriToBitmap(Context mContext, Uri sendUri) {
 Bitmap getBitmap = null;
 try {
 InputStream image_stream;
 try {
 image_stream = mContext.getContentResolver().openInputStream(sendUri);
 getBitmap = BitmapFactory.decodeStream(image_stream);
 } catch (FileNotFoundException e) {
 e.printStackTrace();
 }
 } catch (Exception e) {
 e.printStackTrace();
 }
 return getBitmap;
 }
</code></pre>

blocks|key|178186|text|这是我的工作|type|unstyled|depth|inlineStyleRanges|entityRanges|data|178187|protected+void+onActivityResult(int+requestCode,+int+resultCode,+Intent+data)
{
super.onActivityResult(requestCode,+resultCode,+data);
if+(resultCode+==+RESULT_OK)
{
++++Uri+imageUri+=+data.getData();
++++Bitmap+bitmap+=+MediaStore.Images.Media.getBitmap(this.getContentResolver(),+imageUri);
}
}|code-block|syntax|javascript|178188|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is work for me

<pre><code>protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
super.onActivityResult(requestCode, resultCode, data);
if (resultCode == RESULT_OK)
{
 Uri imageUri = data.getData();
 Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
}
}
</code></pre>

blocks|key|4684275|text|你可以试试这个。您可以在onActivityResult方法中调用setPic()。我曾在一个应用程序中使用它来拍摄照片并将其放入ImageView中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4684276|private+void+setPic()+{

++++//currentPhotoPath+contains+path+of+image+file.
++++//visorFoto+is+a+reference+to+an+ImageView+object.
++++File+file+=+new+File(currentPhotoPath);
++++Uri+imageUri+=+Uri.fromFile(file);
++++visorFoto.setImageURI(imageUri);

}|code-block|syntax|javascript|4684277|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can try this. You can call setPic() in onActivityResult method. I have used this in an application to take photos an put it in an ImageView.

<pre><code>private void setPic() {

 //currentPhotoPath contains path of image file.
 //visorFoto is a reference to an ImageView object.
 File file = new File(currentPhotoPath);
 Uri imageUri = Uri.fromFile(file);
 visorFoto.setImageURI(imageUri);

}
</code></pre>

blocks|key|4684300|text|一旦你有了Uri，你就可以使用这样的东西：-|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4684301|fun+getBitmapFromUri(context:+Context,+uri:+Uri):+Bitmap?+{
++++++++
++++++++var+parcelFileDescriptor:+ParcelFileDescriptor?+=+null
++++++++return+try+{
++++++++++++parcelFileDescriptor+=+context.contentResolver.openFileDescriptor(uri,+"r")
++++++++++++val+fileDescriptor:+FileDescriptor?+=+parcelFileDescriptor?.fileDescriptor
++++++++++++val+image+=+BitmapFactory.decodeFileDescriptor(fileDescriptor)
++++++++++++parcelFileDescriptor?.close()
++++++++++++image
++++++++}+catch+(e:+Exception)+{
++++++++++++//Log.e(TAG,+"Failed+to+load+image.",+e)
++++++++++++null
++++++++}+finally+{
++++++++++++try+{
++++++++++++++++parcelFileDescriptor?.close()
++++++++++++}+catch+(e:+IOException)+{
++++++++++++++++e.printStackTrace()
++++++++++++++++//Log.e(TAG,+"Error+closing+ParcelFile+Descriptor")
++++++++++++}
++++++++}
++++}|code-block|syntax|javascript|4684302|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Once u have the Uri, you can use something like:-
<pre><code>fun getBitmapFromUri(context: Context, uri: Uri): Bitmap? {
 
 var parcelFileDescriptor: ParcelFileDescriptor? = null
 return try {
 parcelFileDescriptor = context.contentResolver.openFileDescriptor(uri, &quot;r&quot;)
 val fileDescriptor: FileDescriptor? = parcelFileDescriptor?.fileDescriptor
 val image = BitmapFactory.decodeFileDescriptor(fileDescriptor)
 parcelFileDescriptor?.close()
 image
 } catch (e: Exception) {
 //Log.e(TAG, &quot;Failed to load image.&quot;, e)
 null
 } finally {
 try {
 parcelFileDescriptor?.close()
 } catch (e: IOException) {
 e.printStackTrace()
 //Log.e(TAG, &quot;Error closing ParcelFile Descriptor&quot;)
 }
 }
 }
</code></pre>

blocks|key|4684330|text|参考Android+Developers+documentation，您可以使用它从URI获取位图|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4684331|++++....

++++Uri+uri+=+intent.getData();
++++try+{
++++++++Bitmap+bitmap+=+getBitmapFromUri(uri);
++++++++//+do+something+with+this+bitmap

++++}+catch+(IOException+e)+{
++++++++e.printStackTrace();
++++}
}


private+Bitmap+getBitmapFromUri(Uri+uri)+throws+IOException+{
++++ParcelFileDescriptor+parcelFileDescriptor+=+context.getContentResolver().openFileDescriptor(uri,+"r");
++++FileDescriptor+fileDescriptor+=+parcelFileDescriptor.getFileDescriptor();
++++Bitmap+image+=+BitmapFactory.decodeFileDescriptor(fileDescriptor);
++++parcelFileDescriptor.close();
++++return+image;
}|code-block|syntax|javascript|4684332|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.android.com/training/data-storage/shared/documents-files#bitmap^0|2|W|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

referring to <a href="https://developer.android.com/training/data-storage/shared/documents-files#bitmap" rel="nofollow noreferrer">Android Developers documentation</a> you can use this to get bitmap from an URI
<pre><code> ....

 Uri uri = intent.getData();
 try {
 Bitmap bitmap = getBitmapFromUri(uri);
 // do something with this bitmap

 } catch (IOException e) {
 e.printStackTrace();
 }
}


private Bitmap getBitmapFromUri(Uri uri) throws IOException {
 ParcelFileDescriptor parcelFileDescriptor = context.getContentResolver().openFileDescriptor(uri, &quot;r&quot;);
 FileDescriptor fileDescriptor = parcelFileDescriptor.getFileDescriptor();
 Bitmap image = BitmapFactory.decodeFileDescriptor(fileDescriptor);
 parcelFileDescriptor.close();
 return image;
}
</code></pre>

blocks|key|178095|text|请喜欢这个链接。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|178096|这就是你要找的How+to+get+Bitmap+from+an+Uri?|offset|length|178097|试试这个，它对我很有效：|178098|public+static+Bitmap+getBitmapFromURL(String+src)+{
++++++++try+{
++++++++++++System.out.printf("src",+src);
++++++++++++URL+url+=+new+URL(src);
++++++++++++HttpURLConnection+connection+=+(HttpURLConnection)+url
++++++++++++++++++++.openConnection();
++++++++++++connection.setDoInput(true);
++++++++++++connection.connect();
++++++++++++InputStream+input+=+connection.getInputStream();
++++++++++++Bitmap+myBitmap+=+BitmapFactory.decodeStream(input);
++++++++++++System.out.printf("Bitmap",+"returned");
++++++++++++myBitmap+=+Bitmap.createScaledBitmap(myBitmap,+100,+100,+false);//This+is+only+if+u+want+to+set+the+image+size.
++++++++++++return+myBitmap;
++++++++}+catch+(IOException+e)+{
++++++++++++e.printStackTrace();
++++++++++++System.out.printf("Exception",+e.getMessage());
++++++++++++return+null;
++++++++}|code-block|syntax|javascript|178099|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/3879992/get-bitmap-from-an-uri-android^0|0|7|U|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@$D|W|E|X|1|Y]]|A|$]]|$1|F|3|G|5|6|7|Z|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|10|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

Please prefer this link.

This is what you are looking for 
<a href="https://stackoverflow.com/questions/3879992/get-bitmap-from-an-uri-android">How to get Bitmap from an Uri?</a>

Try this it works for me: 

<pre><code>public static Bitmap getBitmapFromURL(String src) {
 try {
 System.out.printf("src", src);
 URL url = new URL(src);
 HttpURLConnection connection = (HttpURLConnection) url
 .openConnection();
 connection.setDoInput(true);
 connection.connect();
 InputStream input = connection.getInputStream();
 Bitmap myBitmap = BitmapFactory.decodeStream(input);
 System.out.printf("Bitmap", "returned");
 myBitmap = Bitmap.createScaledBitmap(myBitmap, 100, 100, false);//This is only if u want to set the image size.
 return myBitmap;
 } catch (IOException e) {
 e.printStackTrace();
 System.out.printf("Exception", e.getMessage());
 return null;
 }
</code></pre>

I have included 'share via myApp' option. I inserted following code in the receiving activity class.

<pre><code> // Get the intent that started this activity
 Intent intent = getIntent();
 Uri data = intent.getData();

 // Figure out what to do based on the intent type
 if (intent.getType().indexOf("image/") != -1) {
 // Handle intents with image data ...
}
</code></pre>

What is the next step to retrieve bitmap image.

Retrieve bitmap from uri

我已经包含了“通过myApp共享”选项。我在接收activity类中插入了以下代码。    // Get the intent that started this activity    Intent intent = getIntent();    Uri data = intent.getData();    // Figure out what to do based on the inte

问从uri中检索位图
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