我有一个Python列表,例如list = [1,2,3,4,5,6,7,8,9]
。此外,我还有另一个列表list2 = ['a','b','c','d','e','f','g','h','j']
。现在我想做以下几件事:
idx = (list > 3) & (list < 7)
list2 = list2[idx]
这应该会产生['d','e','f']
。当然,这在列表中是不可能实现的。如何在列表中做到这一点?
发布于 2019-05-28 23:02:03
您可以使用zip
l1 = [1,2,3,4,5,6,7,8,9]
l2 = ['a','b','c','d','e','f','g','h','j']
result = [a for a, b in zip(l2, l1) if 3 < b < 7]
输出:
['d', 'e', 'f']
要获得简化的列表,请执行以下操作:
result, reduced = map(list, zip(*[[a, b] for a, b in zip(l2, l1) if 3 < b < 7]))
输出:
['d', 'e', 'f'] #result
[4, 5, 6] #reduced
发布于 2019-05-28 23:04:34
试试这个:
#Make sure all lists are numpy arrays.
import numpy as np
idx = np.where((list > 3) & (list < 7))
list2 = list2[idx]
https://stackoverflow.com/questions/56345067
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