根据用户的活动成员资格数量显示/隐藏内容
根据用户的活动成员资格数量显示/隐藏内容
提问于 2019-06-10 03:45:54
使用短代码，我需要根据用户拥有的活跃会员数量来显示内容，而不管他是哪个会员计划的成员。
我并不是很喜欢PHP，但是我发现wc_memberships_get_user_memberships函数是存在的，所以我想这样开始吧。但这几乎是我的极限：
add_shortcode('count-active-memberships', 'count_active_memberships');
function count_active_memberships(){
$user_id = get_current_user_id();
$args = array(
'status' = 'active'
);
$active_memberships = count(wc_memberships_get_user_memberships( $user_id, $args ));
}最后，它应该看起来像
count- active - memberships ="3“具有3个活动成员的成员内容/count-active-memberships
谢谢你的帮忙
回答 1
Stack Overflow用户
回答已采纳
发布于 2019-06-10 07:46:10
当您注册一个短码时，您的回调函数count_active_memberships()最多会接收两个参数：
- 一个参数数组(传递给短码的参数)，
- 短码内的内容(count-
- -memberships is the content active
如果您希望仅在当前用户具有3个或更多活动成员资格时才显示某些内容，则可以执行以下操作：
add_shortcode('count-active-memberships', 'count_active_memberships');
function count_active_memberships($atts, $content = ''){
$user_id = get_current_user_id();
// The user is logged in, check memberships
if ( $user_id ) {
$args = array(
'status' => 'active'
);
$active_memberships = wc_memberships_get_user_memberships($user_id, $args);
if ( is_array($active_memberships) && count($active_memberships) >= 3 ) {
return $content;
}
}
// User is either not logged in or doesn't have enough active memberships
// so let's return an empty string.
return '';
}现在，如果您希望用户可以配置所需的最低成员资格数量，则需要定义一个新属性(例如，min_memberships)在注册短码的函数内。例如：
add_shortcode('count-active-memberships', 'count_active_memberships');
function count_active_memberships($atts, $content = ''){
// Shortcode attributes
$atts = shortcode_atts(array(
'min_memberships' => 3
), $atts, 'count-active-memberships');
// Let's make sure that the value passed by the user is a number
if (
! is_numeric($atts['min_memberships'])
|| $atts['min_memberships'] < 0
) {
$atts['min_memberships'] = 3; // Fallback to minimum 3 memberships
}
$user_id = get_current_user_id();
// The user is logged in, check memberships
if ( $user_id ) {
$args = array(
'status' => 'active'
);
$active_memberships = wc_memberships_get_user_memberships($user_id, $args);
if (
is_array($active_memberships)
&& count($active_memberships) >= $atts['min_memberships']
) {
return $content;
}
}
// User is either not logged in or doesn't have enough active memberships
// so let's return an empty string.
return '';
}然后你就可以这样做了：
[count-active-memberships min_memberships=5]
Content visible to users with 5 or more active memberships
[/count-active-memberships]页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/56517875
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