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改装始终响应onFailure
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Stack Overflow用户
提问于 2019-06-11 00:52:34
回答 1查看 518关注 0票数 0

我正在设置一个新的安卓项目,并使用改进,我的改进功能在模拟器(NOX)和邮递员中工作正常,但当我尝试在移动设备上构建我的应用程序时,更新总是进入onFailure,有人能给我解决方案吗?我的API发布在公共主机上,

这就是我所说的翻新

代码语言:javascript
复制
 private APIInterface getInterfaceService() {
        Retrofit retrofit = new Retrofit.Builder()
                .baseUrl(BASE_URL)
                .addConverterFactory(GsonConverterFactory.create())
                .build();
        final APIInterface mInterfaceService = retrofit.create(APIInterface.class);
        return mInterfaceService;
    }

 private void loginInterface(final String username, final String password){
        APIInterface mApiService = this.getInterfaceService();
        Call<Response> mService = mApiService.loginRequest(username,password);
        mService.enqueue(new Callback<Response>() {
            @Override
            public void onResponse(Call<Response> call, retrofit2.Response<Response> response) {
                if(response.body().getValue()==1){
                    Toast.makeText(Login.this,"Welcome",Toast.LENGTH_SHORT).show();
                    Intent intent = new Intent(getApplicationContext(),HomePage.class);
                    startActivity(intent);
                    finish();
                }else{
                    Toast.makeText(Login.this,"Invalid Username or Password",Toast.LENGTH_SHORT).show();
                }
            }

            @Override
            public void onFailure(Call<Response> call, Throwable t) {
                Toast.makeText(Login.this,t.getMessage(),Toast.LENGTH_SHORT).show();
            }
        });
    }

我的回应

代码语言:javascript
复制
 public class Response {

    @SerializedName("value")
    @Expose
    private Integer value;
    @SerializedName("result")
    @Expose
    private List<User> result = null;

    public Integer getValue() {
        return value;
    }

    public void setValue(Integer value) {
        this.value = value;
    }

    public List<User> getResult() {
        return result;
    }

    public void setResult(List<User> result) {
        this.result = result;
    }

}

用户模型

代码语言:javascript
复制
 public class User {
    @SerializedName("id")
    @Expose
    private String id;
    @SerializedName("username")
    @Expose
    private String username;
    @SerializedName("password")
    @Expose
    private String password;
    @SerializedName("email")
    @Expose
    private String email;
    @SerializedName("image")
    @Expose
    private Object image;
    @SerializedName("point")
    @Expose
    private String point;
    @SerializedName("reputation")
    @Expose
    private String reputation;
    @SerializedName("role")
    @Expose
    private String role;

    public User(String id, String username, String password, String email, Object image, String point, String reputation, String role) {
        this.id = id;
        this.username = username;
        this.password = password;
        this.email = email;
        this.image = image;
        this.point = point;
        this.reputation = reputation;
        this.role = role;
    }

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public Object getImage() {
        return image;
    }

    public void setImage(Object image) {
        this.image = image;
    }

    public String getPoint() {
        return point;
    }

    public void setPoint(String point) {
        this.point = point;
    }

    public String getReputation() {
        return reputation;
    }

    public void setReputation(String reputation) {
        this.reputation = reputation;
    }

    public String getRole() {
        return role;
    }

    public void setRole(String role) {
        this.role = role;
    }
}

API接口

代码语言:javascript
复制
public interface APIInterface {
    @FormUrlEncoded
    @POST("login.php")
    Call<Response> loginRequest(@Field("username") String username,
                            @Field("password") String password);
}

我从t.message收到此消息:网络安全策略不允许与{my api url}进行明文通信。

在我将这个添加到清单中之后

代码语言:javascript
复制
android:usesCleartextTraffic="true"

我得到了这个新的'java.lang.IllegalStateException:预期的BEGIN_OBJECT,但在第1行第1列路径$处是字符串‘

我的JSON响应是这样的

代码语言:javascript
复制
{"value":1,"result":[{"id":"1","username":"username","password":"password","email":"email","image":null,"point":"0","reputation":"0","role":"2"}]}

这是我的邮递员回复

EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/56530457

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