问如何使用Regex从字符串中获取文件名

EN

([^\s]+\.[a-z][a-z0-9]+)

# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility

import re

regex = r"([^\s]+\.[a-z][a-z0-9]+)"

test_str = "\"['\\r\\n                    File: FLO_JIUWASOKLDM_05_HetR_IUSJA_&_Cracks.mp4', <br/>, '\\r\\n                    Size: 48.14 MB                ']\"
"

matches = re.finditer(regex, test_str, re.MULTILINE | re.IGNORECASE)

for matchNum, match in enumerate(matches, start=1):

    print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))

    for groupNum in range(0, len(match.groups())):
        groupNum = groupNum + 1

        print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))

# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.