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根据为属性指定的值验证Json架构
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Stack Overflow用户
提问于 2019-06-18 14:31:39
回答 1查看 700关注 0票数 1

我有一个Json请求,其中包含以下数据和对应的json模式

有了这个请求,我想根据模式创建一些所需的字段

假设模式为1,那么我希望obj1中的字段a和b为必填项,obj3中的字段x为必填项。现在,如果模式是2,我希望obj2中的字段p、q和r是必需的,obj1中的字段a和c是必需的,obj3中的字段y是必需的。接下来,如果模式是3,我只需要字段a和c

Json请求

代码语言:javascript
复制
{
  "mode": "1",
  "obj1": {
      "a": 12,
      "b": "test",
      "c": "18 June 2019"
      },
 "obj2": {
      "p": 100,
      "q": "new",
      "r": "19 June 2019",
      "s" : "test2"
      },
  "obj3": {
      "x": 12,
      "y": "test3"
      }
}


**Json schema**
{
  "definitions": {},
  "$schema": "http://json-schema.org/draft-07/schema#",
  "$id": "http://example.com/root.json",
  "type": "object",
  "properties": {
    "mode": {
      "$id": "#/properties/mode",
      "type": "string",
      "examples": [
        "1"
      ]
    },
    "obj1": {
      "$id": "#/properties/obj1",
      "type": "object",
      "title": "The Obj 1 Schema",
      "properties": {
        "a": {
          "$id": "#/properties/obj1/properties/a",
          "type": "integer",
          "examples": [
            12
          ]
        },
        "b": {
          "$id": "#/properties/obj1/properties/b",
          "type": "string",
          "examples": [
            "test"
          ]
        },
        "c": {
          "$id": "#/properties/obj1/properties/c",
          "type": "string",
          "examples": [
            "18 June 2019"
          ]
        }
      }
    },
    "obj 2": {
      "$id": "#/properties/obj2",
      "type": "object",
      "title": "The Obj 2 Schema",
      "properties": {
        "p": {
          "$id": "#/properties/obj2/properties/p",
          "type": "integer",
          "examples": [
            100
          ]
        },
        "q": {
          "$id": "#/properties/obj2/properties/q",
          "type": "string",
          "examples": [
            "new"
          ]
        },
        "r": {
          "$id": "#/properties/obj2/properties/r",
          "type": "string",
          "examples": [
            "19 June 2019"
          ]
        },
        "s": {
          "$id": "#/properties/obj2/properties/s",
          "type": "string",
          "examples": [
            "test2"
          ]
        }
      }
    },
    "obj 3": {
      "$id": "#/properties/obj3",
      "type": "object",
      "title": "The Obj 3 Schema",
      "properties": {
        "x": {
          "$id": "#/properties/obj3/properties/x",
          "type": "integer",
          "examples": [
            12
          ]
        },
        "y": {
          "$id": "#/properties/obj3/properties/y",
          "type": "string",
          "examples": [
            "test3"
          ]
        }
      }
    }
  }
}

编辑-将模式更改为基于@gregsdennis的建议进行验证

JSON模式

代码语言:javascript
复制
    {
      "definitions": {},
      "$schema": "http://json-schema.org/draft-07/schema#",
      "$id": "http://example.com/root.json",
      "type": "object",
      "properties": {
        "mode": {
          "$id": "#/properties/mode",
          "type": "string",
          "examples": [
            "1"
          ]
        },
        "obj1": {
          "$id": "#/properties/obj1",
          "type": "object",
          "title": "The Obj 1 Schema",
          "properties": {
            "a": {
              "type": "integer",
              "examples": [
                12
              ]
            },
            "b": {
              "type": "string",
              "examples": [
                "test"
              ]
            },
            "c": {
              "type": "string",
              "examples": [
                "18 June 2019"
              ]
            }
          }
        },
        "obj 2": {
          "$id": "#/properties/obj2",
          "type": "object",
          "title": "The Obj 2 Schema",
          "properties": {
            "p": {
              "type": "integer",
              "examples": [
                100
              ]
            },
            "q": {
              "type": "string",
              "examples": [
                "new"
              ]
            },
            "r": {
              "type": "string",
              "examples": [
                "19 June 2019"
              ]
            },
            "s": {
              "type": "string",
              "examples": [
                "test2"
              ]
            }
          }
        },
        "obj 3": {
          "$id": "#/properties/obj3",
          "type": "object",
          "title": "The Obj 3 Schema",
          "properties": {
            "x": {
              "type": "integer",
              "examples": [
                12
              ]
            },
            "y": {
              "type": "string",
              "examples": [
                "test3"
              ]
            }
          }
        }
      },
"oneOf": [
    {
      "properties": {
        "mode": {"const": 1},
        "obj1": {"required": ["a","b"]},
        "obj3": {"required": ["x"]}
       }
    },
    {
      "properties": {
        "mode": {"const": 2},
        "obj2": {"required": ["p","q","r"]},
        "obj1": {"required": ["a","c"]},
        "obj3": {"required": ["y"]}
       }
    }
]
    }

因此,简而言之,无论我有多少个模式、字段或对象,我只希望在给定时间为特定模式从不同对象中选择几个字段。有没有人能提出一些解决方案来实现这一点?在json模式中有可能有这样的验证吗?

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回答 1

Stack Overflow用户

回答已采纳

发布于 2019-06-19 05:18:51

您需要的是一个oneOf,其中每个子模式都为每个obj*属性提供一个有效状态。每个状态都是这样的:

代码语言:javascript
复制
{
  "properties": {
    "mode": {"const": 1},
    "obj1": {"required": ["a","b"]},
    "obj3": {"required": ["x"]}
  }
}

为您在问题中列出的每个状态创建其中一个,并将它们全部放入位于根目录的oneOf中。

您可以使用if/then/else,来实现这一点,但对于这种情况,我更喜欢使用oneOf来避免嵌套。

另外,我注意到中间有很多多余的$id,它们只是指定它们在模式中的位置。你想要一个在根的,但是你不需要其他的。实现可以很容易地解决这类基于位置的引用。

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/56642941

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