根据为属性指定的值验证Json架构
根据为属性指定的值验证Json架构
提问于 2019-06-18 14:31:39
我有一个Json请求，其中包含以下数据和对应的json模式
有了这个请求，我想根据模式创建一些所需的字段
假设模式为1，那么我希望obj1中的字段a和b为必填项，obj3中的字段x为必填项。现在，如果模式是2，我希望obj2中的字段p、q和r是必需的，obj1中的字段a和c是必需的，obj3中的字段y是必需的。接下来，如果模式是3，我只需要字段a和c
Json请求
{
"mode": "1",
"obj1": {
"a": 12,
"b": "test",
"c": "18 June 2019"
},
"obj2": {
"p": 100,
"q": "new",
"r": "19 June 2019",
"s" : "test2"
},
"obj3": {
"x": 12,
"y": "test3"
}
}
**Json schema**
{
"definitions": {},
"$schema": "http://json-schema.org/draft-07/schema#",
"$id": "http://example.com/root.json",
"type": "object",
"properties": {
"mode": {
"$id": "#/properties/mode",
"type": "string",
"examples": [
"1"
]
},
"obj1": {
"$id": "#/properties/obj1",
"type": "object",
"title": "The Obj 1 Schema",
"properties": {
"a": {
"$id": "#/properties/obj1/properties/a",
"type": "integer",
"examples": [
12
]
},
"b": {
"$id": "#/properties/obj1/properties/b",
"type": "string",
"examples": [
"test"
]
},
"c": {
"$id": "#/properties/obj1/properties/c",
"type": "string",
"examples": [
"18 June 2019"
]
}
}
},
"obj 2": {
"$id": "#/properties/obj2",
"type": "object",
"title": "The Obj 2 Schema",
"properties": {
"p": {
"$id": "#/properties/obj2/properties/p",
"type": "integer",
"examples": [
100
]
},
"q": {
"$id": "#/properties/obj2/properties/q",
"type": "string",
"examples": [
"new"
]
},
"r": {
"$id": "#/properties/obj2/properties/r",
"type": "string",
"examples": [
"19 June 2019"
]
},
"s": {
"$id": "#/properties/obj2/properties/s",
"type": "string",
"examples": [
"test2"
]
}
}
},
"obj 3": {
"$id": "#/properties/obj3",
"type": "object",
"title": "The Obj 3 Schema",
"properties": {
"x": {
"$id": "#/properties/obj3/properties/x",
"type": "integer",
"examples": [
12
]
},
"y": {
"$id": "#/properties/obj3/properties/y",
"type": "string",
"examples": [
"test3"
]
}
}
}
}
}编辑-将模式更改为基于@gregsdennis的建议进行验证
JSON模式
{
"definitions": {},
"$schema": "http://json-schema.org/draft-07/schema#",
"$id": "http://example.com/root.json",
"type": "object",
"properties": {
"mode": {
"$id": "#/properties/mode",
"type": "string",
"examples": [
"1"
]
},
"obj1": {
"$id": "#/properties/obj1",
"type": "object",
"title": "The Obj 1 Schema",
"properties": {
"a": {
"type": "integer",
"examples": [
12
]
},
"b": {
"type": "string",
"examples": [
"test"
]
},
"c": {
"type": "string",
"examples": [
"18 June 2019"
]
}
}
},
"obj 2": {
"$id": "#/properties/obj2",
"type": "object",
"title": "The Obj 2 Schema",
"properties": {
"p": {
"type": "integer",
"examples": [
100
]
},
"q": {
"type": "string",
"examples": [
"new"
]
},
"r": {
"type": "string",
"examples": [
"19 June 2019"
]
},
"s": {
"type": "string",
"examples": [
"test2"
]
}
}
},
"obj 3": {
"$id": "#/properties/obj3",
"type": "object",
"title": "The Obj 3 Schema",
"properties": {
"x": {
"type": "integer",
"examples": [
12
]
},
"y": {
"type": "string",
"examples": [
"test3"
]
}
}
}
},
"oneOf": [
{
"properties": {
"mode": {"const": 1},
"obj1": {"required": ["a","b"]},
"obj3": {"required": ["x"]}
}
},
{
"properties": {
"mode": {"const": 2},
"obj2": {"required": ["p","q","r"]},
"obj1": {"required": ["a","c"]},
"obj3": {"required": ["y"]}
}
}
]
}因此，简而言之，无论我有多少个模式、字段或对象，我只希望在给定时间为特定模式从不同对象中选择几个字段。有没有人能提出一些解决方案来实现这一点？在json模式中有可能有这样的验证吗？
回答 1
Stack Overflow用户
回答已采纳
发布于 2019-06-19 05:18:51
您需要的是一个oneOf，其中每个子模式都为每个obj*属性提供一个有效状态。每个状态都是这样的：
{
"properties": {
"mode": {"const": 1},
"obj1": {"required": ["a","b"]},
"obj3": {"required": ["x"]}
}
}为您在问题中列出的每个状态创建其中一个，并将它们全部放入位于根目录的oneOf中。
您可以使用if/then/else，来实现这一点，但对于这种情况，我更喜欢使用oneOf来避免嵌套。
另外，我注意到中间有很多多余的$id，它们只是指定它们在模式中的位置。你想要一个在根的，但是你不需要其他的。实现可以很容易地解决这类基于位置的引用。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/56642941
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