我的视图上有一个DropDownList和一个按钮。单击按钮时,我希望将选定的DropDown值传递给控制器。该怎么做呢?
查看代码如下:
@model Sample2.Models.LeaveType
@{
ViewBag.Title = "Status of Application";
}
@{
List<SelectListItem> listItems = new List<SelectListItem>();
listItems.Add(new SelectListItem
{
Text = "All",
Value = "A",
Selected = true
});
listItems.Add(new SelectListItem
{
Text = "Recommended",
Value = "R"
});
listItems.Add(new SelectListItem
{
Text = "Sanctioned",
Value = "S"
});
}
<table>
<tr>
<td>
@Html.DropDownListFor(model => model.LeaveType1, listItems, "-- Select Status --")
</td>
<td>
@using (Html.BeginForm("Index", "Home", FormMethod.Get))
{
<input type="submit" value="Show" />
}
</td>
</tr>
</table>
控制器代码如下:
public ActionResult Index(string Id)
{
using (var context = new Admin_TestEntities())
{
var data = context.Leave_GetDetails(Id).ToList();
return View(data.AsEnumerable().ToList());
}
}
**已编辑**
根据建议,我更改了代码,如下所示,它正在工作:
@using (Html.BeginForm("Index", "Home", FormMethod.Post))
{
@Html.DropDownList("Id", listItems)
<input type="submit" value="Show" />
}
发布于 2015-04-27 15:15:19
你可以这样做:
[Post]
public ActionResult Index(string fromList)
{
...
}
该视图可能如下所示:
<div>
@Html.BeginForm("Index", "Home", FormMethod.Post)
{
@Html.DropDownListFor(model => model.LeaveType1, listItems, "-- Select Status --")
<input type="submit" />
}
</div>
https://stackoverflow.com/questions/29889165
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