如何在Java中创建一个新的zip文件并向其中添加一个包含大量文件的目录？
我正在尝试将文件的目录添加到压缩包中。该目录大约有150个文件。在几个5-75个文件中，我不断收到崩溃并显示错误消息"The process cannot access the file because it is being used by another process."
我尝试了延迟，这可能有帮助，但肯定不能解决错误。
使用来自：Is it possible to create a NEW zip file using the java FileSystem?的代码
final File folder = new File("C:/myDir/img");
for (final File fileEntry : folder.listFiles()) {
if (fileEntry.isDirectory()) {
continue;
}
else {
String filename = fileEntry.getName();
String toBeAddedName = "C:/myDir/img/" + filename;
Path toBeAdded = FileSystems.getDefault().getPath(toBeAddedName).toAbsolutePath();
createZip(zipLocation, toBeAdded, "./" + filename);
System.out.println("Added file " + ++count);
//Delay because 'file in use' bug
try { Thread.sleep(1000); } //1secs
catch (InterruptedException e) {}
}
}
public static void createZip(Path zipLocation, Path toBeAdded, String internalPath) throws Throwable {
Map<String, String> env = new HashMap<String, String>();
//Check if file exists.
env.put("create", String.valueOf(Files.notExists(zipLocation)));
//Use a zip filesystem URI
URI fileUri = zipLocation.toUri(); //Here
URI zipUri = new URI("jar:" + fileUri.getScheme(), fileUri.getPath(), null);
System.out.println(zipUri);
//URI uri = URI.create("jar:file:"+zipLocation); //Here creates the zip
//Try with resource
try (FileSystem zipfs = FileSystems.newFileSystem(zipUri, env)) {
//Create internal path in the zipfs
Path internalTargetPath = zipfs.getPath(internalPath);
//Create parent dir
Files.createDirectories(internalTargetPath.getParent());
//Copy a file into the zip file
Files.copy(toBeAdded, internalTargetPath, StandardCopyOption.REPLACE_EXISTING);
}
}回答 1
Stack Overflow用户
发布于 2019-06-20 03:14:03
我不能保证这就是您问题的原因，但是您的代码以一种奇怪的方式(至少是低效的方式)将文件压缩为ZIP文件。具体地说，您将为每个要压缩的文件打开一个新的FileSystem。我假设你是这样做的，因为你链接的Q&A就是这样做的。但是，that answer只压缩一个文件，而您希望同时压缩多个文件。您应该在压缩目录的整个过程中保持FileSystem处于打开状态。
public static void compress(Path directory, int depth, Path zipArchiveFile) throws IOException {
var uri = URI.create("jar:" + zipArchiveFile.toUri());
var env = Map.of("create", Boolean.toString(Files.notExists(zipArchiveFile, NOFOLLOW_LINKS)));
try (var fs = FileSystems.newFileSystem(uri, env)) {
Files.walkFileTree(directory, Set.of(), depth, new SimpleFileVisitor<>() {
private final Path archiveRoot = fs.getRootDirectories().iterator().next();
@Override
public FileVisitResult preVisitDirectory(Path dir, BasicFileAttributes attrs) throws IOException {
// Don't include the directory itself
if (!directory.equals(dir)) {
Files.createDirectory(resolveDestination(dir));
}
return FileVisitResult.CONTINUE;
}
@Override
public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) throws IOException {
Files.copy(file, resolveDestination(file), REPLACE_EXISTING);
return FileVisitResult.CONTINUE;
}
private Path resolveDestination(Path path) {
/*
* Use Path#resolve(String) instead of Path#resolve(Path). I couldn't find where the
* documentation mentions this, but at least three implementations will throw a
* ProviderMismatchException if #resolve(Path) is invoked with a Path argument that
* belongs to a different provider (i.e. if the implementation types don't match).
*
* Note: Those three implementations, at least in OpenJDK 12.0.1, are the JRT, ZIP/JAR,
* and Windows file system providers (I don't have access to Linux's or Mac's provider
* source currently).
*/
return archiveRoot.resolve(directory.relativize(path).toString());
}
});
}
}注意： depth参数的用法与maxDepth在Files#walkFileTree中的用法完全相同(https://docs.oracle.com/en/java/javase/12/docs/api/java.base/java/nio/file/Files.html#walkFileTree(java.nio.file.Path,java.util.Set,int,java.nio.file.FileVisitor%29)
注意：如果你只关心目录本身的文件(也就是不想递归遍历文件树)，那么你可以使用。使用完the_ Stream后，不要忘记关闭它。
可能是您反复打开和关闭FileSystem导致了您的问题，在这种情况下，上述方法应该可以解决问题。
https://stackoverflow.com/questions/56655156
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