假设我有一张地图:
<map name="externalIds" table="album_external_ids">
<key column="album_id" not-null="true"/>
<map-key-many-to-many class="Major" column="major_id"/>
<element column="external_id" type="string" not-null="true"/>
</map>
如何创建一个HQL,意思是“选择映射关键字的id == :foo和映射值==:bar的实体”?
我可以使用select album from Album album join album.externalIds ids
加入它,但是我如何引用it的键和值呢?ids.key.id = :foo和ids.value = :bar不起作用,hibernate文档对此主题保持沉默。
天真的方法不起作用:
select album
from Album album
join album.externalIds externalId
where index(externalId).id = :foo and externalId = :bar
和
select album
from Album album
join album.externalIds externalId
join index(externalId) major
where major.id = :foo and externalId = :bar
发布于 2010-12-03 23:19:17
我认为您的查询应该如下所示:
select album from Album album where album.externalIds['foo'] = 'bar'
希望这能有所帮助,
文森特·吉古埃尔
https://stackoverflow.com/questions/3020599
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