blocks|key|1360222|text|FileUtils有iterateFiles和listFiles方法。试一试。(来自commons-io)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1360223|编辑:您可以对不同方法的基准进行check+here。commons-io方法似乎很慢，所以选择一些更快的from+here+(如果重要的话)|1360224|entityMap|0|LINK|mutability|MUTABLE|url|https://commons.apache.org/proper/commons-io/javadocs/api-2.5/org/apache/commons/io/FileUtils.html|1|https://commons.apache.org/proper/commons-io/javadocs/api-2.5/org/apache/commons/io/FileUtils.html#iterateFiles(java.io.File,%2520org.apache.commons.io.filefilter.IOFileFilter,%2520org.apache.commons.io.filefilter.IOFileFilter)|2|https://commons.apache.org/proper/commons-io/javadocs/api-2.5/org/apache/commons/io/FileUtils.html#listFiles(java.io.File,%2520org.apache.commons.io.filefilter.IOFileFilter,%2520org.apache.commons.io.filefilter.IOFileFilter)|3|http://commons.apache.org/proper/commons-io/|4|https://github.com/brettryan/io-recurse-tests|5|https://github.com/brettryan/io-recurse-tests/blob/master/src/test/java/com/drunkendev/io/recurse/tests/RecursionTest.java^0|A|C|N|9|0|9|0|A|C|1|N|9|2|16|A|3|0|G|A|4|1H|9|5|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]|$9|17|A|18|1|19]|$9|1A|A|1B|1|1C]|$9|1D|A|1E|1|1F]]|E|$]]|$1|F|3|G|5|6|7|1G|8|@]|D|@$9|1H|A|1I|1|1J]|$9|1K|A|1L|1|1M]]|E|$]]|$1|H|3|-4|5|6|7|1N|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]|P|$5|K|L|M|E|$N|Q]]|R|$5|K|L|M|E|$N|S]]|T|$5|K|L|M|E|$N|U]]|V|$5|K|L|M|E|$N|W]]|X|$5|K|L|M|E|$N|Y]]]]

<a href="https://commons.apache.org/proper/commons-io/javadocs/api-2.5/org/apache/commons/io/FileUtils.html" rel="noreferrer">FileUtils</a> have <a href="https://commons.apache.org/proper/commons-io/javadocs/api-2.5/org/apache/commons/io/FileUtils.html#iterateFiles(java.io.File,%20org.apache.commons.io.filefilter.IOFileFilter,%20org.apache.commons.io.filefilter.IOFileFilter)" rel="noreferrer"><code>iterateFiles</code></a> and <a href="https://commons.apache.org/proper/commons-io/javadocs/api-2.5/org/apache/commons/io/FileUtils.html#listFiles(java.io.File,%20org.apache.commons.io.filefilter.IOFileFilter,%20org.apache.commons.io.filefilter.IOFileFilter)" rel="noreferrer"><code>listFiles</code></a> methods. Give them a try. (from <a href="http://commons.apache.org/proper/commons-io/" rel="noreferrer">commons-io</a>)

Edit: You can <a href="https://github.com/brettryan/io-recurse-tests" rel="noreferrer">check here</a> for a benchmark of different approaches. It seems that the commons-io approach is slow, so pick some of the faster ones <a href="https://github.com/brettryan/io-recurse-tests/blob/master/src/test/java/com/drunkendev/io/recurse/tests/RecursionTest.java" rel="noreferrer">from here</a> (if it matters)

blocks|key|1145299|text|//准备运行|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1145300|import+java.io.File;

public+class+Filewalker+{

++++public+void+walk(+String+path+)+{

++++++++File+root+=+new+File(+path+);
++++++++File[]+list+=+root.listFiles();

++++++++if+(list+==+null)+return;

++++++++for+(+File+f+:+list+)+{
++++++++++++if+(+f.isDirectory()+)+{
++++++++++++++++walk(+f.getAbsolutePath()+);
++++++++++++++++System.out.println(+"Dir:"+%2B+f.getAbsoluteFile()+);
++++++++++++}
++++++++++++else+{
++++++++++++++++System.out.println(+"File:"+%2B+f.getAbsoluteFile()+);
++++++++++++}
++++++++}
++++}

++++public+static+void+main(String[]+args)+{
++++++++Filewalker+fw+=+new+Filewalker();
++++++++fw.walk("c:\\"+);
++++}

}|code-block|syntax|javascript|1145301|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

// Ready to run

<pre><code>import java.io.File;

public class Filewalker {

 public void walk( String path ) {

 File root = new File( path );
 File[] list = root.listFiles();

 if (list == null) return;

 for ( File f : list ) {
 if ( f.isDirectory() ) {
 walk( f.getAbsolutePath() );
 System.out.println( "Dir:" + f.getAbsoluteFile() );
 }
 else {
 System.out.println( "File:" + f.getAbsoluteFile() );
 }
 }
 }

 public static void main(String[] args) {
 Filewalker fw = new Filewalker();
 fw.walk("c:\\" );
 }

}
</code></pre>

blocks|key|1145443|text|不需要外部库。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1145444|返回一个Collection，这样您就可以在调用后对它做任何想做的事情。|1145445|public+static+Collection<File>+listFileTree(File+dir)+{
++++Set<File>+fileTree+=+new+HashSet<File>();
++++if(dir==null%7C%7Cdir.listFiles()==null){
++++++++return+fileTree;
++++}
++++for+(File+entry+:+dir.listFiles())+{
++++++++if+(entry.isFile())+fileTree.add(entry);
++++++++else+fileTree.addAll(listFileTree(entry));
++++}
++++return+fileTree;
}|code-block|syntax|javascript|1145446|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

No external libraries needed.
 Returns a Collection so you can do whatever you want with it after the call.

<pre><code>public static Collection&lt;File&gt; listFileTree(File dir) {
 Set&lt;File&gt; fileTree = new HashSet&lt;File&gt;();
 if(dir==null||dir.listFiles()==null){
 return fileTree;
 }
 for (File entry : dir.listFiles()) {
 if (entry.isFile()) fileTree.add(entry);
 else fileTree.addAll(listFileTree(entry));
 }
 return fileTree;
}
</code></pre>

blocks|key|1145279|text|我会这样说：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1145280|public+void+list(File+file)+{
++++System.out.println(file.getName());
++++File[]+children+=+file.listFiles();
++++for+(File+child+:+children)+{
++++++++list(child);
++++}
}|code-block|syntax|javascript|1145281|System.out.println只是用来指示对该文件执行某些操作。没有必要区分文件和目录，因为一个普通的文件只有零子目录。|1145282|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I would go with something like: 

<pre><code>public void list(File file) {
 System.out.println(file.getName());
 File[] children = file.listFiles();
 for (File child : children) {
 list(child);
 }
}
</code></pre>

The System.out.println is just there to indicate to do something with the file. there is no need to differentiate between files and directories, since a normal file will simply have zero children.

blocks|key|1145412|text|对于这种简单的遍历，我更喜欢使用队列而不是递归：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1145413|List<File>+allFiles+=+new+ArrayList<File>();
Queue<File>+dirs+=+new+LinkedList<File>();
dirs.add(new+File("/start/dir/"));
while+(!dirs.isEmpty())+{
++for+(File+f+:+dirs.poll().listFiles())+{
++++if+(f.isDirectory())+{
++++++dirs.add(f);
++++}+else+if+(f.isFile())+{
++++++allFiles.add(f);
++++}
++}
}|code-block|syntax|javascript|1145414|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I prefer using a queue over recursion for this kind of simple traversion:

<pre><code>List&lt;File&gt; allFiles = new ArrayList&lt;File&gt;();
Queue&lt;File&gt; dirs = new LinkedList&lt;File&gt;();
dirs.add(new File("/start/dir/"));
while (!dirs.isEmpty()) {
 for (File f : dirs.poll().listFiles()) {
 if (f.isDirectory()) {
 dirs.add(f);
 } else if (f.isFile()) {
 allFiles.add(f);
 }
 }
}
</code></pre>

blocks|key|1360258|text|只需使用简单的递归自己编写即可：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1360259|public+List<File>+addFiles(List<File>+files,+File+dir)
{
++++if+(files+==+null)
++++++++files+=+new+LinkedList<File>();

++++if+(!dir.isDirectory())
++++{
++++++++files.add(dir);
++++++++return+files;
++++}

++++for+(File+file+:+dir.listFiles())
++++++++addFiles(files,+file);
++++return+files;
}|code-block|syntax|javascript|1360260|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

just write it yourself using simple recursion:

<pre><code>public List&lt;File&gt; addFiles(List&lt;File&gt; files, File dir)
{
 if (files == null)
 files = new LinkedList&lt;File&gt;();

 if (!dir.isDirectory())
 {
 files.add(dir);
 return files;
 }

 for (File file : dir.listFiles())
 addFiles(files, file);
 return files;
}
</code></pre>

blocks|key|1145613|text|在Java+7中，您可以使用以下类：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1145614|import+java.io.IOException;
import+java.nio.file.FileVisitResult;
import+java.nio.file.Files;
import+java.nio.file.Path;
import+java.nio.file.Paths;
import+java.nio.file.SimpleFileVisitor;
import+java.nio.file.attribute.BasicFileAttributes;

public+class+MyFileIterator+extends+SimpleFileVisitor<Path>
{
++++public+MyFileIterator(String+path)+throws+Exception
++++{
++++++++Files.walkFileTree(Paths.get(path),+this);
++++}

++++@Override
++++public+FileVisitResult+visitFile(Path+file,
++++++++++++BasicFileAttributes+attributes)+throws+IOException
++++{
++++++++System.out.println("File:+"+%2B+file);
++++++++return+FileVisitResult.CONTINUE;
++++}

++++@Override
++++public+FileVisitResult+preVisitDirectory(Path+dir,
++++++++++++BasicFileAttributes+attributes)+throws+IOException
++++{
++++++++System.out.println("Dir:+"+%2B+dir);
++++++++return+FileVisitResult.CONTINUE;
++++}
}|code-block|syntax|javascript|1145615|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

With Java 7 you can use the following class:

<pre><code>import java.io.IOException;
import java.nio.file.FileVisitResult;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.nio.file.SimpleFileVisitor;
import java.nio.file.attribute.BasicFileAttributes;

public class MyFileIterator extends SimpleFileVisitor&lt;Path&gt;
{
 public MyFileIterator(String path) throws Exception
 {
 Files.walkFileTree(Paths.get(path), this);
 }

 @Override
 public FileVisitResult visitFile(Path file,
 BasicFileAttributes attributes) throws IOException
 {
 System.out.println("File: " + file);
 return FileVisitResult.CONTINUE;
 }

 @Override
 public FileVisitResult preVisitDirectory(Path dir,
 BasicFileAttributes attributes) throws IOException
 {
 System.out.println("Dir: " + dir);
 return FileVisitResult.CONTINUE;
 }
}
</code></pre>

blocks|key|1360198|text|我认为这应该可以完成以下工作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1360199|File+dir+=+new+File(dirname);
String[]+files+=+dir.list();|code-block|syntax|javascript|1360200|这样你就有了文件和目录。现在使用递归，并对dirs执行相同的操作(File类具有isDirectory()方法)。|offset|length|style|CODE|1360201|entityMap^0|0|0|X|4|14|D|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

I think this should do the work:

<pre><code>File dir = new File(dirname);
String[] files = dir.list();
</code></pre>

This way you have files and dirs. Now use recursion and do the same for dirs (<code>File</code> class has <code>isDirectory()</code> method).

blocks|key|1360631|text|在Java+8中，我们现在可以使用Files实用程序遍历文件树。非常简单。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1360632|Files.walk(root.toPath())
++++++.filter(path+->+!Files.isDirectory(path))
++++++.forEach(path+->+System.out.println(path));|code-block|syntax|javascript|1360633|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In Java 8, we can now use the Files utility to walk a file tree. Very simple.

<pre><code>Files.walk(root.toPath())
 .filter(path -&gt; !Files.isDirectory(path))
 .forEach(path -&gt; System.out.println(path));
</code></pre>

blocks|key|1360400|text|除了递归遍历之外，还可以使用基于Visitor的方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1360401|下面的代码是使用基于访问者的方法进行traversal.It的，程序的输入是要遍历的根目录。|1360402|public+interface+Visitor+{
++++void+visit(DirElement+d);
++++void+visit(FileElement+f);
}

public+abstract+class+Element+{
++++protected+File+rootPath;
++++abstract+void+accept(Visitor+v);

++++@Override
++++public+String+toString()+{
++++++++return+rootPath.getAbsolutePath();
++++}
}

public+class+FileElement+extends+Element+{
++++FileElement(final+String+path)+{
++++++++rootPath+=+new+File(path);
++++}

++++@Override
++++void+accept(final+Visitor+v)+{
++++++++v.visit(this);
++++}
}

public+class+DirElement+extends+Element+implements+Iterable<Element>+{
++++private+final+List<Element>+elemList;
++++DirElement(final+String+path)+{
++++++++elemList+=+new+ArrayList<Element>();
++++++++rootPath+=+new+File(path);
++++++++for+(File+f+:+rootPath.listFiles())+{
++++++++++++if+(f.isDirectory())+{
++++++++++++++++elemList.add(new+DirElement(f.getAbsolutePath()));
++++++++++++}+else+if+(f.isFile())+{
++++++++++++++++elemList.add(new+FileElement(f.getAbsolutePath()));
++++++++++++}
++++++++}
++++}

++++@Override
++++void+accept(final+Visitor+v)+{
++++++++v.visit(this);
++++}

++++public+Iterator<Element>+iterator()+{
++++++++return+elemList.iterator();
++++}
}

public+class+ElementWalker+{
++++private+final+String+rootDir;
++++ElementWalker(final+String+dir)+{
++++++++rootDir+=+dir;
++++}

++++private+void+traverse()+{
++++++++Element+d+=+new+DirElement(rootDir);
++++++++d.accept(new+Walker());
++++}

++++public+static+void+main(final+String[]+args)+{
++++++++ElementWalker+t+=+new+ElementWalker("C:\\temp");
++++++++t.traverse();
++++}

++++private+class+Walker+implements+Visitor+{
++++++++public+void+visit(final+DirElement+d)+{
++++++++++++System.out.println(d);
++++++++++++for(Element+e:d)+{
++++++++++++++++e.accept(this);
++++++++++++}
++++++++}

++++++++public+void+visit(final+FileElement+f)+{
++++++++++++System.out.println(f);
++++++++}
++++}
}|code-block|syntax|javascript|1360403|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Apart from the recursive traversal one can use a Visitor based approach as well.

Below code is uses Visitor based approach for the traversal.It is expected that the input to the program is the root directory to traverse.

<pre><code>public interface Visitor {
 void visit(DirElement d);
 void visit(FileElement f);
}

public abstract class Element {
 protected File rootPath;
 abstract void accept(Visitor v);

 @Override
 public String toString() {
 return rootPath.getAbsolutePath();
 }
}

public class FileElement extends Element {
 FileElement(final String path) {
 rootPath = new File(path);
 }

 @Override
 void accept(final Visitor v) {
 v.visit(this);
 }
}

public class DirElement extends Element implements Iterable&lt;Element&gt; {
 private final List&lt;Element&gt; elemList;
 DirElement(final String path) {
 elemList = new ArrayList&lt;Element&gt;();
 rootPath = new File(path);
 for (File f : rootPath.listFiles()) {
 if (f.isDirectory()) {
 elemList.add(new DirElement(f.getAbsolutePath()));
 } else if (f.isFile()) {
 elemList.add(new FileElement(f.getAbsolutePath()));
 }
 }
 }

 @Override
 void accept(final Visitor v) {
 v.visit(this);
 }

 public Iterator&lt;Element&gt; iterator() {
 return elemList.iterator();
 }
}

public class ElementWalker {
 private final String rootDir;
 ElementWalker(final String dir) {
 rootDir = dir;
 }

 private void traverse() {
 Element d = new DirElement(rootDir);
 d.accept(new Walker());
 }

 public static void main(final String[] args) {
 ElementWalker t = new ElementWalker("C:\\temp");
 t.traverse();
 }

 private class Walker implements Visitor {
 public void visit(final DirElement d) {
 System.out.println(d);
 for(Element e:d) {
 e.accept(this);
 }
 }

 public void visit(final FileElement f) {
 System.out.println(f);
 }
 }
}
</code></pre>

blocks|key|1145668|text|您可以使用下面的代码来递归地获取特定文件夹或目录的文件列表。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1145669|public+static+void+main(String+args[])+{

++++++++recusiveList("D:");

++++}

++++public+static+void+recursiveList(String+path)+{

++++++++File+f+=+new+File(path);
++++++++File[]+fl+=+f.listFiles();
++++++++for+(int+i+=+0;+i+<+fl.length;+i%2B%2B)+{
++++++++++++if+(fl[i].isDirectory()+&&+!fl[i].isHidden())+{
++++++++++++++++System.out.println(fl[i].getAbsolutePath());
++++++++++++++++recusiveList(fl[i].getAbsolutePath());
++++++++++++}+else+{
++++++++++++++++System.out.println(fl[i].getName());
++++++++++++}
++++++++}
++++}|code-block|syntax|javascript|1145670|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use below code to get a list of files of specific folder or directory recursively.

<pre><code>public static void main(String args[]) {

 recusiveList("D:");

 }

 public static void recursiveList(String path) {

 File f = new File(path);
 File[] fl = f.listFiles();
 for (int i = 0; i &lt; fl.length; i++) {
 if (fl[i].isDirectory() &amp;&amp; !fl[i].isHidden()) {
 System.out.println(fl[i].getAbsolutePath());
 recusiveList(fl[i].getAbsolutePath());
 } else {
 System.out.println(fl[i].getName());
 }
 }
 }
</code></pre>

blocks|key|1145865|text|我想出了一个递归打印所有文件/文件名的方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1145866|private+static+void+printAllFiles(String+filePath,File+folder)+{
++++if(filePath==null)+{
++++++++return;
++++}
++++File[]+files+=+folder.listFiles();
++++for(File+element+:+files)+{
++++++++if(element.isDirectory())+{
++++++++++++printAllFiles(filePath,element);
++++++++}+else+{
++++++++++++System.out.println("+FileName+"%2B+element.getName());
++++++++}
++++}
}|code-block|syntax|javascript|1145867|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I came up with this for printing all the files/file names recursively.

<pre><code>private static void printAllFiles(String filePath,File folder) {
 if(filePath==null) {
 return;
 }
 File[] files = folder.listFiles();
 for(File element : files) {
 if(element.isDirectory()) {
 printAllFiles(filePath,element);
 } else {
 System.out.println(" FileName "+ element.getName());
 }
 }
}
</code></pre>

blocks|key|1145484|text|具有单个列表的非递归BFS+(具体示例是搜索*.eml文件)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1145485|++++final+FileFilter+filter+=+new+FileFilter()+{
++++++++@Override
++++++++public+boolean+accept(File+file)+{
++++++++++++return+file.isDirectory()+%7C%7C+file.getName().endsWith(".eml");
++++++++}
++++};

++++//+BFS+recursive+search
++++List<File>+queue+=+new+LinkedList<File>();
++++queue.addAll(Arrays.asList(dir.listFiles(filter)));

++++for+(ListIterator<File>+itr+=+queue.listIterator();+itr.hasNext();)+{
++++++++File+file+=+itr.next();
++++++++if+(file.isDirectory())+{
++++++++++++itr.remove();
++++++++++++for+(File+f:+file.listFiles(filter))+itr.add(f);
++++++++}
++++}|code-block|syntax|javascript|1145486|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Non-recursive BFS with a single list (particular example is searching for *.eml files):

<pre><code> final FileFilter filter = new FileFilter() {
 @Override
 public boolean accept(File file) {
 return file.isDirectory() || file.getName().endsWith(".eml");
 }
 };

 // BFS recursive search
 List&lt;File&gt; queue = new LinkedList&lt;File&gt;();
 queue.addAll(Arrays.asList(dir.listFiles(filter)));

 for (ListIterator&lt;File&gt; itr = queue.listIterator(); itr.hasNext();) {
 File file = itr.next();
 if (file.isDirectory()) {
 itr.remove();
 for (File f: file.listFiles(filter)) itr.add(f);
 }
 }
</code></pre>

blocks|key|1360703|text|我的版本(当然，我可以使用Java+8中内置的walk+;-+)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1360704|public+static+List<File>+findFilesIn(File+rootDir,+Predicate<File>+predicate)+{
++++++++ArrayList<File>+collected+=+new+ArrayList<>();
++++++++walk(rootDir,+predicate,+collected);
++++++++return+collected;
++++}

++++private+static+void+walk(File+dir,+Predicate<File>+filterFunction,+List<File>+collected)+{
++++++++Stream.of(listOnlyWhenDirectory(dir))
++++++++++++++++.forEach(file+->+walk(file,+filterFunction,+addAndReturn(collected,+file,+filterFunction)));
++++}

++++private+static+File[]+listOnlyWhenDirectory(File+dir)+{
++++++++return+dir.isDirectory()+?+dir.listFiles()+:+new+File[]{};
++++}

++++private+static+List<File>+addAndReturn(List<File>+files,+File+toAdd,+Predicate<File>+filterFunction)+{
++++++++if+(filterFunction.test(toAdd))+{
++++++++++++files.add(toAdd);
++++++++}
++++++++return+files;
++++}|code-block|syntax|javascript|1360705|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

My version (of course I could have used the built in walk in Java 8 ;-) ):

<pre><code>public static List&lt;File&gt; findFilesIn(File rootDir, Predicate&lt;File&gt; predicate) {
 ArrayList&lt;File&gt; collected = new ArrayList&lt;&gt;();
 walk(rootDir, predicate, collected);
 return collected;
 }

 private static void walk(File dir, Predicate&lt;File&gt; filterFunction, List&lt;File&gt; collected) {
 Stream.of(listOnlyWhenDirectory(dir))
 .forEach(file -&gt; walk(file, filterFunction, addAndReturn(collected, file, filterFunction)));
 }

 private static File[] listOnlyWhenDirectory(File dir) {
 return dir.isDirectory() ? dir.listFiles() : new File[]{};
 }

 private static List&lt;File&gt; addAndReturn(List&lt;File&gt; files, File toAdd, Predicate&lt;File&gt; filterFunction) {
 if (filterFunction.test(toAdd)) {
 files.add(toAdd);
 }
 return files;
 }
</code></pre>

blocks|key|1360826|text|这里是一个使用recursion的简单但完美的解决方案|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1360827|public+static+List<Path>+listFiles(String+rootDirectory)
{
++++List<Path>+files+=+new+ArrayList<>();
++++listFiles(rootDirectory,+files);

++++return+files;
}

private+static+void+listFiles(String+path,+List<Path>+collectedFiles)
{
++++File+root+=+new+File(path);
++++File[]+files+=+root.listFiles();

++++if+(files+==+null)
++++{
++++++++return;
++++}

++++for+(File+file+:+files)
++++{
++++++++if+(file.isDirectory())
++++++++{
++++++++++++listFiles(file.getAbsolutePath(),+collectedFiles);
++++++++}+else
++++++++{
++++++++++++collectedFiles.add(file.toPath());
++++++++}
++++}
}|code-block|syntax|javascript|1360828|entityMap^0|7|9|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Here a simple but perfectly working solution using <code>recursion</code>:

<pre><code>public static List&lt;Path&gt; listFiles(String rootDirectory)
{
 List&lt;Path&gt; files = new ArrayList&lt;&gt;();
 listFiles(rootDirectory, files);

 return files;
}

private static void listFiles(String path, List&lt;Path&gt; collectedFiles)
{
 File root = new File(path);
 File[] files = root.listFiles();

 if (files == null)
 {
 return;
 }

 for (File file : files)
 {
 if (file.isDirectory())
 {
 listFiles(file.getAbsolutePath(), collectedFiles);
 } else
 {
 collectedFiles.add(file.toPath());
 }
 }
}
</code></pre>

blocks|key|1145800|text|++++private+void+fillFilesRecursively(File+file,+List<File>+resultFiles)+{
++++++++if+(file.isFile())+{
++++++++++++resultFiles.add(file);
++++++++}+else+{
++++++++++++for+(File+child+:+file.listFiles())+{
++++++++++++++++fillFilesRecursively(child,+resultFiles);
++++++++++++}
++++++++}
++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1145801|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> private void fillFilesRecursively(File file, List&lt;File&gt; resultFiles) {
 if (file.isFile()) {
 resultFiles.add(file);
 } else {
 for (File child : file.listFiles()) {
 fillFilesRecursively(child, resultFiles);
 }
 }
 }
</code></pre>

blocks|key|1360973|text|Kotlin为此提供了FileTreeWalk。例如：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1360974|dataDir.walkTopDown().filter+{+!it.isDirectory+}.joinToString("\n")+{
+++"${it.toRelativeString(dataDir)}:+${it.length()}"
}|code-block|syntax|javascript|1360975|将生成给定根目录下所有非目录文件的文本列表，每行一个文件，其中包含相对于根目录的路径和长度。|1360976|entityMap|0|LINK|mutability|MUTABLE|url|https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.io/-file-tree-walk/index.html^0|B|C|B|C|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|11|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

Kotlin has <a href="https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.io/-file-tree-walk/index.html" rel="nofollow noreferrer"><code>FileTreeWalk</code></a> for this purpose. For example:

<pre><code>dataDir.walkTopDown().filter { !it.isDirectory }.joinToString("\n") {
 "${it.toRelativeString(dataDir)}: ${it.length()}"
}
</code></pre>

Will produce a text list of all the non-directory files under a given root, one file per line with the path relative to the root and length.

blocks|key|1145966|text|accepted+answer很棒，但是当你想在lambda中进行IO时，它就失效了。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1145967|如果您的操作声明了IOExceptions，下面是您可以做的事情。|1145968|您可以将过滤后的流视为Iterable，然后在常规的for-each循环中执行操作。这样，您就不必在lambda中处理异常了。|style|CODE|1145969|try+(Stream<Path>+pathStream+=+Files.walk(Paths.get(path))
++++++++.filter(Files::isRegularFile))+{

++++for+(Path+file+:+(Iterable<Path>)+pathStream::iterator)+{
++++++++//+something+that+throws+IOException
++++++++Files.copy(file,+System.out);
++++}
}|code-block|syntax|javascript|1145970|在这里找到了这个诀窍：https://stackoverflow.com/a/32668807/1207791|1145971|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/24006711/1207791|1|https://stackoverflow.com/a/32668807/1207791^0|0|F|0|0|0|B|8|0|0|B|18|1|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|6|7|14|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|15|8|@$A|16|B|17|H|I]]|9|@]|C|$]]|$1|J|3|K|5|L|7|18|8|@]|9|@]|C|$M|N]]|$1|O|3|P|5|6|7|19|8|@]|9|@$A|1A|B|1B|1|1C]]|C|$]]|$1|Q|3|-4|5|6|7|1D|8|@]|9|@]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]|Y|$5|T|U|V|C|$W|Z]]]]

The <a href="https://stackoverflow.com/a/24006711/1207791">accepted answer</a> is great, however it breaks down when you want to do IO inside the lambda.

Here is what you can do if your action declares IOExceptions.

You can treat the filtered stream as an <code>Iterable</code>, and then do your action in a regular for-each loop. This way, you don't have to handle exceptions inside a lambda.

<pre class="lang-java prettyprint-override"><code>try (Stream&lt;Path&gt; pathStream = Files.walk(Paths.get(path))
 .filter(Files::isRegularFile)) {

 for (Path file : (Iterable&lt;Path&gt;) pathStream::iterator) {
 // something that throws IOException
 Files.copy(file, System.out);
 }
}
</code></pre>

Found that trick here: <a href="https://stackoverflow.com/a/32668807/1207791">https://stackoverflow.com/a/32668807/1207791</a>

blocks|key|1361048|text|另一种方法是，即使有人已经提供了Java+8+walk，也可以这样做。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1361049|这个文件将递归地为您提供所有文件|1361050|++private+Stream<File>+files(File+file)+{
++++return+file.isDirectory()
++++++++++++?+Arrays.stream(file.listFiles()).flatMap(this::files)
++++++++++++:+Stream.of(file);
}|code-block|syntax|javascript|1361051|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Another way you can do even if someone already provide Java 8 walk.

This one will provide you all files recursively

<pre><code> private Stream&lt;File&gt; files(File file) {
 return file.isDirectory()
 ? Arrays.stream(file.listFiles()).flatMap(this::files)
 : Stream.of(file);
}
</code></pre>

blocks|key|1146073|text|public+static+String+getExten(String+path)+{
++++int+i+=+path.lastIndexOf('.');
++++if+(i+>+0)+{
+++++++return+path.substring(i);
++++}
++++else+return+"";
}
public+static+List<String>+GetAllFiles(String+path,+List<String>fileList){
++++File+file+=+new+File(path);
++++
++++File[]+files+=+file.listFiles();
++++for(File+folder:files)+{
++++++++if(extensions.contains(getExten(folder.getPath())))+{
++++++++++++fileList.add(folder.getPath());
++++++++}
++++}
++++File[]+direcs+=+file.listFiles(File::isDirectory);
++++for(File+dir:direcs)+{
++++++++GetAllFiles(dir.getPath(),fileList);
++++}
++++return+fileList;
++++
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1146074|这是一个简单的递归函数，应该会给出所有的文件。extensions是一个字符串列表，它只包含那些被接受的扩展名。extensions+=+".txt"，".docx“等。|unstyled|1146075|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>public static String getExten(String path) {
 int i = path.lastIndexOf('.');
 if (i &gt; 0) {
 return path.substring(i);
 }
 else return &quot;&quot;;
}
public static List&lt;String&gt; GetAllFiles(String path, List&lt;String&gt;fileList){
 File file = new File(path);
 
 File[] files = file.listFiles();
 for(File folder:files) {
 if(extensions.contains(getExten(folder.getPath()))) {
 fileList.add(folder.getPath());
 }
 }
 File[] direcs = file.listFiles(File::isDirectory);
 for(File dir:direcs) {
 GetAllFiles(dir.getPath(),fileList);
 }
 return fileList;
 
}
</code></pre>
This is a simple recursive function that should give you all the files. extensions is a list of string that contains only those extensions which are accepted. Example extensions = [&quot;.txt&quot;,&quot;.docx&quot;] etc.

blocks|key|1360780|text|示例使用java.nio中的Files.find()在目录递归搜索子目录中输出*.csv文件：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1360781|String+path+=+"C:/Daten/ibiss/ferret/";
++++logger.debug("Path:"+%2B+path);
++++try+(Stream<Path>+fileList+=+Files.find(Paths.get(path),+Integer.MAX_VALUE,
++++++++++++(filePath,+fileAttr)+->+fileAttr.isRegularFile()+&&+filePath.toString().endsWith("csv")))+{
++++++++List<String>+someThingNew+=+fileList.sorted().map(String::valueOf).collect(Collectors.toList());
++++++++for+(String+t+:+someThingNew)+{
++++++++++++t.toString();
++++++++++++logger.debug("Filename:"+%2B+t);
++++++++}

++++}|code-block|syntax|javascript|1360782|发布这个例子，因为我很难理解如何传递Bryan给出的#1例子中的filename参数，在Stream-result上使用foreach+--|1360783|希望这能有所帮助。|1360784|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Example outputs *.csv files in directory recursive searching Subdirectories using Files.find() from java.nio:

<pre><code>String path = "C:/Daten/ibiss/ferret/";
 logger.debug("Path:" + path);
 try (Stream&lt;Path&gt; fileList = Files.find(Paths.get(path), Integer.MAX_VALUE,
 (filePath, fileAttr) -&gt; fileAttr.isRegularFile() &amp;&amp; filePath.toString().endsWith("csv"))) {
 List&lt;String&gt; someThingNew = fileList.sorted().map(String::valueOf).collect(Collectors.toList());
 for (String t : someThingNew) {
 t.toString();
 logger.debug("Filename:" + t);
 }

 }
</code></pre>

Posting this example, as I had trouble understanding howto pass the filename parameter in the #1 example given by Bryan, using foreach on Stream-result - 

Hope this helps.

blocks|key|1146103|text|根据@Michael答案，添加检查listFiles是否返回null|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1146104|static+Stream<File>+files(File+file)+{
++++return+file.isDirectory()
++++++++++++?+Optional.ofNullable(file.listFiles()).map(Stream::of).orElseGet(Stream::empty).flatMap(MainActivity::files)
++++++++++++:+Stream.of(file);
}|code-block|syntax|javascript|1146105|或者使用支持Android5和Android6的Lightweight-Stream-API|offset|length|1146106|static+Stream<File>+files(File+f)+{
++++return+f.isDirectory()+?+Stream.ofNullable(f.listFiles()).flatMap(MainActivity::files)+:+Stream.of(f);
}|1146107|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/aNNiMON/Lightweight-Stream-API^0|0|0|O|M|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]]|A|$]]|$1|K|3|L|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

base on @Michael answer, add check whether listFiles return null
<pre><code>static Stream&lt;File&gt; files(File file) {
 return file.isDirectory()
 ? Optional.ofNullable(file.listFiles()).map(Stream::of).orElseGet(Stream::empty).flatMap(MainActivity::files)
 : Stream.of(file);
}
</code></pre>
or use <a href="https://github.com/aNNiMON/Lightweight-Stream-API" rel="nofollow noreferrer">Lightweight-Stream-API</a>, which support Android5 &amp; Android6
<pre><code>static Stream&lt;File&gt; files(File f) {
 return f.isDirectory() ? Stream.ofNullable(f.listFiles()).flatMap(MainActivity::files) : Stream.of(f);
}
</code></pre>

blocks|key|1361189|text|List<Path>+filePaths+=+Files
++++.find(Paths.get(dir),+Integer.MAX_VALUE,+(filePath,+fileAttr)+->+fileAttr.isRegularFile()+%7C%7C+fileAttr.isDirectory())
++++.collect(Collectors.toList());|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1361190|filePaths将拥有文件和文件夹列表，这些文件和文件夹列表可以迭代并进一步处理。|unstyled|offset|length|style|CODE|1361191|entityMap^0|0|0|9|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre class="lang-java prettyprint-override"><code>List&lt;Path&gt; filePaths = Files
 .find(Paths.get(dir), Integer.MAX_VALUE, (filePath, fileAttr) -&gt; fileAttr.isRegularFile() || fileAttr.isDirectory())
 .collect(Collectors.toList());
</code></pre>
<code>filePaths</code> will have files and folder list which can be iterated and proceed further.

blocks|key|1145524|text|基于stacker的答案。这是一个在JSP中工作的解决方案，没有任何外部库，因此您可以将其放在服务器上的几乎任何位置：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1145525|<!DOCTYPE+html>
<%25@+page+session="false"+%25>
<%25@+page+import="java.util.*"+%25>
<%25@+page+import="java.io.*"+%25>
<%25@+page+contentType="text/html;+charset=UTF-8"+%25>

<%25!
++++public+List<String>+files+=+new+ArrayList<String>();
++++/**
++++++++Fills+files+array+with+all+sub-files.
++++*/
++++public+void+walk(+File+root+)+{
++++++++File[]+list+=+root.listFiles();

++++++++if+(list+==+null)+return;

++++++++for+(+File+f+:+list+)+{
++++++++++++if+(+f.isDirectory()+)+{
++++++++++++++++walk(+f+);
++++++++++++}
++++++++++++else+{
++++++++++++++++files.add(f.getAbsolutePath());
++++++++++++}
++++++++}
++++}
%25>
<%25
++++files.clear();
++++File+jsp+=+new+File(request.getRealPath(request.getServletPath()));
++++File+dir+=+jsp.getParentFile();
++++walk(dir);
++++String+prefixPath+=+dir.getAbsolutePath()+%2B+"/";
%25>|code-block|syntax|javascript|1145526|然后，您只需执行以下操作：|1145527|++++<ul>
++++++++<%25+for+(String+file+:+files)+{+%25>
++++++++++++<%25+if+(file.matches(".%2B\\.(apk%7Cipa%7Cmobileprovision)"))+{+%25>
++++++++++++++++<li><%25=file.replace(prefixPath,+"")%25></li>
++++++++++++<%25+}+%25>
++++++++<%25+}+%25>
++++</ul>|1145528|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Based on stacker answer. Here is a solution working in JSP without any external libraries so you can put it almost anywhere on your server:

<pre><code>&lt;!DOCTYPE html&gt;
&lt;%@ page session="false" %&gt;
&lt;%@ page import="java.util.*" %&gt;
&lt;%@ page import="java.io.*" %&gt;
&lt;%@ page contentType="text/html; charset=UTF-8" %&gt;

&lt;%!
 public List&lt;String&gt; files = new ArrayList&lt;String&gt;();
 /**
 Fills files array with all sub-files.
 */
 public void walk( File root ) {
 File[] list = root.listFiles();

 if (list == null) return;

 for ( File f : list ) {
 if ( f.isDirectory() ) {
 walk( f );
 }
 else {
 files.add(f.getAbsolutePath());
 }
 }
 }
%&gt;
&lt;%
 files.clear();
 File jsp = new File(request.getRealPath(request.getServletPath()));
 File dir = jsp.getParentFile();
 walk(dir);
 String prefixPath = dir.getAbsolutePath() + "/";
%&gt;
</code></pre>

Then you just do something like:

<pre><code> &lt;ul&gt;
 &lt;% for (String file : files) { %&gt;
 &lt;% if (file.matches(".+\\.(apk|ipa|mobileprovision)")) { %&gt;
 &lt;li&gt;&lt;%=file.replace(prefixPath, "")%&gt;&lt;/li&gt;
 &lt;% } %&gt;
 &lt;% } %&gt;
 &lt;/ul&gt;
</code></pre>

blocks|key|1361142|text|import+java.io.File;

public+class+Main+{
++++public+static+void+main(String[]+args)+{
++++++++loopFiles(new+File("C:\\Users\\serge.klimkovitch\\Documents"));
++++}

++++private+static+void+loopFiles(File+element)+{
++++++++if+(element.isDirectory())+{
++++++++++++for+(File+currentFile+:+element.listFiles())+{
++++++++++++++++loopFiles(currentFile);
++++++++++++++++System.out.println(currentFile);
++++++++++++}
++++++++}
++++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1361143|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import java.io.File;

public class Main {
 public static void main(String[] args) {
 loopFiles(new File(&quot;C:\\Users\\serge.klimkovitch\\Documents&quot;));
 }

 private static void loopFiles(File element) {
 if (element.isDirectory()) {
 for (File currentFile : element.listFiles()) {
 loopFiles(currentFile);
 System.out.println(currentFile);
 }
 }
 }
}
</code></pre>

How do I recursively list all files under a directory in Java? Does the framework provide any utility? 

I saw a lot of hacky implementations. But none from the framework or <a href="http://java.sun.com/j2se/1.4.2/docs/api/java/nio/package-summary.html" rel="noreferrer">nio</a>

Recursively list files in Java

如何在Java中递归列出某个目录下的所有文件？这个框架提供了什么实用工具吗？我看到了很多老套的实现。但是没有来自框架或的

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