blocks|key|1710765|text|只要你想在任何字符串中使用Environment.NewLine。举个例子：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1710766|string+text+=+"fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";

text+=+text.Replace("@",+"@"+%2B+System.Environment.NewLine);|code-block|syntax|javascript|1710767|entityMap^0|D|J|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Use <code>Environment.NewLine</code> whenever you want in any string. An example:

<pre><code>string text = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";

text = text.Replace("@", "@" + System.Environment.NewLine);
</code></pre>

blocks|key|1495717|text|您可以在@符号后添加一个新行字符，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1495718|string+newString+=+oldString.Replace("@",+"@\n");++|code-block|syntax|javascript|1495719|您还可以在Environment类中使用NewLine属性(我认为它是环境)。|offset|length|style|CODE|1495720|entityMap^0|0|0|5|B|K|7|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

You can add a new line character after the @ symbol like so: 

<pre><code>string newString = oldString.Replace("@", "@\n"); 
</code></pre>

You can also use the <code>NewLine</code> property in the <code>Environment</code> Class (I think it is Environment).

blocks|key|1495791|text|前面的答案很接近，但是为了满足@符号保持接近的实际要求，您可能希望它是str.Replace("@",+"@"+%2B+System.Environment.NewLine)。这将保留@符号，并为当前平台添加适当的换行符。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1495792|entityMap^0|F|1|Z|1E|2I|1|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|O|8|@]|D|@]|E|$]]]|G|$]]

The previous answers come close, but to meet the actual requirement that the <code>@</code> symbol stay close, you'd want that to be <code>str.Replace("@", "@" + System.Environment.NewLine)</code>. That will keep the <code>@</code> symbol and add the appropriate newline character(s) for the current platform.

blocks|key|1495843|text|然后只需将前面的答案修改为：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1495844|Console.Write(strToProcess.Replace("@",+"@"+%2B+Environment.NewLine));|code-block|syntax|javascript|1495845|如果您不想在文本文件中使用换行符，那么就不要保留它。|1495846|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Then just modify the previous answers to:

<pre><code>Console.Write(strToProcess.Replace("@", "@" + Environment.NewLine));
</code></pre>

If you don't want the newlines in the text file, then don't preserve it.

blocks|key|1710846|text|一个简单的字符串替换就可以完成这项工作。看看下面的示例程序：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1710847|using+System;

namespace+NewLineThingy
{
++++class+Program
++++{
++++++++static+void+Main(string[]+args)
++++++++{
++++++++++++string+str+=+"fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
++++++++++++str+=+str.Replace("@",+"@"+%2B+Environment.NewLine);
++++++++++++Console.WriteLine(str);
++++++++++++Console.ReadKey();
++++++++}
++++}
}|code-block|syntax|javascript|1710848|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

A simple string replace will do the job. Take a look at the example program below:

<pre><code>using System;

namespace NewLineThingy
{
 class Program
 {
 static void Main(string[] args)
 {
 string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
 str = str.Replace("@", "@" + Environment.NewLine);
 Console.WriteLine(str);
 Console.ReadKey();
 }
 }
}
</code></pre>

blocks|key|1711016|text|正如其他人所说的那样，换行符将使你在windows的文本文件中换行。尝试以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1711017|using+System;
using+System.IO;

static+class+Program
{
++++static+void+Main()
++++{
++++++++WriteToFile
++++++++(
++++++++@"C:\test.txt",
++++++++"fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@",
++++++++"@"
++++++++);

++++++++/*
++++++++output+in+test.txt+in+windows+=
++++++++fkdfdsfdflkdkfk@
++++++++dfsdfjk72388389@
++++++++kdkfkdfkkl@
++++++++jkdjkfjd@
++++++++jjjk@+
++++++++*/
++++}

++++public+static+void+WriteToFile(string+filename,+string+text,+string+newLineDelim)
++++{
++++++++bool+equal+=+Environment.NewLine+==+"\r\n";

++++++++//Environment.NewLine+==+\r\n+=+True
++++++++Console.WriteLine("Environment.NewLine+==+\\r\\n+=+{0}",+equal);

++++++++//replace+newLineDelim+with+newLineDelim+%2B+a+new+line
++++++++//trim+to+get+rid+of+any+new+lines+chars+at+the+end+of+the+file
++++++++string+filetext+=+text.Replace(newLineDelim,+newLineDelim+%2B+Environment.NewLine).Trim();

++++++++using+(StreamWriter+sw+=+new+StreamWriter(File.OpenWrite(filename)))
++++++++{
++++++++++++sw.Write(filetext);
++++++++}
++++}
}|code-block|syntax|javascript|1711018|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

as others have said new line char will give you a new line in a text file in windows.
try the following:

<pre><code>using System;
using System.IO;

static class Program
{
 static void Main()
 {
 WriteToFile
 (
 @"C:\test.txt",
 "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@",
 "@"
 );

 /*
 output in test.txt in windows =
 fkdfdsfdflkdkfk@
 dfsdfjk72388389@
 kdkfkdfkkl@
 jkdjkfjd@
 jjjk@ 
 */
 }

 public static void WriteToFile(string filename, string text, string newLineDelim)
 {
 bool equal = Environment.NewLine == "\r\n";

 //Environment.NewLine == \r\n = True
 Console.WriteLine("Environment.NewLine == \\r\\n = {0}", equal);

 //replace newLineDelim with newLineDelim + a new line
 //trim to get rid of any new lines chars at the end of the file
 string filetext = text.Replace(newLineDelim, newLineDelim + Environment.NewLine).Trim();

 using (StreamWriter sw = new StreamWriter(File.OpenWrite(filename)))
 {
 sw.Write(filetext);
 }
 }
}
</code></pre>

blocks|key|1496103|text|string+strToProcess+=+"fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
var+result+=+strToProcess.Replace("@",+"@+\r\n");
Console.WriteLine(result);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1496104|Output|unstyled|offset|length|1496105|entityMap|0|LINK|mutability|MUTABLE|url|https://i.stack.imgur.com/TAIFU.png^0|0|0|6|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
var result = strToProcess.Replace("@", "@ \r\n");
Console.WriteLine(result);
</code></pre>

<a href="https://i.stack.imgur.com/TAIFU.png" rel="nofollow noreferrer">Output</a>

blocks|key|1495906|text|根据你对其他人的回复，这就是你要找的东西。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1495907|string+file+=+@"C:\file.txt";
string+strToProcess+=+"fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
string[]+lines+=+strToProcess.Split(new+char[]+{+'@'+},+StringSplitOptions.RemoveEmptyEntries);

using+(StreamWriter+writer+=+new+StreamWriter(file))
{
++++foreach+(string+line+in+lines)
++++{
++++++++writer.WriteLine(line+%2B+"@");
++++}
}|code-block|syntax|javascript|1495908|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Based on your replies to everyone else, something like this is what you're looking for.

<pre><code>string file = @"C:\file.txt";
string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
string[] lines = strToProcess.Split(new char[] { '@' }, StringSplitOptions.RemoveEmptyEntries);

using (StreamWriter writer = new StreamWriter(file))
{
 foreach (string line in lines)
 {
 writer.WriteLine(line + "@");
 }
}
</code></pre>

blocks|key|1711046|text|string+str+=+"fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
str+=+str.Replace("@",+Environment.NewLine);
richTextBox1.Text+=+str;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1711047|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
str = str.Replace("@", Environment.NewLine);
richTextBox1.Text = str;
</code></pre>

blocks|key|1711199|text|如下所述更改您的字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1711200|string+strToProcess+=+"fkdfdsfdflkdkfk"%2B+System.Environment.NewLine+%2B"+dfsdfjk72388389"%2B+System.Environment.NewLine+%2B"kdkfkdfkkl"%2B+System.Environment.NewLine+%2B"jkdjkfjd"%2B+System.Environment.NewLine+%2B"jjjk"%2B+System.Environment.NewLine;|code-block|syntax|javascript|1711201|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Change your string as mentioned below.
<pre><code>string strToProcess = &quot;fkdfdsfdflkdkfk&quot;+ System.Environment.NewLine +&quot; dfsdfjk72388389&quot;+ System.Environment.NewLine +&quot;kdkfkdfkkl&quot;+ System.Environment.NewLine +&quot;jkdjkfjd&quot;+ System.Environment.NewLine +&quot;jjjk&quot;+ System.Environment.NewLine;
</code></pre>

blocks|key|1496041|text|您也可以使用string[]+something+=+text.Split('@')。确保使用单引号将"@“括起来，以将其存储为char类型。这将把每个"@“之前的字符作为单独的单词存储在数组中。然后，可以使用for循环输出每个(element+%2B+System.Environment.NewLine)，也可以使用System.IO.File.WriteAllLines([file+path+%2B+name+and+extension],+[array+name])将其写入文本文件。如果指定的文件不存在于该位置，则会自动创建该文件。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1496042|entityMap^0|6|10|1S|4|37|10|4E|24|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|G|$]]

You could also use <code>string[] something = text.Split('@')</code>. Make sure you use single quotes to surround the "@" to store it as a <code>char</code> type.
This will store the characters up to and including each "@" as individual words in the array. You can then output each (<code>element + System.Environment.NewLine</code>) using a for loop or write it to a text file using <code>System.IO.File.WriteAllLines([file path + name and extension], [array name])</code>. If the specified file doesn't exist in that location it will be automatically created.

blocks|key|1711133|text|protected+void+Button1_Click(object+sender,+EventArgs+e)
{
++++string+str+=+"fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
++++str+=+str.Replace("@",+"@"+%2B+" ");
++++Response.Write(str);+++++++
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1711134|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>protected void Button1_Click(object sender, EventArgs e)
{
 string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
 str = str.Replace("@", "@" + "&lt;br/&gt;");
 Response.Write(str); 
}
</code></pre>

blocks|key|1496089|text|using+System;
using+System.IO;
using+System.Text;

class+Test
{
++++public+static+void+Main()
++++{
+++++++++++++string+strToProcess+=+"fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
++++++++++++strToProcess.Replace("@",+Environment.NewLine);
++++++++++++Console.WriteLine(strToProcess);
++++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1496090|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>using System;
using System.IO;
using System.Text;

class Test
{
 public static void Main()
 {
 string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
 strToProcess.Replace("@", Environment.NewLine);
 Console.WriteLine(strToProcess);
 }
}
</code></pre>

I have a string.

<pre><code>string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
</code></pre>

I need to add a newline after every occurence of "@" symbol in the string.

My Output should be like this

<pre><code>fkdfdsfdflkdkfk@
dfsdfjk72388389@
kdkfkdfkkl@
jkdjkfjd@
jjjk@
</code></pre>

Adding a newline into a string in C#

我有一根绳子。string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";我需要在字符串中每次出现"@“符号后添加一个换行符。我的输出应该是这样的fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@

问在C#中向字符串中添加换行符
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回答 13

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问在C#中向字符串中添加换行符EN

回答 13

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问在C#中向字符串中添加换行符
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