blocks|key|935257|text|@Deprecated
public+static+int+toInt(Object+obj)
{
++++if+(obj+instanceof+String)
++++{
+++++++++return+Integer.parseInt((String)+obj);
++++}+else+if+(obj+instanceof+Number)
++++{
+++++++++return+((Number)+obj).intValue();
++++}+else
++++{
+++++++++String+toString+=+obj.toString();
+++++++++if+(toString.matches("-?\d%2B"))
+++++++++{
++++++++++++++return+Integer.parseInt(toString);
+++++++++}
+++++++++throw+new+IllegalArgumentException("This+Object+doesn't+represent+an+int");
++++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|935258|正如您所看到的，这不是一种非常有效的方法。你只需要确定你所拥有的是什么类型的对象。然后以正确的方式将其转换为int类型。|unstyled|935259|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>@Deprecated
public static int toInt(Object obj)
{
 if (obj instanceof String)
 {
 return Integer.parseInt((String) obj);
 } else if (obj instanceof Number)
 {
 return ((Number) obj).intValue();
 } else
 {
 String toString = obj.toString();
 if (toString.matches("-?\d+"))
 {
 return Integer.parseInt(toString);
 }
 throw new IllegalArgumentException("This Object doesn't represent an int");
 }
}
</code></pre>

As you can see, this isn't a very efficient way of doing it. You simply have to be sure of what kind of object you have. Then convert it to an int the right way.

blocks|key|1149393|text|您必须将其转换为Integer+(int的包装类)。然后，您可以使用Integer的intValue()方法来获取内部整数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1149394|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

You have to cast it to an Integer (int's wrapper class). You can then use Integer's intValue() method to obtain the inner int.

blocks|key|1149576|text|答案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1149577|int+i+=+(+Integer+)+yourObject;|code-block|syntax|javascript|1149578|如果你的对象已经是一个整数，它将平滑地运行。即：|1149579|Object+yourObject+=+1;
//++cast+here|1149580|或|1149581|Object+yourObject+=+new+Integer(1);
//++cast+here|1149582|等。|1149583|如果您的对象是其他任何对象，您需要首先(如果可能)将其转换为int：|1149584|String+s+=+"1";
Object+yourObject+=+Integer.parseInt(s);
//++cast+here|1149585|1149586|String+s+=+"1";
Object+yourObject+=+Integer.valueOf(+s+);
//++cast+here|1149587|entityMap^0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|11|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|13|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|15|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|16|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|U|3|L|5|6|7|18|8|@]|9|@]|A|$]]|$1|V|3|W|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|X|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]]|Y|$]]

Answer:

<pre><code>int i = ( Integer ) yourObject;
</code></pre>

If, your object is an integer already, it will run smoothly. ie:

<pre><code>Object yourObject = 1;
// cast here
</code></pre>

or

<pre><code>Object yourObject = new Integer(1);
// cast here
</code></pre>

etc.

If your object is anything else, you would need to convert it ( if possible ) to an int first:

<pre><code>String s = "1";
Object yourObject = Integer.parseInt(s);
// cast here
</code></pre>

Or

<pre><code>String s = "1";
Object yourObject = Integer.valueOf( s );
// cast here
</code></pre>

blocks|key|1149751|text|在处理来自GSON的数据时，我使用一行程序：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1149752|int+i+=+object+!=+null+?+Double.valueOf(object.toString()).intValue()+:+0;|code-block|syntax|javascript|1149753|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I use a one-liner when processing data from GSON:

<pre><code>int i = object != null ? Double.valueOf(object.toString()).intValue() : 0;
</code></pre>

blocks|key|1149437|text|你不能。int不是Object。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1149438|虽然Integer是一个Object，但我怀疑这是你的意思。|1149439|entityMap^0|4|3|9|6|0|2|7|C|6|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|I|$]]

You can't. An <code>int</code> is not an <code>Object</code>.

<code>Integer</code> is an <code>Object</code> though, but I doubt that's what you mean.

blocks|key|935097|text|不能这样做。int不是一个对象，它是一个原始类型。您可以将其强制转换为Integer，然后获取int。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|935098|+Integer+i+=+(Integer)+o;+//+throws+ClassCastException+if+o.getClass()+!=+Integer.class

+int+num+=+i;+//Java+1.5+or+higher|code-block|syntax|javascript|935099|entityMap^0|6|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Can't be done. An <code>int</code> is not an object, it's a primitive type. You can cast it to Integer, then get the int.

<pre><code> Integer i = (Integer) o; // throws ClassCastException if o.getClass() != Integer.class

 int num = i; //Java 1.5 or higher
</code></pre>

blocks|key|935213|text|int+i+=+(Integer)+object;+//Type+is+Integer.

int+i+=+Integer.parseInt((String)object);+//Type+is+String.|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|935214|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>int i = (Integer) object; //Type is Integer.

int i = Integer.parseInt((String)object); //Type is String.
</code></pre>

blocks|key|935134|text|如果您的意思是将字符串转换为整数，请使用Integer.valueOf("123")。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|935135|但是，您不能将大多数其他对象转换为int，因为它们不会有int值。例如，XmlDocument没有int值。|935136|entityMap^0|K|M|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|N|8|@]|D|@]|E|$]]]|I|$]]

If you mean cast a String to int, use <code>Integer.valueOf("123")</code>.

You can't cast most other Objects to int though, because they wont have an int value. E.g. an XmlDocument has no int value.

blocks|key|1149828|text|int[]+getAdminIDList(String+tableName,+String+attributeName,+int+value)+throws+SQLException+{
++++ArrayList+list+=+null;
++++Statement+statement+=+conn.createStatement();
++++ResultSet+result+=+statement.executeQuery("SELECT+admin_id+FROM+"+%2B+tableName+%2B+"+WHERE+"+%2B+attributeName+%2B+"='"+%2B+value+%2B+"'");
++++while+(result.next())+{
++++++++list.add(result.getInt(1));
++++}
++++statement.close();
++++int+id[]+=+new+int[list.size()];
++++for+(int+i+=+0;+i+<+id.length;+i%2B%2B)+{
++++++++try+{
++++++++++++id[i]+=+((Integer)+list.get(i)).intValue();
++++++++}+catch(NullPointerException+ne)+{
++++++++}+catch(ClassCastException+ch)+{}
++++}
++++return+id;
}
//+enter+code+here|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1149829|这段代码展示了为什么ArrayList很重要，以及我们为什么使用它。简单地从Object转换int。可能是有帮助的。|unstyled|offset|length|style|CODE|1149830|entityMap^0|0|A|9|12|6|1A|3|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]|$G|S|H|T|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|U|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>int[] getAdminIDList(String tableName, String attributeName, int value) throws SQLException {
 ArrayList list = null;
 Statement statement = conn.createStatement();
 ResultSet result = statement.executeQuery("SELECT admin_id FROM " + tableName + " WHERE " + attributeName + "='" + value + "'");
 while (result.next()) {
 list.add(result.getInt(1));
 }
 statement.close();
 int id[] = new int[list.size()];
 for (int i = 0; i &lt; id.length; i++) {
 try {
 id[i] = ((Integer) list.get(i)).intValue();
 } catch(NullPointerException ne) {
 } catch(ClassCastException ch) {}
 }
 return id;
}
// enter code here
</code></pre>

This code shows why <code>ArrayList</code> is important and why we use it. Simply casting <code>int</code> from <code>Object</code>. May be its helpful.

blocks|key|935489|text|请参考以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|935490|public+class+sample+
{
++public+static+void+main(String[]+args)+
++{
++++Object+obj=new+Object();
++++int+a=10,b=0;
++++obj=a;
++++b=(int)obj;

++++System.out.println("Object="%2Bobj%2B"\nB="%2Bb);
++}
}|code-block|syntax|javascript|935491|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Refer This code: 

<pre><code>public class sample 
{
 public static void main(String[] args) 
 {
 Object obj=new Object();
 int a=10,b=0;
 obj=a;
 b=(int)obj;

 System.out.println("Object="+obj+"\nB="+b);
 }
}
</code></pre>

blocks|key|935497|text|so+divide1=me.getValue()/2;

int+divide1+=+(Integer)+me.getValue()/2;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|935498|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>so divide1=me.getValue()/2;

int divide1 = (Integer) me.getValue()/2;
</code></pre>

blocks|key|935562|text|最后，找到了您的规范的最佳实现。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|935563|public+int+tellMyNumber(Object+any)+{
++++return+42;
}|code-block|syntax|javascript|935564|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Finally, the best implementation for your specification was found.

<pre class="lang-java prettyprint-override"><code>public int tellMyNumber(Object any) {
 return 42;
}
</code></pre>

blocks|key|935294|text|首先检查instanceof关键字。如果为true，则对其进行强制转换。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|935295|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

first check with instanceof keyword . if true then cast it.

How can I cast an Object to an int in java?

How to cast an Object to an int

Java

如何在java中将对象强制转换为int类型？

问如何将对象强制转换为int类型
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