blocks|key|185191|text|在Python3.x中，raw_input被重命名为input，并删除了Python2.x+input。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|185192|这意味着，就像raw_input一样，Python3.x中的input总是返回一个string对象。|185193|要解决这个问题，您需要通过将这些输入放入int中来显式地将它们转换为整数|185194|x+=+int(input("Enter+a+number:+"))
y+=+int(input("Enter+a+number:+"))|code-block|syntax|javascript|185195|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/3/library/functions.html#input|1|http://docs.python.org/3/library/functions.html#int^0|C|9|Q|5|1A|5|0|7|9|U|5|U|5|0|0|K|3|K|3|1|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|15|8|@$9|16|A|17|B|C]|$9|18|A|19|B|C]]|D|@$9|1A|A|1B|1|1C]]|E|$]]|$1|H|3|I|5|6|7|1D|8|@$9|1E|A|1F|B|C]]|D|@$9|1G|A|1H|1|1I]]|E|$]]|$1|J|3|K|5|L|7|1J|8|@]|D|@]|E|$M|N]]|$1|O|3|-4|5|6|7|1K|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]]]

In Python 3.x, <code>raw_input</code> was renamed to <code>input</code> and the Python 2.x <code>input</code> was removed. 

This means that, just like <code>raw_input</code>, <a href="http://docs.python.org/3/library/functions.html#input" rel="noreferrer"><code>input</code></a> in Python 3.x always returns a string object.

To fix the problem, you need to explicitly make those inputs into integers by putting them in <a href="http://docs.python.org/3/library/functions.html#int" rel="noreferrer"><code>int</code></a>:

<pre><code>x = int(input("Enter a number: "))
y = int(input("Enter a number: "))
</code></pre>

blocks|key|185343|text|对于一行中的多个整数，map可能更好。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|185344|arr+=+map(int,+raw_input().split())|code-block|syntax|javascript|185345|如果这个数字是已知的(比如2个整数)，你可以使用|185346|num1,+num2+=+map(int,+raw_input().split())|185347|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/library/functions.html#map^0|B|3|B|3|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

For multiple integer in a single line, <a href="https://docs.python.org/library/functions.html#map" rel="noreferrer"><code>map</code></a> might be better.

<pre><code>arr = map(int, raw_input().split())
</code></pre>

If the number is already known, (like 2 integers), you can use

<pre><code>num1, num2 = map(int, raw_input().split())
</code></pre>

blocks|key|185288|text|多个问题需要在一行中输入多个整数。最好的方法是输入整个数字字符串一行，然后将它们拆分为整数。以下是Python+3的一个版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|185289|a+=+[]
p+=+input()
p+=+p.split()++++++
for+i+in+p:
++++a.append(int(i))|code-block|syntax|javascript|185290|也可以使用列表理解|185291|p+=+input().split("whatever+the+seperator+is")|185292|为了将所有输入从字符串转换为int，我们执行以下操作|185293|x+=+[int(i)+for+i+in+p]
print(x,+end='+')|185294|应以直线打印列表元素。|185295|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Multiple questions require input for several integers on single line. The best way is to input the whole string of numbers one one line and then split them to integers. Here is a Python 3 version:

<pre><code>a = []
p = input()
p = p.split() 
for i in p:
 a.append(int(i))
</code></pre>

Also a list comprehension can be used

<pre><code>p = input().split("whatever the seperator is")
</code></pre>

And to convert all the inputs from string to int we do the following

<pre><code>x = [int(i) for i in p]
print(x, end=' ')
</code></pre>

shall print the list elements in a straight line.

blocks|key|185383|text|转换为整数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|185384|my_number+=+int(input("enter+the+number"))|code-block|syntax|javascript|185385|同样，浮点数也是如此：|185386|my_decimalnumber+=+float(input("enter+the+number"))|185387|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Convert to integers:

<pre><code>my_number = int(input("enter the number"))
</code></pre>

Similarly for floating point numbers:

<pre><code>my_decimalnumber = float(input("enter the number"))
</code></pre>

blocks|key|185407|text|n=int(input())
for+i+in+range(n):
++++n=input()
++++n=int(n)
++++arr1=list(map(int,input().split()))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|185408|for循环应运行'n‘次。第二个'n‘是数组的长度。最后一条语句将整数映射到一个列表，并以空格分隔的形式接受输入。您也可以在for循环结束时返回数组。|unstyled|185409|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>n=int(input())
for i in range(n):
 n=input()
 n=int(n)
 arr1=list(map(int,input().split()))
</code></pre>

the for loop shall run 'n' number of times . the second 'n' is the length of the array.
the last statement maps the integers to a list and takes input in space separated form .
you can also return the array at the end of for loop.

blocks|key|4691040|text|我在解决CodeChef上的一个问题时遇到了一个接受整数输入的问题，在这个问题中，由空格分隔的两个整数应该从一行读取。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4691041|虽然int(input())对于单个整数就足够了，但我没有找到直接输入两个整数的方法。我试过这个：|style|CODE|4691042|num+=+input()
num1+=+0
num2+=+0

for+i+in+range(len(num)):
++++if+num[i]+==+'+':
++++++++break

num1+=+int(num[:i])
num2+=+int(num[i%2B1:])|code-block|syntax|javascript|4691043|现在我使用num1和num2作为整数。|4691044|entityMap|0|LINK|mutability|MUTABLE|url|http://www.codechef.com/problems/TLG^0|4|8|0|0|2|C|0|0|5|4|A|4|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|6|7|10|8|@$A|11|B|12|F|G]]|9|@]|C|$]]|$1|H|3|I|5|J|7|13|8|@]|9|@]|C|$K|L]]|$1|M|3|N|5|6|7|14|8|@$A|15|B|16|F|G]|$A|17|B|18|F|G]]|9|@]|C|$]]|$1|O|3|-4|5|6|7|19|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

I encountered a problem of taking integer input while solving a problem on <a href="http://www.codechef.com/problems/TLG" rel="nofollow noreferrer">CodeChef</a>, where two integers - separated by space - should be read from one line.
While <code>int(input())</code> is sufficient for a single integer, I did not find a direct way to input two integers. I tried this:
<pre class="lang-py prettyprint-override"><code>num = input()
num1 = 0
num2 = 0

for i in range(len(num)):
 if num[i] == ' ':
 break

num1 = int(num[:i])
num2 = int(num[i+1:])
</code></pre>
Now I use <code>num1</code> and <code>num2</code> as integers.

blocks|key|4691128|text|def+dbz():
++++try:
++++++++r+=+raw_input("Enter+number:")
++++++++if+r.isdigit():
++++++++++++i+=+int(raw_input("Enter+divident:"))
++++++++++++d+=+int(r)/i
++++++++++++print+"O/p+is+-:",d
++++++++else:
++++++++++++print+"Not+a+number"
++++except+Exception+,e:
++++++++print+"Program+halted+incorrect+data+entered",type(e)
dbz()

Or+

num+=+input("Enter+Number:")#"input"+will+accept+only+numbers|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4691129|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>def dbz():
 try:
 r = raw_input("Enter number:")
 if r.isdigit():
 i = int(raw_input("Enter divident:"))
 d = int(r)/i
 print "O/p is -:",d
 else:
 print "Not a number"
 except Exception ,e:
 print "Program halted incorrect data entered",type(e)
dbz()

Or 

num = input("Enter Number:")#"input" will accept only numbers
</code></pre>

Why are <code>x</code> and <code>y</code> strings instead of ints in the below code?

(Note: in Python 2.x use <code>raw_input()</code>. In Python 3.x use <code>input()</code>. <code>raw_input()</code> was renamed to <code>input()</code> in Python 3.x)

<pre><code>play = True

while play:

 x = input("Enter a number: ")
 y = input("Enter a number: ")

 print(x + y)
 print(x - y)
 print(x * y)
 print(x / y)
 print(x % y)

 if input("Play again? ") == "no":
 play = False
</code></pre>

How can I read inputs as numbers?

Python

为什么在下面的代码中是x和y字符串而不是in？(注意:在Python2.x中使用raw_input()。在Python3.x中使用input()。在Python3.x中将raw_input()重命名为input() )play = Truewhile play:    x = input("Enter a number: ")    y = input("Enter a number: ")   

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