问使用AJAX将JavaScript数组发布到asp.net MVC控制器

EN

public class AddUserViewModel
{
    public int ProjectId { get; set; }
    public int[] userAccountIds { get; set; }
}

[HttpPost]
public ActionResult AddUsers(AddUserViewModel model)
{
    ...
}

function sendForm(projectId, target) {
    $.ajax({
        url: target,
        type: 'POST',
        contentType: 'application/json',
        data: JSON.stringify({ 
            projectId: projectId, 
            userAccountIds: [1, 2, 3] 
        }),
        success: ajaxOnSuccess,
        error: function (jqXHR, exception) {
            alert('Error message.');
        }
    });
}

var myArray = new Array();
myArray.push(2);
myArray.push(3);
$.ajax({
            type: "POST",
            url: '/MyController/MyAction',
            data: { 'myArray': myArray.join() },
            success: refreshPage
        });

public PartialViewResult MyAction(string myArray)
{
   var myArrayInt = myArray.Split(',').Select(x=>Int32.Parse(x)).ToArray();
   //My Action Code Here
}

var uname = 'John Doe';

$.ajax({

        url: "/Main/getRequestID",  // This is path of your Controller with Action Result.
        dataType: "json",           // Data Type for sending the data

        data: {                     // Data that will be passed to Controller
            'my_name': uname,     // assign data like key-value pair       
             // 'my_name'  like fields in quote is same with parameter in action Result
        },

        type: "POST",               // Type of Request
        contentType: "application/json; charset=utf-8", //Optional to specify Content Type.

        success: function (data) { // This function is executed when this request is succeed.
                alert(data);
        },

        error: function (data) {
                alert("Error");   // This function is executed when error occurred.
        }
)};

public ActionResult getRequestID(String my_name)
{

    MYDBModel myTable = new Models.MYDBModel();
    myTable.FBUserName = my_name;
    db.MYDBModel.Add(myTable);
    db.SaveChanges();              // db object of our DbContext.cs
    //return RedirectToAction(“Index”);   // After that you can redirect to some pages…
    return Json(true, JsonRequestBehavior.AllowGet);    // Or you can get that data back after inserting into database.. This json displays all the details to our view as well.
}