blocks|key|1709803|text|下面是另外两种方法，都非常简洁。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1709804|$arr1+=+@(0)+*+20
$arr2+=+,0+*+20|code-block|syntax|javascript|1709805|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here's two more ways, both very concise.

<pre><code>$arr1 = @(0) * 20
$arr2 = ,0 * 20
</code></pre>

blocks|key|1709772|text|$array+=+1..5+%7C+foreach+{+$false+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1709773|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$array = 1..5 | foreach { $false }
</code></pre>

blocks|key|1494721|text|$array+=+@()
for($i=0;+$i+-lt+5;+$i%2B%2B)
{
++++$array+%2B=+$i
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1494722|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$array = @()
for($i=0; $i -lt 5; $i++)
{
 $array += $i
}
</code></pre>

blocks|key|1494861|text|这是另一个想法。你必须记住，它下面是.NET：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1494862|$arr+=+[System.Array]::CreateInstance([System.Object],+5)
$arr.GetType()
$arr.Length

$arr+=+[Object[]]::new(5)
$arr.GetType()
$arr.Length|code-block|syntax|javascript|1494863|结果：|1494864|IsPublic+IsSerial+Name+++++++++++++++++++++++++++++++++++++BaseType+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
--------+--------+----+++++++++++++++++++++++++++++++++++++--------+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
True+++++True+++++Object[]+++++++++++++++++++++++++++++++++System.Array+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
5
True+++++True+++++Object[]+++++++++++++++++++++++++++++++++System.Array+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
5|1494865|使用new()有一个明显的优点:当您在ISE中编程并想要创建一个对象时，ISE将向您提供所有参数组合及其类型的提示。在New-Object中，您必须记住参数的类型和顺序，这与此不同。|offset|length|style|CODE|1494866|​|1494867|📷|atomic|1494868|1494869|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/0a2a6da17fae6e779cc90127b3dcc0c3.jpeg|imageAlt^0|0|0|0|0|2|5|1N|A|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|15|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|17|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|18|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|19|8|@$M|1A|N|1B|O|P]|$M|1C|N|1D|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1E|8|@]|9|@]|A|$]]|$1|S|3|T|5|U|7|1F|8|@]|9|@$M|1G|N|1H|1|1I]]|A|$]]|$1|V|3|R|5|6|7|1J|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|X|$Y|$5|Z|10|11|A|$12|13|14|-4]]]]

Here's another idea. You have to remember, that it's .NET underneath:

<pre><code>$arr = [System.Array]::CreateInstance([System.Object], 5)
$arr.GetType()
$arr.Length

$arr = [Object[]]::new(5)
$arr.GetType()
$arr.Length
</code></pre>

Result:

<pre><code>IsPublic IsSerial Name BaseType 
-------- -------- ---- -------- 
True True Object[] System.Array 
5
True True Object[] System.Array 
5
</code></pre>

Using <code>new()</code> has one distinct advantage: when you're programming in ISE and want to create an object, ISE will give you hint with all paramer combinations and their types. You don't have that with <code>New-Object</code>, where you have to remember the types and order of arguments. 

<a href="https://i.stack.imgur.com/QEUCF.jpg" rel="noreferrer"><img src="https://i.stack.imgur.com/QEUCF.jpg" alt="ISE IntelliSense for new object"></a>

blocks|key|1709699|text|我找到的解决方案是使用New-Object+cmdlet初始化适当大小的数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1709700|$array+=+new-object+object[]+5+
for($i=0;+$i+-lt+$array.Length;$i%2B%2B)
{
++++$array[$i]+=+$FALSE
}|code-block|syntax|javascript|1709701|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The solution I found was to use the New-Object cmdlet to initialize an array of the proper size.

<pre><code>$array = new-object object[] 5 
for($i=0; $i -lt $array.Length;$i++)
{
 $array[$i] = $FALSE
}
</code></pre>

blocks|key|1494707|text|如果我不知道前面的大小，我会使用数组列表而不是数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1494708|$al+=+New-Object+System.Collections.ArrayList
for($i=0;+$i+-lt+5;+$i%2B%2B)
{
++++$al.Add($i)
}|code-block|syntax|javascript|1494709|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If I don't know the size up front, I use an arraylist instead of an array.

<pre><code>$al = New-Object System.Collections.ArrayList
for($i=0; $i -lt 5; $i++)
{
 $al.Add($i)
}
</code></pre>

blocks|key|1494950|text|这是另一种典型的方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1494951|$array+=+for($i+=+0;+$i+-le+4;+$i%2B%2B)+{+$false+}|code-block|syntax|javascript|1494952|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here's another typical way:

<pre><code>$array = for($i = 0; $i -le 4; $i++) { $false }
</code></pre>

blocks|key|1494895|text|或者尝试一下这个想法。与powershell+5.0%2B配合使用。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1494896|[bool[]]$tf=((,$False)*5)|code-block|syntax|javascript|1494897|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Or try this an idea. Works with powershell 5.0+.

<pre><code>[bool[]]$tf=((,$False)*5)
</code></pre>

blocks|key|1494956|text|$array+=+foreach($i+in+1..5)+{+$false+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1494957|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$array = foreach($i in 1..5) { $false }
</code></pre>

What's the best way to initialize an array in PowerShell?

For example, the code

<pre><code>$array = @()
for($i=0; $i -lt 5;$i++)
{
 $array[$i] = $FALSE
}
</code></pre>

generates the error

<pre><code>Array assignment failed because index '0' was out of range.
At H:\Software\PowerShell\TestArray.ps1:4 char:10
+ $array[$ &lt;&lt;&lt;&lt; i] = $FALSE
</code></pre>

PowerShell array initialization

在PowerShell中初始化数组的最佳方法是什么？例如，代码$array = @()for($i=0; $i -lt 5;$i++){    $array[$i] = $FALSE}生成错误Array assignment failed because index '0' was out of range.At H:\Software\PowerShell\TestArray.ps1:4 cha

问PowerShell数组初始化
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