blocks|key|1234091|text|添加此代码|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1234092|[self.navigationItem+setHidesBackButton:YES];|code-block|syntax|javascript|1234093|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Add this Code

<pre><code>[self.navigationItem setHidesBackButton:YES];
</code></pre>

blocks|key|1234147|text|除了删除后退按钮(使用已经推荐的方法)，不要忘记，在iOS+7和更高版本中，用户仍然可以通过从左向右滑动手势“弹出”到上一个屏幕。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1234148|要禁用该功能(在适当的情况下)，请执行以下操作(例如，在viewDidLoad中)：|1234149|+if+([[[UIDevice+currentDevice]+systemVersion]+floatValue]+>=+7.0)
+++++self.navigationController.interactivePopGestureRecognizer.enabled+=+NO;|code-block|syntax|javascript|1234150|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

In addition to removing the back button (using the methods already recommended), don't forget the user can still 'pop' to the previous screen with a left-to-right swipe gesture in iOS 7 and later.

To disable that (when appropriate), implement the following (in viewDidLoad for example):

<pre><code> if ([[[UIDevice currentDevice] systemVersion] floatValue] &gt;= 7.0)
 self.navigationController.interactivePopGestureRecognizer.enabled = NO;
</code></pre>

blocks|key|1448945|text|只是为了澄清现有的答案：hidesBackButton属性是正确的答案，但在许多答案中，self指的是什么并不清楚。基本上，您应该在即将推送(或刚刚推送)到UINavigationController上的视图控制器中设置self.navigationItem.hidesBackButton+=+YES。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1448946|换句话说，假设我有一个名为myNavController的UINavigationController。我想要在它上面放一个新的视图，当我这样做的时候，我不想再显示后退按钮。我可以这样做：|1448947|UIViewController+*newVC+=+[[UIViewController+alloc]+init];
//presumably+would+do+some+stuff+here+to+set+up+the+new+view+controller
newVC.navigationItem.hidesBackButton+=+YES;
[myNavController+pushViewController:newVC+animated:YES];|code-block|syntax|javascript|1448948|当代码完成时，由newVC控制的视图现在应该会显示，并且不应该显示任何back按钮。|1448949|entityMap^0|C|F|18|4|26|M|32|15|0|D|F|T|M|0|0|8|5|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|15|8|@$9|16|A|17|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|P|$]]

Just to clarify existing answers: the <code>hidesBackButton</code> property is the right answer, but it isn't clear in many answers what <code>self</code> refers to. Basically you should set <code>self.navigationItem.hidesBackButton = YES</code> in the view controller that is about to get pushed (or just got pushed) onto the <code>UINavigationController</code>.

In other words, say I have a <code>UINavigationController</code> named <code>myNavController</code>. I want to put a new view on it, and when I do I don't want the back button to show anymore. I could do something like:

<pre><code>UIViewController *newVC = [[UIViewController alloc] init];
//presumably would do some stuff here to set up the new view controller
newVC.navigationItem.hidesBackButton = YES;
[myNavController pushViewController:newVC animated:YES];
</code></pre>

When the code finishes, the view controlled by <code>newVC</code> should now be showing, and no back button should be visible.

blocks|key|1448700|text|为了有条件地隐藏和显示Back按钮，您可以使用以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1448701|-(void)viewDidAppear:(BOOL)animated
{
++++if+([tempAry+count]==0)
++++{
++++++++[self.navigationItem+setHidesBackButton:YES+animated:YES];
++++}
++++else
++++{
++++++++[self.navigationItem+setHidesBackButton:NO+animated:YES];
++++}
++++[super+viewDidAppear:animated];
}+|code-block|syntax|javascript|1448702|注意:在某些情况下，你必须将它放在viewDidAppear方法中，而不是viewWillAppear方法中，比如:当你将下一个类的数组更新到前一个类中，然后将条件签入到下一个类中，就像上面一样。|1448703|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

For hiding and showing the Back button conditionally you can use following code:

<pre><code>-(void)viewDidAppear:(BOOL)animated
{
 if ([tempAry count]==0)
 {
 [self.navigationItem setHidesBackButton:YES animated:YES];
 }
 else
 {
 [self.navigationItem setHidesBackButton:NO animated:YES];
 }
 [super viewDidAppear:animated];
} 
</code></pre>

Note: in some cases, you have to put it in viewDidAppear method instead of viewWillAppear
such cases like: when you are updating array of next class into previous class and then checking condition into next class as above.

blocks|key|1448961|text|Swift+iOS+(我用过下面的代码)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1448962|//+hide+back+button
++++++++self.navigationItem.setHidesBackButton(true,+animated:+false)

//+pgrm+mark+-----+------

++++//+hide+the+back+button+for+this+view+controller

++++override+func+setEditing(editing:+Bool,+animated:+Bool)+{
++++++++super.setEditing(editing,+animated:+animated)

++++++++self.navigationItem.setHidesBackButton(editing,+animated:+animated)

++++}//+end+setEditing|code-block|syntax|javascript|1448963|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Swift iOS (I have used following)

<pre><code>// hide back button
 self.navigationItem.setHidesBackButton(true, animated: false)

// pgrm mark ----- ------

 // hide the back button for this view controller

 override func setEditing(editing: Bool, animated: Bool) {
 super.setEditing(editing, animated: animated)

 self.navigationItem.setHidesBackButton(editing, animated: animated)

 }// end setEditing
</code></pre>

blocks|key|1448812|text|由于某些原因，Zoran+Simic建议的解决方案对我不起作用。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1448813|然而，下面的代码确实可以工作：|1448814|MyController*+controller+++=+++[[MyController+alloc]++init];
NSArray*+array+++++++++++++=+++[[[NSArray+alloc]+initWithObjects:controller,+nil]+autorelease];

[self.navigationController+setViewControllers:array+animated:NO];

[controller+release];|code-block|syntax|javascript|1448815|显然，您必须按照自己的喜好来操作NSArray，才能让它为您工作。希望这对某些人有帮助:)|1448816|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

The solution suggest by Zoran Simic didn't work for me for some reason.

This code did work however:

<pre><code>MyController* controller = [[MyController alloc] init];
NSArray* array = [[[NSArray alloc] initWithObjects:controller, nil] autorelease];

[self.navigationController setViewControllers:array animated:NO];

[controller release];
</code></pre>

Obviously you'd have to manipulate an NSArray to your taste to make it work for you.
Hope that helps somebody :)

blocks|key|1233974|text|在我的UIViewController子类中，我有这个方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1233975|-(void)setEditing:(BOOL)editing+animated:(BOOL)animated+{
++++[super+setEditing:editing+animated:+animated];

++++//+hide+back+button+in+edit+mode
++++[self.navigationItem+setHidesBackButton:editing+animated:YES];
}|code-block|syntax|javascript|1233976|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In my UIViewController subclass I have this method:

<pre><code>-(void)setEditing:(BOOL)editing animated:(BOOL)animated {
 [super setEditing:editing animated: animated];

 // hide back button in edit mode
 [self.navigationItem setHidesBackButton:editing animated:YES];
}
</code></pre>

blocks|key|1234286|text|这将隐藏Swift中的back按钮并将其替换为add按钮：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1234287|override+func+setEditing(_+editing:+Bool,+animated:+Bool)+{
++++super.setEditing(editing,+animated:+animated)

++++//+This+hides+the+back+button+while+in+editing+mode,+which+makes+room+for+an+add+item+button
++++self.navigationItem.setHidesBackButton(editing,+animated:+animated)

++++if+editing+{
++++++++//+This+adds+the+add+item+button
++++++++let+addButton+=+UIBarButtonItem(barButtonSystemItem:+.add,+target:+self,+action:+#selector(addTapped))
++++++++//+Use+the+animated+setter+for+the+left+button+so+that+add+button+fades+in+while+the+back+button+fades+out
++++++++self.navigationItem.setLeftBarButton(addButton,+animated:+animated)
++++++++self.enableBackGesture(enabled:+false)
++++}+else+{
++++++++//+This+removes+the+add+item+button
++++++++self.navigationItem.setLeftBarButton(nil,+animated:+animated)
++++++++self.enableBackGesture(enabled:+true)
++++}
}

func+enableBackGesture(enabled:+Bool)+{
++++//+In+addition+to+removing+the+back+button+and+adding+the+add+item+button+while+in+edit+mode,+the+user+can+still+exit+to+the+previous+screen+with+a+left-to-right+swipe+gesture+in+iOS+7+and+later.+This+code+disables+this+action+while+in+edit+mode.
++++if+let+navigationController+=+self.navigationController+{
++++++++if+let+interactivePopGestureRecognizer+=+navigationController.interactivePopGestureRecognizer+{
++++++++++++interactivePopGestureRecognizer.isEnabled+=+enabled
++++++++}
++++}
}|code-block|syntax|javascript|1234288|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This hides the back button and replaces it with an add button in Swift:

<pre><code>override func setEditing(_ editing: Bool, animated: Bool) {
 super.setEditing(editing, animated: animated)

 // This hides the back button while in editing mode, which makes room for an add item button
 self.navigationItem.setHidesBackButton(editing, animated: animated)

 if editing {
 // This adds the add item button
 let addButton = UIBarButtonItem(barButtonSystemItem: .add, target: self, action: #selector(addTapped))
 // Use the animated setter for the left button so that add button fades in while the back button fades out
 self.navigationItem.setLeftBarButton(addButton, animated: animated)
 self.enableBackGesture(enabled: false)
 } else {
 // This removes the add item button
 self.navigationItem.setLeftBarButton(nil, animated: animated)
 self.enableBackGesture(enabled: true)
 }
}

func enableBackGesture(enabled: Bool) {
 // In addition to removing the back button and adding the add item button while in edit mode, the user can still exit to the previous screen with a left-to-right swipe gesture in iOS 7 and later. This code disables this action while in edit mode.
 if let navigationController = self.navigationController {
 if let interactivePopGestureRecognizer = navigationController.interactivePopGestureRecognizer {
 interactivePopGestureRecognizer.isEnabled = enabled
 }
 }
}
</code></pre>

blocks|key|1234324|text|斯威夫特3|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1234325|通常，您应该使用Apple的per-ViewController+API，正如本页面中多次描述的那样，但有时您需要立即控制Back按钮。|1234326|下面的代码隐藏“后退”按钮，并确保在隐藏按钮区域中不会发生轻击冲突检测。|1234327|let+emptyView+=+UIView(frame:+.zero)
self.navigationItem.leftBarButtonItem+=+UIBarButtonItem(customView:+emptyView)|code-block|syntax|javascript|1234328|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|O|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|P|8|@]|9|@]|A|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Swift 3.

Generally, you should use Apple's per-ViewController API as described many times already on this page, but sometimes you need immediate control of the Back button.

The following code hides the Back button and ensures that tap collision detection doesn't occur in the hidden button region.

<pre><code>let emptyView = UIView(frame: .zero)
self.navigationItem.leftBarButtonItem = UIBarButtonItem(customView: emptyView)
</code></pre>

blocks|key|1234352|text|这将隐藏“后退”按钮|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1234353|let+backBtn+=+UIBarButtonItem(title:+"",+style:+UIBarButtonItemStyle.plain,+target:+navigationController,+action:+nil)


navigationItem.leftBarButtonItem+=+backBtn|code-block|syntax|javascript|1234354|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This hides the back button

<pre><code>let backBtn = UIBarButtonItem(title: "", style: UIBarButtonItemStyle.plain, target: navigationController, action: nil)


navigationItem.leftBarButtonItem = backBtn
</code></pre>

Do you know how to hide the 'back' button in a UINavigationController?
Also, how to show it back, but I guess that's very similar to hiding it...

Just like the mail application does on the iPhone when you hit 'Edit' while viewing emails.

How to hide the "back" button in UINavigationController?

你知道如何在UINavigationController中隐藏“后退”按钮吗？另外，如何显示它，但我猜这与隐藏它非常相似……就像你在查看电子邮件时点击“编辑”时，邮件应用程序在iPhone上所做的那样。

问如何在UINavigationController中隐藏“后退”按钮？
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问如何在UINavigationController中隐藏“后退”按钮？
EN