问是否可以在Python中对返回某些内容的函数进行多进程处理？

EN

#
# Simple example which uses a pool of workers to carry out some tasks.
#
# Notice that the results will probably not come out of the output
# queue in the same in the same order as the corresponding tasks were
# put on the input queue.  If it is important to get the results back
# in the original order then consider using `Pool.map()` or
# `Pool.imap()` (which will save on the amount of code needed anyway).
#
# Copyright (c) 2006-2008, R Oudkerk
# All rights reserved.
#

import time
import random

from multiprocessing import Process, Queue, current_process, freeze_support

#
# Function run by worker processes
#

def worker(input, output):
    for func, args in iter(input.get, 'STOP'):
        result = calculate(func, args)
        output.put(result)

#
# Function used to calculate result
#

def calculate(func, args):
    result = func(*args)
    return '%s says that %s%s = %s' % \
        (current_process().name, func.__name__, args, result)

#
# Functions referenced by tasks
#

def mul(a, b):
    time.sleep(0.5*random.random())
    return a * b

def plus(a, b):
    time.sleep(0.5*random.random())
    return a + b

#
#
#

def test():
    NUMBER_OF_PROCESSES = 4
    TASKS1 = [(mul, (i, 7)) for i in range(20)]
    TASKS2 = [(plus, (i, 8)) for i in range(10)]

    # Create queues
    task_queue = Queue()
    done_queue = Queue()

    # Submit tasks
    for task in TASKS1:
        task_queue.put(task)

    # Start worker processes
    for i in range(NUMBER_OF_PROCESSES):
        Process(target=worker, args=(task_queue, done_queue)).start()

    # Get and print results
    print 'Unordered results:'
    for i in range(len(TASKS1)):
        print '\t', done_queue.get()

    # Add more tasks using `put()`
    for task in TASKS2:
        task_queue.put(task)

    # Get and print some more results
    for i in range(len(TASKS2)):
        print '\t', done_queue.get()

    # Tell child processes to stop
    for i in range(NUMBER_OF_PROCESSES):
        task_queue.put('STOP')


if __name__ == '__main__':
    freeze_support()
    test()

import os
from Queue import Queue
from multiprocessing import Process

def returning_wrapper(func, *args, **kwargs):
    queue = kwargs.get("multiprocess_returnable")
    del kwargs["multiprocess_returnable"]
    queue.put(func(*args, **kwargs))

class Multiprocess(object):
    """Cute decorator to run a function in multiple processes."""
    def __init__(self, func):
        self.func = func
        self.processes = []

    def __call__(self, *args, **kwargs):
        num_processes = kwargs.get("multiprocess_num_processes", 2) # default to two processes.
        return_obj = kwargs.get("multiprocess_returnable", Queue()) # default to stdlib Queue
        kwargs["multiprocess_returnable"] = return_obj
        for i in xrange(num_processes):
            pro = Process(target=returning_wrapper, args=tuple([self.func] + list(args)), kwargs=kwargs)
            self.processes.append(pro)
            pro.start()
        return return_obj


@Multiprocess
def info():
    print 'module name:', __name__
    print 'parent process:', os.getppid()
    print 'process id:', os.getpid()
    return 4 * 22

data = info()
print data.get(False)