blocks|key|409212|text|-m+1表示返回任何给定文件中的第一个匹配项。但它仍将继续在其他文件中搜索。此外，如果在同一行中有两个或更多匹配，则会显示所有匹配项。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|409213|您可以使用head+-1来解决此问题：|409214|grep+-o+-a+-m+1+-h+-r+"Pulsanti+Operietur"+/path/to/dir+%7C+head+-1|code-block|syntax|javascript|409215|每个grep选项的说明：|409216|-o,+--only-matching,+print+only+the+matched+part+of+the+line+(instead+of+the+entire+line)
-a,+--text,+process+a+binary+file+as+if+it+were+text
-m+1,+--max-count,+stop+reading+a+file+after+1+matching+line
-h,+--no-filename,+suppress+the+prefixing+of+file+names+on+output
-r,+--recursive,+read+all+files+under+a+directory+recursively|409217|entityMap^0|0|4|0|5|7|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@$9|W|A|X|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|Z|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|R|$]]

<p><code>-m 1</code> means return the first match in any given file. But it will still continue to search in other files. Also, if there are two or more matched in the same line, all of them will be displayed.</p>

<h3>You can use <code>head -1</code> to solve this problem:</h3>

<pre><code>grep -o -a -m 1 -h -r "Pulsanti Operietur" /path/to/dir | head -1
</code></pre>

<h3>explanation of each grep option:</h3>

<pre><code>-o, --only-matching, print only the matched part of the line (instead of the entire line)
-a, --text, process a binary file as if it were text
-m 1, --max-count, stop reading a file after 1 matching line
-h, --no-filename, suppress the prefixing of file names on output
-r, --recursive, read all files under a directory recursively
</code></pre>


blocks|key|191158|text|我的类似grep-a的程序ack有一个-1选项，它在任何地方找到第一个匹配项时停止。它也支持@mvp所指的-m+1。我之所以把它放在那里，是因为如果我要搜索一棵巨大的源代码树来查找我知道只存在于一个文件中的内容，那么就没有必要找到它并按Ctrl-C组合键。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|191159|entityMap|0|LINK|mutability|MUTABLE|url|http://beyondgrep.com/^0|D|3|J|2|1H|4|D|3|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]|$9|Q|A|R|B|C]|$9|S|A|T|B|C]]|D|@$9|U|A|V|1|W]]|E|$]]|$1|F|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

<p>My grep-a-like program <a href="http://beyondgrep.com" rel="noreferrer"><code>ack</code></a> has a <code>-1</code> option that stops at the first match found anywhere.  It supports the <code>-m 1</code> that @mvp refers to as well.  I put it in there because if I'm searching a big tree of source code to find something that I know exists in only one file, it's unnecessary to find it and have to hit Ctrl-C.</p>


blocks|key|409293|text|单行程序，使用find|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|409294|find+-type+f+-exec+grep+-lm1+"PATTERN"+{}+\;+-a+-quit|code-block|syntax|javascript|409295|entityMap^0|7|4|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

<p>A single liner, using <code>find</code>:</p>

<pre><code>find -type f -exec grep -lm1 "PATTERN" {} \; -a -quit
</code></pre>


blocks|key|191228|text|你可以使用下面的命令，如果你想要打印整个行和文件名，如果你正在搜索的当前目录中出现特定的单词。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|191229|grep+-m+1+-r+"Not+caching"+*+%7C+head+-1|code-block|syntax|javascript|191230|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>You can use below command if you want to print entire line and file name if the occurrence of particular word in current directory you are searching.</p>

<pre><code>grep -m 1 -r "Not caching" * | head -1
</code></pre>


blocks|key|191273|text|阅读grep手册(man+grep)这是使用扩展regexp查找第一个匹配的最小命令。在我的笔记本电脑中获取以太网名称的例子不是eth0！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|191274|$+ifconfing+%7C+grep+-E+-o+-m+1+"%5E[a-z0-9]%2B"|code-block|syntax|javascript|191275|解释：-E表示扩展正则表达式，-o表示仅返回匹配项，-m为1表示只查找一行|191276|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<p>Reading the grep manual (man grep) this is the minimum command to find first match with Extended regexp. Example getting the ethernet name that in my laptop is NOT eth0 !</p>
<pre><code>$ ifconfing | grep -E -o -m 1 &quot;^[a-z0-9]+&quot;
</code></pre>
<p>Explanation:
-E for extended regexp,
-o to return only the match,
-m 1 to look only one line</p>


<p>I'm searching a directory recursively using grep with the following arguments hoping to only return the first match. Unfortunately, it returns more than one -- in-fact two the last time I looked. It seems like I have too many arguments, especially without getting the  desired outcome. :-/</p>

<pre><code># grep -o -a -m 1 -h -r "Pulsanti Operietur" /path/to/directory
</code></pre>

<p>returns:</p>

<pre><code>Pulsanti Operietur
Pulsanti Operietur
</code></pre>

<p>Maybe grep isn't the best way to do this? You tell me, thanks very much.</p>


Grep only the first match and stop

我使用grep递归地搜索目录，并使用以下参数，希望只返回第一个匹配项。不幸的是，它返回的不止一个--实际上是我上次查看时返回的两个。我似乎有太多的争论，特别是没有得到想要的结果。:-/# grep -o -a -m 1 -h -r "Pulsanti Operietur" /path/to/directory返回：Pu...

问仅对第一个匹配项执行Grep并停止
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问仅对第一个匹配项执行Grep并停止EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问仅对第一个匹配项执行Grep并停止
EN