如何删除NSString右端的空格？
如何删除NSString右端的空格？
提问于 2011-04-17 04:11:31
这将删除字符串两端的空格：
NSString *newString = [oldString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];如何删除字符串右端的空格？
更新:来自accepted answer的代码现在是SSToolkit的一部分。耶！
回答 3
Stack Overflow用户
回答已采纳
发布于 2011-04-17 12:53:30
基于@Regexident和@Max的答案，我想出了以下方法：
@implementation NSString (SSToolkitAdditions)
#pragma mark Trimming Methods
- (NSString *)stringByTrimmingLeadingCharactersInSet:(NSCharacterSet *)characterSet {
NSRange rangeOfFirstWantedCharacter = [self rangeOfCharacterFromSet:[characterSet invertedSet]];
if (rangeOfFirstWantedCharacter.location == NSNotFound) {
return @"";
}
return [self substringFromIndex:rangeOfFirstWantedCharacter.location];
}
- (NSString *)stringByTrimmingLeadingWhitespaceAndNewlineCharacters {
return [self stringByTrimmingLeadingCharactersInSet:
[NSCharacterSet whitespaceAndNewlineCharacterSet]];
}
- (NSString *)stringByTrimmingTrailingCharactersInSet:(NSCharacterSet *)characterSet {
NSRange rangeOfLastWantedCharacter = [self rangeOfCharacterFromSet:[characterSet invertedSet]
options:NSBackwardsSearch];
if (rangeOfLastWantedCharacter.location == NSNotFound) {
return @"";
}
return [self substringToIndex:rangeOfLastWantedCharacter.location+1]; // non-inclusive
}
- (NSString *)stringByTrimmingTrailingWhitespaceAndNewlineCharacters {
return [self stringByTrimmingTrailingCharactersInSet:
[NSCharacterSet whitespaceAndNewlineCharacterSet]];
}
@end下面是GHUnit测试，这些测试都通过了：
@interface StringCategoryTest : GHTestCase
@end
@implementation StringCategoryTest
- (void)testStringByTrimmingLeadingCharactersInSet {
NSCharacterSet *letterCharSet = [NSCharacterSet letterCharacterSet];
GHAssertEqualObjects([@"zip90210zip" stringByTrimmingLeadingCharactersInSet:letterCharSet], @"90210zip", nil);
}
- (void)testStringByTrimmingLeadingWhitespaceAndNewlineCharacters {
GHAssertEqualObjects([@"" stringByTrimmingLeadingWhitespaceAndNewlineCharacters], @"", nil);
GHAssertEqualObjects([@"\n \n " stringByTrimmingLeadingWhitespaceAndNewlineCharacters], @"", nil);
GHAssertEqualObjects([@"\n hello \n" stringByTrimmingLeadingWhitespaceAndNewlineCharacters], @"hello \n", nil);
}
- (void)testStringByTrimmingTrailingCharactersInSet {
NSCharacterSet *letterCharSet = [NSCharacterSet letterCharacterSet];
GHAssertEqualObjects([@"zip90210zip" stringByTrimmingTrailingCharactersInSet:letterCharSet], @"zip90210", nil);
}
- (void)testStringByTrimmingTrailingWhitespaceAndNewlineCharacters {
GHAssertEqualObjects([@"" stringByTrimmingLeadingWhitespaceAndNewlineCharacters], @"", nil);
GHAssertEqualObjects([@"\n \n " stringByTrimmingLeadingWhitespaceAndNewlineCharacters], @"", nil);
GHAssertEqualObjects([@"\n hello \n" stringByTrimmingTrailingWhitespaceAndNewlineCharacters], @"\n hello", nil);
}
@end我向SSToolkit提交了一个添加了这些方法的GitHub拉取请求。
Stack Overflow用户
发布于 2011-04-17 05:44:59
NSString* str = @"hdskfh dsakjfh akhf kasdhfk asdfkjash fkadshf1234 ";
NSRange rng = [str rangeOfCharacterFromSet: [NSCharacterSet characterSetWithCharactersInString: [str stringByReplacingOccurrencesOfString: @" " withString: @""]] options: NSBackwardsSearch];
str = [str substringToIndex: rng.location+1];Stack Overflow用户
发布于 2012-06-21 08:09:55
当最后一个非尾随字符是多字节时，需要稍微更改一下：
- (NSString *)stringByTrimmingTrailingCharactersInSet:(NSCharacterSet *)characterSet {
NSRange rangeOfLastWantedCharacter = [self rangeOfCharacterFromSet:[characterSet invertedSet]
options:NSBackwardsSearch];
if (rangeOfLastWantedCharacter.location == NSNotFound) {
return @"";
}
return [self substringToIndex:rangeOfLastWantedCharacter.location + rangeOfLastWantedCharacter.length]; // non-inclusive
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/5689288
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