blocks|key|1525769|text|ls+-Art+%7C+tail+-n+1|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1525770|不是很优雅，但很管用。|unstyled|1525771|使用的标志：|1525772|-A列出除.和..之外的所有文件|offset|length|style|CODE|1525773|排序时的-r逆序|1525774|-t按时间排序，最新的在前|1525775|entityMap^0|0|0|0|0|2|5|1|7|2|0|4|2|0|0|2|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|V|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|F|7|X|8|@$K|Y|L|Z|M|N]|$K|10|L|11|M|N]|$K|12|L|13|M|N]]|9|@]|A|$]]|$1|O|3|P|5|F|7|14|8|@$K|15|L|16|M|N]]|9|@]|A|$]]|$1|Q|3|R|5|F|7|17|8|@$K|18|L|19|M|N]]|9|@]|A|$]]|$1|S|3|-4|5|F|7|1A|8|@]|9|@]|A|$]]]|T|$]]

<pre><code>ls -Art | tail -n 1
</code></pre>
Not very elegant, but it works.
Used flags:
<code>-A</code> list all files except <code>.</code> and <code>..</code>
<code>-r</code> reverse order while sorting
<code>-t</code> sort by time, newest first

blocks|key|1525794|text|ls+-t+%7C+head+-n1|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1525795|这个命令实际上给出了当前工作目录中最近修改过的文件。|unstyled|1525796|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>ls -t | head -n1
</code></pre>

This command actually gives the latest modified file in the current working directory.

blocks|key|1310770|text|我使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1310771|ls+-ABrt1+--group-directories-first+%7C+tail+-n1|offset|length|style|CODE|1310772|它只给我文件名，不包括文件夹。|1310773|entityMap^0|0|0|1A|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|K|$]]

I use:

<code>ls -ABrt1 --group-directories-first | tail -n1</code>

It gives me just the file name, excluding folders.

blocks|key|1310748|text|ls+-lAtr+%7C+tail+-1|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1310749|其他解决方案不包括以'.'开头的文件。|1310750|此命令还将包含'.'和'..'，这可能是您想要的，也可能不是：|1310751|ls+-latr+%7C+tail+-1|1310752|entityMap^0|0|I|0|A|3|0|7|3|B|4|0|0|I|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|T|8|@$9|U|A|V|B|C]|$9|W|A|X|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|L|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|M|$]]

<code>ls -lAtr | tail -1</code>

The other solutions do not include files that start with <code>'.'</code>.

This command will also include <code>'.'</code> and <code>'..'</code>, which may or may not be what you want:

<code>ls -latr | tail -1</code>

blocks|key|1310783|text|我喜欢echo+*(om[1])+(zsh语法)，因为它只给出文件名，而不调用任何其他命令。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1310784|entityMap^0|3|D|I|3|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

I like <code>echo *(om[1])</code> (<code>zsh</code> syntax) as that just gives the file name and doesn't invoke any other command.

blocks|key|1526069|text|在文件数量变得非常大(比如整个文件系统)之前，查找/排序解决方案非常有效。改用awk来跟踪最新的文件：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1526070|find+$DIR+-type+f+-printf+"%25T@+%25p\n"+%7C+
awk+'
BEGIN+{+recent+=+0;+file+=+""+}
{
if+($1+>+recent)
+++{
+++recent+=+$1;
+++file+=+$0;
+++}
}
END+{+print+file;+}'+%7C
sed+'s/%5E[0-9]*\.[0-9]*+//'|code-block|syntax|javascript|1526071|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The find / sort solution works great until the number of files gets really large (like an entire file system). Use awk instead to just keep track of the most recent file:

<pre><code>find $DIR -type f -printf "%T@ %p\n" | 
awk '
BEGIN { recent = 0; file = "" }
{
if ($1 &gt; recent)
 {
 recent = $1;
 file = $0;
 }
}
END { print file; }' |
sed 's/^[0-9]*\.[0-9]* //'
</code></pre>

blocks|key|1526170|text|基于dmckee的答案的简短变体：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1526171|ls+-t+%7C+head+-1|code-block|syntax|javascript|1526172|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Shorted variant based on dmckee's answer:

<pre><code>ls -t | head -1
</code></pre>

blocks|key|1525928|text|我个人喜欢使用尽可能少的非内置bash命令(以减少昂贵的fork和exec+syscall的数量)。要按日期排序，需要调用ls。但是使用head并不是真正必要的。我使用以下一行(仅适用于支持名称管道的系统)：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1525929|read+newest+<+<(ls+-t+*.log)|code-block|syntax|javascript|1525930|或获取最旧文件的名称|1525931|read+oldest+<+<(ls+-rt+*.log)|1525932|(注意两个'<‘标记之间的空格！)|1525933|如果还需要隐藏文件，可以添加-A+arg。|1525934|我希望这能有所帮助。|1525935|entityMap^0|F|4|1P|2|1W|4|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|14|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|16|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|17|8|@]|D|@]|E|$]]|$1|S|3|T|5|6|7|18|8|@]|D|@]|E|$]]|$1|U|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|V|$]]

I personally prefer to use as few not built-in <code>bash</code> commands as I can (to reduce the number of expensive fork and exec syscalls). To sort by date the <code>ls</code> needed to be called. But using of <code>head</code> is not really necessary. I use the following one-liner (works only on systems supporting name pipes):

<pre><code>read newest &lt; &lt;(ls -t *.log)
</code></pre>

or to get the name of the oldest file

<pre><code>read oldest &lt; &lt;(ls -rt *.log)
</code></pre>

(Mind the space between the two '&lt;' marks!)

If the hidden files are also needed -A arg could be added.

I hope this could help.

blocks|key|1526350|text|使用R递归选项..你可以认为这是一个很好的答案的增强。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1526351|ls+-arRtlh+%7C+tail+-50|code-block|syntax|javascript|1526352|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

using R recursive option .. you may consider this as enhancement for good answers here 

<pre><code>ls -arRtlh | tail -50
</code></pre>

blocks|key|1311312|text|只有Bash内置，紧跟着BashFAQ/003|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1311313|shopt+-s+nullglob

for+f+in+*+.*;+do
++++[[+-d+$f+]]+&&+continue
++++[[+$f+-nt+$latest+]]+&&+latest=$f
done

printf+'%25s\n'+"$latest"|code-block|syntax|javascript|1311314|entityMap|0|LINK|mutability|MUTABLE|url|https://mywiki.wooledge.org/BashFAQ/003^0|C|B|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

With only Bash builtins, closely following <a href="https://mywiki.wooledge.org/BashFAQ/003" rel="nofollow noreferrer">BashFAQ/003</a>:
<pre class="lang-sh prettyprint-override"><code>shopt -s nullglob

for f in * .*; do
 [[ -d $f ]] &amp;&amp; continue
 [[ $f -nt $latest ]] &amp;&amp; latest=$f
done

printf '%s\n' &quot;$latest&quot;
</code></pre>

blocks|key|1525876|text|试试这个简单的命令|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1525877|ls+-ltq++<path>++%7C+head+-n+1|code-block|syntax|javascript|1525878|如果要修改文件名，请使用path+=+/ab/cd/*.log|1525879|如果要修改目录名，请使用path+=+/ab/cd/*/|1525880|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

try this simple command

<pre><code>ls -ltq &lt;path&gt; | head -n 1
</code></pre>

If you want file name - last modified, path = /ab/cd/*.log

If you want directory name - last modified, path = /ab/cd/*/

blocks|key|1526030|text|ls+-t+-1+%7C+sed+'1q'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1526031|将显示文件夹中上次修改的项目。与grep配对以查找具有关键字的最新条目|unstyled|offset|length|style|CODE|1526032|ls+-t+-1+%7C+grep+foo+%7C+sed+'1q'|1526033|entityMap^0|0|G|4|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|M|3|-4|5|F|7|T|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>ls -t -1 | sed '1q'
</code></pre>

Will show the last modified item in the folder. Pair with <code>grep</code> to find latest entries with keywords

<pre><code>ls -t -1 | grep foo | sed '1q'
</code></pre>

blocks|key|1311124|text|递归地：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1311125|find+$1+-type+f+-exec+stat+--format+'%25Y+:%25y+%25n'+"{}"+\;+%7C+sort+-nr+%7C+cut+-d:+-f2-+%7C+head|code-block|syntax|javascript|1311126|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Recursively:

<pre><code>find $1 -type f -exec stat --format '%Y :%y %n' "{}" \; | sort -nr | cut -d: -f2- | head
</code></pre>

blocks|key|1526130|text|根据模式查找每个目录中最新的文件，例如工作目录下名称以tmp结尾的子目录(不区分大小写)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1526131|find+.+-iname+\*tmp+-type+d+-exec+sh+-c+"ls+-lArt+{}+%7C+tail+-n+1"+\;|code-block|syntax|javascript|1526132|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Finding the most current file in every directory according to a pattern, e.g. the sub directories of the working directory that have name ending with "tmp" (case insensitive):

<pre><code>find . -iname \*tmp -type d -exec sh -c "ls -lArt {} | tail -n 1" \;
</code></pre>

blocks|key|1526281|text|假设您不关心以.开头的隐藏文件|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1526282|ls+-rt+%7C+tail+-n+1|code-block|syntax|javascript|1526283|否则|1526284|ls+-Art+%7C+tail+-n+1|1526285|entityMap^0|7|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

Presuming you don't care about hidden files that start with a <code>.</code>

<pre><code>ls -rt | tail -n 1
</code></pre>

Otherwise

<pre><code>ls -Art | tail -n 1
</code></pre>

blocks|key|1311283|text|ls+-Frt+%7C+grep+"[%5E/]$"+%7C+tail+-n+1|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1311284|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|1525966|text|我也需要这样做，我找到了这些命令。这些对我来说是有效的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1525967|如果您想要最后一个文件在文件夹中的创建日期(访问时间)：|1525968|ls+-Aru+%7C+tail+-n+1++|code-block|syntax|javascript|1525969|如果您想要内容(修改时间)发生变化的最后一个文件：|1525970|ls+-Art+%7C+tail+-n+1++|1525971|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I needed to do it too, and I found these commands. these work for me:

If you want last file by its date of creation in folder(access time) :

<pre><code>ls -Aru | tail -n 1 
</code></pre>

And if you want last file that has changes in its content (modify time) :

<pre><code>ls -Art | tail -n 1 
</code></pre>

Looking for a command that will return the single most recent file in a directory.
Not seeing a limit parameter to <code>ls</code>...

Get most recent file in a directory on Linux

查找将返回目录中单个最新文件的命令。看不到ls的限制参数...

问在Linux上获取目录中的最新文件
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回答 17

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