blocks|key|413122|text|>>>+import+time
>>>+import+datetime
>>>+s+=+"01/12/2011"
>>>+time.mktime(datetime.datetime.strptime(s,+"%25d/%25m/%25Y").timetuple())
1322697600.0|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|413123|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>&gt;&gt;&gt; import time
&gt;&gt;&gt; import datetime
&gt;&gt;&gt; s = "01/12/2011"
&gt;&gt;&gt; time.mktime(datetime.datetime.strptime(s, "%d/%m/%Y").timetuple())
1322697600.0
</code></pre>

blocks|key|628376|text|我使用的是ciso8601，它比datetime的strptime快62倍。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|628377|t+=+"01/12/2011"
ts+=+ciso8601.parse_datetime(t)
#+to+get+time+in+seconds:
time.mktime(ts.timetuple())|code-block|syntax|javascript|628378|您可以了解更多here。|628379|entityMap|0|LINK|mutability|MUTABLE|url|https://pypi.python.org/pypi/ciso8601^0|5|8|0|0|7|4|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|M|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

I use <code>ciso8601</code>, which is 62x faster than datetime's strptime.
<pre><code>t = &quot;01/12/2011&quot;
ts = ciso8601.parse_datetime(t)
# to get time in seconds:
time.mktime(ts.timetuple())
</code></pre>
You can learn more <a href="https://pypi.python.org/pypi/ciso8601" rel="nofollow noreferrer">here</a>.

blocks|key|413114|text|>>>+int(datetime.datetime.strptime('01/12/2011',+'%25d/%25m/%25Y').strftime("%25s"))
1322683200|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|413115|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>&gt;&gt;&gt; int(datetime.datetime.strptime('01/12/2011', '%d/%m/%Y').strftime("%s"))
1322683200
</code></pre>

blocks|key|628526|text|只需使用datetime.datetime.strptime|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|628527|import+datetime
stime+=+"01/12/2011"
print(datetime.datetime.strptime(stime,+"%25d/%25m/%25Y").timestamp())|code-block|syntax|javascript|628528|结果：|628529|1322697600|628530|要使用协调时而不是本地时区，请使用.replace|628531|datetime.datetime.strptime(stime,+"%25d/%25m/%25Y").replace(tzinfo=datetime.timezone.utc).timestamp()|628532|entityMap^0|4|Q|0|0|0|0|H|8|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|T|$]]

Simply use <code>datetime.datetime.strptime</code>:

<pre><code>import datetime
stime = "01/12/2011"
print(datetime.datetime.strptime(stime, "%d/%m/%Y").timestamp())
</code></pre>

Result:

<pre><code>1322697600
</code></pre>

To use UTC instead of the local timezone use <code>.replace</code>:

<pre><code>datetime.datetime.strptime(stime, "%d/%m/%Y").replace(tzinfo=datetime.timezone.utc).timestamp()
</code></pre>

blocks|key|413228|text|答案还取决于您的输入日期时区。如果你的约会是本地日期，那么你可以像katrielalex说的那样使用mktime()+--只是我不明白他为什么用datetime而不是这个更短的版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|413229|>>>+time.mktime(time.strptime('01/12/2011',+"%25d/%25m/%25Y"))
1322694000.0|code-block|syntax|javascript|413230|但是请注意，我的结果与他的不同，因为我可能在不同的TZ+(结果是无时区的UNIX时间戳)|413231|现在，如果输入日期已经是UTC格式，那么我认为正确的解决方案是：|413232|>>>+calendar.timegm(time.strptime('01/12/2011',+'%25d/%25m/%25Y'))
1322697600|413233|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

The answer depends also on your input date timezone. If your date is a local date, then you can use mktime() like katrielalex said - only I don't see why he used datetime instead of this shorter version:

<pre><code>&gt;&gt;&gt; time.mktime(time.strptime('01/12/2011', "%d/%m/%Y"))
1322694000.0
</code></pre>

But observe that my result is different than his, as I am probably in a different TZ (and the result is timezone-free UNIX timestamp)

Now if the input date is already in UTC, than I believe the right solution is:

<pre><code>&gt;&gt;&gt; calendar.timegm(time.strptime('01/12/2011', '%d/%m/%Y'))
1322697600
</code></pre>

blocks|key|413193|text|首先，必须使用strptime类将字符串转换为struct_time格式。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|413194|然后从那里使用mktime来获得你的浮动。|413195|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/library/time.html#time.strptime|1|http://docs.python.org/library/time.html#time.mktime^0|7|8|0|0|7|6|1|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|F|3|-4|5|6|7|X|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]|N|$5|I|J|K|C|$L|O]]]]

First you must the <a href="http://docs.python.org/library/time.html#time.strptime" rel="noreferrer">strptime</a> class to convert the string to a struct_time format. 

Then just use <a href="http://docs.python.org/library/time.html#time.mktime" rel="noreferrer">mktime</a> from there to get your float.

blocks|key|628381|text|我建议使用dateutil|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|628382|import+dateutil.parser
dateutil.parser.parse("01/12/2011",+dayfirst=True).timestamp()|code-block|syntax|javascript|628383|entityMap|0|LINK|mutability|MUTABLE|url|http://labix.org/python-dateutil^0|5|8|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

I would suggest <a href="http://labix.org/python-dateutil" rel="nofollow noreferrer">dateutil</a>:

<pre><code>import dateutil.parser
dateutil.parser.parse("01/12/2011", dayfirst=True).timestamp()
</code></pre>

blocks|key|413363|text|似乎相当有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|413364|import+datetime
day,+month,+year+=+'01/12/2011'.split('/')
datetime.datetime(int(year),+int(month),+int(day)).timestamp()|code-block|syntax|javascript|413365|每个环路1.61µs±120+ns+(平均值±标准dev.共7次运行，每次100000次循环)|413366|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Seems to be quite efficient:

<pre><code>import datetime
day, month, year = '01/12/2011'.split('/')
datetime.datetime(int(year), int(month), int(day)).timestamp()
</code></pre>

1.61 µs ± 120 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)

blocks|key|413511|text|您可以转换为isoformat|type|unstyled|depth|inlineStyleRanges|entityRanges|data|413512|my_date+=+'2020/08/08'
my_date+=+my_date.replace('/','-')+#+just+to+adapte+to+your+question
date_timestamp+=+datetime.datetime.fromisoformat(my_date).timestamp()|code-block|syntax|javascript|413513|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can convert to isoformat 

<pre><code>my_date = '2020/08/08'
my_date = my_date.replace('/','-') # just to adapte to your question
date_timestamp = datetime.datetime.fromisoformat(my_date).timestamp()
</code></pre>

blocks|key|628601|text|您可以参考以下链接从datetime.datetime中使用strptime函数，以将日期从任何格式转换为时区。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|628602|https://docs.python.org/3/library/datetime.html#strftime-and-strptime-behavior|628603|entityMap|0|LINK|mutability|MUTABLE|url^0|A|H|U|8|0|0|26|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@]|D|@$9|U|A|V|1|W]]|E|$]]|$1|H|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|G]]]]

You can refer this following link for using <code>strptime</code> function from <code>datetime.datetime</code>, to convert date from any format along with time zone.

<a href="https://docs.python.org/3/library/datetime.html#strftime-and-strptime-behavior" rel="nofollow noreferrer">https://docs.python.org/3/library/datetime.html#strftime-and-strptime-behavior</a>

blocks|key|413294|text|只需使用datetime.timestamp(您的datetime实例)，datetime实例包含时区信息，因此时间戳将是标准的utc时间戳。如果您将日期时间转换为timetuple，它将丢失它的时区，因此结果将是错误的。如果你想提供一个接口，你应该这样写:+int(datetime.timestamp(time_instance))+*+1000|type|unstyled|depth|inlineStyleRanges|entityRanges|data|413295|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

just use datetime.timestamp(your datetime instanse), datetime instance contains the timezone infomation, so the timestamp will be a standard utc timestamp. if you transform the datetime to timetuple, it will lose it's timezone, so the result will be error.
if you want to provide an interface, you should write like this:
 int(datetime.timestamp(time_instance)) * 1000

How to convert a string in the format <code>"%d/%m/%Y"</code> to timestamp?

<pre><code>"01/12/2011" -&gt; 1322697600
</code></pre>

Convert string date to timestamp in Python

如何将"%d/%m/%Y"格式的字符串转换为时间戳？"01/12/2011" -> 1322697600

问在Python中将字符串日期转换为时间戳
EN

回答 11

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在Python中将字符串日期转换为时间戳EN

回答 11

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在Python中将字符串日期转换为时间戳
EN