blocks|key|2916979|text|对于PHP+>=+5.3.0尝试|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2916980|PHP+magic+constants。|2916981|__DIR__|code-block|syntax|javascript|2916982|并使您的路径成为相对路径。|2916983|对于PHP+<+5.3.0尝试|2916984|dirname(__FILE__)|2916985|entityMap|0|LINK|mutability|MUTABLE|url|http://www.php.net/manual/en/language.constants.predefined.php^0|2|C|0|4|F|0|0|0|0|2|B|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@]|D|@$9|14|A|15|1|16]]|E|$]]|$1|H|3|I|5|J|7|17|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|18|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|J|7|1C|8|@]|D|@]|E|$K|L]]|$1|S|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

For PHP >= 5.3.0 try

PHP <a href="http://www.php.net/manual/en/language.constants.predefined.php" rel="noreferrer">magic constants</a>.

<pre><code>__DIR__
</code></pre>

And make your path relative.

For PHP &lt; 5.3.0 try

<pre><code>dirname(__FILE__)
</code></pre>

blocks|key|2917029|text|当你这么说的时候|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2917030|$_SERVER['DOCUMENT_ROOT']|code-block|syntax|javascript|2917031|包含以下路径：|2917032|D:/workspace|2917033|那么D:就是你要找的，不是吗？在这种情况下，您可以通过斜杠分解字符串并返回第一个字符串：|offset|length|style|CODE|2917034|$pathInPieces+=+explode('/',+$_SERVER['DOCUMENT_ROOT']);
echo+$pathInPieces[0];|2917035|这将输出服务器的根目录。|2917036|当你使用常量DIRECTORY_SEPARATOR而不是硬编码的斜杠('/')时，这段代码也可以在下运行。|BOLD|2917037|更新2:+$_SERVER全局变量并不总是可用。例如，在命令行(cli)上。因此，您应该使用__DIR__而不是$_SERVER['DOCUMENT_ROOT']。__DIR__返回php文件本身的路径。|2917038|entityMap^0|0|0|0|0|2|2|0|0|0|6|J|Z|3|1D|4|0|0|4|5|2P|5|8|1A|7|1K|P|2A|7|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|13|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|15|8|@$M|16|N|17|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|18|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|19|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|1A|8|@$M|1B|N|1C|O|P]|$M|1D|N|1E|O|P]|$M|1F|N|1G|O|W]]|9|@]|A|$]]|$1|X|3|Y|5|6|7|1H|8|@$M|1I|N|1J|O|W]|$M|1K|N|1L|O|W]|$M|1M|N|1N|O|P]|$M|1O|N|1P|O|P]|$M|1Q|N|1R|O|P]|$M|1S|N|1T|O|P]]|9|@]|A|$]]|$1|Z|3|-4|5|6|7|1U|8|@]|9|@]|A|$]]]|10|$]]

When you say that

<pre><code>$_SERVER['DOCUMENT_ROOT']
</code></pre>

contains this path:

<pre><code>D:/workspace
</code></pre>

Then <code>D:</code> is what you are looking for, isn't it?
In that case you could explode the string by slashes and return the first one:

<pre><code>$pathInPieces = explode('/', $_SERVER['DOCUMENT_ROOT']);
echo $pathInPieces[0];
</code></pre>

This will output the server's root directory.

Update: When you use the constant <code>DIRECTORY_SEPARATOR</code> instead of the hardcoded slash (<code>'/'</code>) this code is also working under Windows.

Update 2: The <code>$_SERVER</code> global variable is not always available. On command line (cli) for example. So you should use <code>__DIR__</code> instead of <code>$_SERVER['DOCUMENT_ROOT']</code>. <code>__DIR__</code> returns the path of the php file itself.

blocks|key|3131252|text|使用PHP函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3131253|getcwd()|offset|length|style|CODE|3131254|获取当前工作目录。|3131255|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.getcwd.php^0|0|0|8|0|8|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@$D|T|E|U|F|G]]|9|@$D|V|E|W|1|X]]|A|$]]|$1|H|3|I|5|6|7|Y|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|Q]]]]

use the PHP function:

<a href="http://php.net/manual/en/function.getcwd.php" rel="noreferrer"><code>getcwd()</code></a>

Gets the current working directory.

blocks|key|3131278|text|我想指出Wordpress处理这个问题的方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3131279|define(+'ABSPATH',+dirname(+__FILE__+)+.+'/'+);|code-block|syntax|javascript|3131280|由于Wordpress在网络上的使用率非常高，而且在本地也运行得很好，所以我非常信任这种方法。你可以在wordpress+wp-config.php文件的底部找到这个定义。|offset|length|style|CODE|3131281|entityMap^0|0|0|1P|D|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I want to point to the way Wordpress handles this:
<pre><code>define( 'ABSPATH', dirname( __FILE__ ) . '/' );
</code></pre>
As Wordpress is very heavy used all over the web and also works fine locally I have much trust in this method. You can find this definition on the bottom of your wordpress <code>wp-config.php</code> file

blocks|key|245313|text|目前，PHP本身还没有提供一种方法来确定项目的根目录。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|245314|但是您可以自己实现一个非常简单的方法，它将准确地实现您正在寻找的东西。|245315|解决方案|offset|length|style|BOLD|245316|在您的项目中创建一个新文件，比如D:/workspace/MySystem/Code/FilesManager.php+(使用最适合您的名称和路径)。然后，使用以下代码：|CODE|245317|<?php

class+FilesManager
{
++public+static+function+rootDirectory()
++{
++++//+Change+the+second+parameter+to+suit+your+needs
++++return+dirname(__FILE__,+2);
++}
}|code-block|syntax|javascript|245318|现在，您可以在D:/workspace/MySystem/Code/a/b/c/Feature.php中执行此操作|245319|echo+FilesManager::rootDirectory();|245320|而预期的结果应该是：|245321|"D:/workspace/MySystem"|245322|无论您的"feature“文件位于项目中的哪个位置，输出都是相同的。|245323|说明|245324|dirname用于返回第一个参数的父目录。我们使用magic+constant+__FILE__来告诉它FilesManager.php的路径。第二个参数告诉它在层次结构中向上移动的次数。在这种情况下，我们需要做两次，但它实际上取决于你把你的文件放在层次结构中的什么位置。如果你只需要起来一次，你可以省略第二个参数，这意味着文件位于根目录。但是，你可以直接返回__DIR__。|245325|无论根目录位于服务器上的什么位置，都可以保证此解决方案有效。除非您最终将实用程序类移动到层次结构中的其他位置。|245326|附加说明|245327|出于以下原因，我会避免使用DOCUMENT_ROOT+(根据这个answer)：|245328|245329|它使您的应用程序依赖于服务器。|unordered-list-item|245330|+Apache安装程序可能会给出不正确的根目录路径。|245331|245332|entityMap|0|LINK|mutability|MUTABLE|url|https://www.php.net/manual/en/function.dirname.php|1|https://www.php.net/manual/en/language.constants.predefined.php|2|https://expressionengine.stackexchange.com/a/2178^0|0|0|0|4|0|G|17|0|0|7|18|0|0|0|0|0|0|2|0|14|8|1G|G|50|7|0|7|0|P|E|1|0|0|0|4|0|W|6|2|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1V|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|1W|8|@$F|1X|G|1Y|H|I]]|9|@]|A|$]]|$1|J|3|K|5|6|7|1Z|8|@$F|20|G|21|H|L]]|9|@]|A|$]]|$1|M|3|N|5|O|7|22|8|@]|9|@]|A|$P|Q]]|$1|R|3|S|5|6|7|23|8|@$F|24|G|25|H|L]]|9|@]|A|$]]|$1|T|3|U|5|O|7|26|8|@]|9|@]|A|$P|Q]]|$1|V|3|W|5|6|7|27|8|@]|9|@]|A|$]]|$1|X|3|Y|5|O|7|28|8|@]|9|@]|A|$P|Q]]|$1|Z|3|10|5|6|7|29|8|@]|9|@]|A|$]]|$1|11|3|12|5|6|7|2A|8|@$F|2B|G|2C|H|I]]|9|@]|A|$]]|$1|13|3|14|5|6|7|2D|8|@$F|2E|G|2F|H|L]|$F|2G|G|2H|H|L]|$F|2I|G|2J|H|L]]|9|@$F|2K|G|2L|1|2M]|$F|2N|G|2O|1|2P]]|A|$]]|$1|15|3|16|5|6|7|2Q|8|@]|9|@]|A|$]]|$1|17|3|18|5|6|7|2R|8|@$F|2S|G|2T|H|I]]|9|@]|A|$]]|$1|19|3|1A|5|6|7|2U|8|@]|9|@$F|2V|G|2W|1|2X]]|A|$]]|$1|1B|3|-4|5|6|7|2Y|8|@]|9|@]|A|$]]|$1|1C|3|1D|5|1E|7|2Z|8|@]|9|@]|A|$]]|$1|1F|3|1G|5|1E|7|30|8|@]|9|@]|A|$]]|$1|1H|3|-4|5|6|7|31|8|@]|9|@]|A|$]]|$1|1I|3|-4|5|6|7|32|8|@]|9|@]|A|$]]]|1J|$1K|$5|1L|1M|1N|A|$1O|1P]]|1Q|$5|1L|1M|1N|A|$1O|1R]]|1S|$5|1L|1M|1N|A|$1O|1T]]]]

At this moment, PHP itself does not provide a way to get the project's root directory for sure.
But you can implement a very simple method yourself that will do exactly what you're looking for.
Solution
Create a new file in your project, let say <code>D:/workspace/MySystem/Code/FilesManager.php</code> (use whatever name and path suit you the best). Then, use the following code:
<pre><code>&lt;?php

class FilesManager
{
 public static function rootDirectory()
 {
 // Change the second parameter to suit your needs
 return dirname(__FILE__, 2);
 }
}
</code></pre>
Now you can do this in, let's say <code>D:/workspace/MySystem/Code/a/b/c/Feature.php</code>:
<pre><code>echo FilesManager::rootDirectory();
</code></pre>
And the expected result should be:
<pre><code>&quot;D:/workspace/MySystem&quot;
</code></pre>
The output will be the same no matter where your &quot;feature&quot; file is located in the project.
Explanation
<a href="https://www.php.net/manual/en/function.dirname.php" rel="noreferrer">dirname</a> is used to return the parent directory of the first parameter. We use the <a href="https://www.php.net/manual/en/language.constants.predefined.php" rel="noreferrer">magic constant</a> <code>__FILE__</code> to give it <code>FilesManager.php</code>'s path. The second parameter tells how many times to go up in the hierarchy. In this case, we need to do it twice, but it really depends where you put your file in the hierarchy. You can omit the second parameter if you only need to got up once, meaning the file is located in the root. But then, you can return <code>__DIR__</code> directly instead.
This solution is guaranteed to work, no matter where the root is located on your server. Unless you end up moving the utility class somewhere else in the hierarchy.
Additional note
I'd avoid using DOCUMENT_ROOT for the following reasons (according to this <a href="https://expressionengine.stackexchange.com/a/2178">answer</a>):
<ul>
<li>It makes your application dependent on the server.</li>
<li>The Apache setup may give an incorrect path to the root directory.</li>
</ul>

blocks|key|3131183|text|你可以试试：$_SERVER['PATH_TRANSLATED']|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3131184|引用：|3131185|3131186|文件系统-在服务器完成任何虚拟到真实的映射之后，指向当前脚本的基于路径(不是文档根目录)。注意:从PHP4.3.2开始，不再在Apache2SAPI下隐式设置PATH_TRANSLATED，这与Apache1中的情况不同，在Apache1中，当服务器变量不是由Apache填充时，它被设置为与SCRIPT_FILENAME服务器变量相同的值。|blockquote|3131187|3131188|此更改是为了符合CGI规范，即只有在定义了PATH_INFO时才应存在PATH_TRANSLATED。Apache2用户可以在httpd.conf中使用AcceptPathInfo+=+On来定义PATH_INFO|3131189|3131190|来源：php.net/manual|3131191|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/reserved.variables.server.php^0|6|R|0|0|0|27|F|42|F|0|0|L|9|1R|A|24|J|2Q|9|0|0|3|E|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|12|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|13|8|@]|D|@]|E|$]]|$1|I|3|J|5|K|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|L|3|-4|5|6|7|19|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|1A|8|@$9|1B|A|1C|B|C]|$9|1D|A|1E|B|C]|$9|1F|A|1G|B|C]|$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]|$1|P|3|Q|5|6|7|1K|8|@]|D|@$9|1L|A|1M|1|1N]]|E|$]]|$1|R|3|-4|5|6|7|1O|8|@]|D|@]|E|$]]]|S|$T|$5|U|V|W|E|$X|Y]]]]

you can try:
<code>$_SERVER['PATH_TRANSLATED']</code>

quote:

<blockquote>
 Filesystem- (not document root-) based path to the current script, after the server has done any virtual-to-real mapping. Note: As of PHP 4.3.2, <code>PATH_TRANSLATED</code> is no longer set implicitly under the Apache 2 SAPI in contrast to the situation in Apache 1, where it's set to the same value as the <code>SCRIPT_FILENAME</code> server variable when it's not populated by Apache. 
 This change was made to comply with the CGI specification that PATH_TRANSLATED should only exist if <code>PATH_INFO</code> is defined. Apache 2 users may use <code>AcceptPathInfo = On</code> inside <code>httpd.conf</code> to define <code>PATH_INFO</code>
</blockquote>

source:
<a href="http://php.net/manual/en/reserved.variables.server.php" rel="nofollow noreferrer">php.net/manual</a>

blocks|key|241627|text|echo+$pathInPieces+=+explode(DIRECTORY_SEPARATOR+,+__FILE__);
echo+$pathInPieces[0].DIRECTORY_SEPARATOR;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|241628|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>echo $pathInPieces = explode(DIRECTORY_SEPARATOR , __FILE__);
echo $pathInPieces[0].DIRECTORY_SEPARATOR;
</code></pre>

blocks|key|244009|text|您也可以使用realpath。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|244010|realpath(".")返回您的文档根目录。|style|CODE|244011|您可以使用您的特定路径调用realpath。请注意，如果目标文件夹或文件不存在，它将不起作用。在这种情况下，它将返回false，这对于测试文件是否存在非常有用。|244012|在我的示例中，我需要为要写入磁盘的新文件指定路径，解决方案是附加相对于文档根目录的路径：|244013|$filepath+=+realpath(".")+.+"/path/to/newfile.txt";|244014|希望这对任何人都有帮助。|244015|entityMap|0|LINK|mutability|MUTABLE|url|https://www.php.net/manual/en/function.realpath^0|6|8|0|0|0|D|0|0|0|0|1F|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@$A|Y|B|Z|1|10]]|C|$]]|$1|D|3|E|5|6|7|11|8|@$A|12|B|13|F|G]]|9|@]|C|$]]|$1|H|3|I|5|6|7|14|8|@]|9|@]|C|$]]|$1|J|3|K|5|6|7|15|8|@]|9|@]|C|$]]|$1|L|3|M|5|6|7|16|8|@$A|17|B|18|F|G]]|9|@]|C|$]]|$1|N|3|O|5|6|7|19|8|@]|9|@]|C|$]]|$1|P|3|-4|5|6|7|1A|8|@]|9|@]|C|$]]]|Q|$R|$5|S|T|U|C|$V|W]]]]

You could also use <a href="https://www.php.net/manual/en/function.realpath" rel="nofollow noreferrer">realpath</a>.
<code>realpath(&quot;.&quot;)</code> returns your document root.
You can call realpath with your specific path. Note that it will NOT work if the target folder or file does not exist. In such case it will return false, which could be useful for testing if a file exists.
In my case I needed to specify a path for a new file to be written to disk, and the solution was to append the path relative to document root:
<code>$filepath = realpath(&quot;.&quot;) . &quot;/path/to/newfile.txt&quot;;</code>
Hope this helps anyone.

blocks|key|246544|text|摘要|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|246545|此示例假设您始终知道apache根文件夹的位置为'/var/www/‘，并且您正在尝试查找下一个文件夹路径(例如，'/var/www/my_website_+folder+')。此外，这是从脚本或web浏览器工作的原因，这就是为什么有额外的代码。|246546|代码PHP7|246547|function+getHtmlRootFolder(string+$root+=+'/var/www/')+{

++++//+--+try+to+use+DOCUMENT_ROOT+first+--
++++$ret+=+str_replace('+',+'',+$_SERVER['DOCUMENT_ROOT']);
++++$ret+=+rtrim($ret,+'/')+.+'/';

++++//+--+if+doesn't+contain+root+path,+find+using+this+file's+loc.+path+--
++++if+(!preg_match("#".$root."#",+$ret))+{
++++++$root+=+rtrim($root,+'/')+.+'/';
++++++$root_arr+=+explode("/",+$root);
++++++$pwd_arr+=+explode("/",+getcwd());
++++++$ret+=+$root+.+$pwd_arr[count($root_arr)+-+1];
++++}

++++return+(preg_match("#".$root."#",+$ret))+?+rtrim($ret,+'/')+.+'/'+:+null;
}|code-block|syntax|javascript|246548|示例|246549|echo+getHtmlRootFolder();|246550|输出：|246551|/var/www/somedir/|246552|详情：|246553|基本上，首先尝试获取包含“/var/www/”的DOCUMENT_ROOT，然后使用它，否则获取当前目录(在项目中存在很多)，并根据$root路径的计数获取下一个路径值。注意:添加了rtrim语句，以确保路径在所有情况下都以'/‘结尾。它不会检查它是否要求大于/var/www/，它也可以返回/var/www/作为可能的响应。|246554|entityMap^0|0|2|0|0|0|6|0|0|0|2|0|0|0|0|0|3|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|15|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|16|8|@$9|17|A|18|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|19|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|L|7|1D|8|@]|D|@]|E|$M|N]]|$1|S|3|T|5|6|7|1E|8|@]|D|@]|E|$]]|$1|U|3|V|5|L|7|1F|8|@]|D|@]|E|$M|N]]|$1|W|3|X|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|Y|3|Z|5|6|7|1J|8|@]|D|@]|E|$]]|$1|10|3|-4|5|6|7|1K|8|@]|D|@]|E|$]]]|11|$]]

Summary

This example assumes you always know where the apache root folder is '/var/www/' and you are trying to find the next folder path (e.g. '/var/www/my_website_folder'). Also this works from a script or the web browser which is why there is additional code.

Code PHP7

<pre><code>function getHtmlRootFolder(string $root = '/var/www/') {

 // -- try to use DOCUMENT_ROOT first --
 $ret = str_replace(' ', '', $_SERVER['DOCUMENT_ROOT']);
 $ret = rtrim($ret, '/') . '/';

 // -- if doesn't contain root path, find using this file's loc. path --
 if (!preg_match("#".$root."#", $ret)) {
 $root = rtrim($root, '/') . '/';
 $root_arr = explode("/", $root);
 $pwd_arr = explode("/", getcwd());
 $ret = $root . $pwd_arr[count($root_arr) - 1];
 }

 return (preg_match("#".$root."#", $ret)) ? rtrim($ret, '/') . '/' : null;
}
</code></pre>

Example

<pre><code>echo getHtmlRootFolder();
</code></pre>

Output:

<pre><code>/var/www/somedir/
</code></pre>

Details:

Basically first tries to get DOCUMENT_ROOT if it contains '/var/www/' then use it, else get the current dir (which much exist inside the project) and gets the next path value based on count of the $root path. Note: added rtrim statements to ensure the path returns ending with a '/' in all cases . It doesn't check for it requiring to be larger than /var/www/ it can also return /var/www/ as a possible response.

blocks|key|241712|text|dirname(__FILE__)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|241713|非常有用，但它将获取相对于当前文件URL的当前路径，以防您位于远离根目录的其他目录中，例如includes，您需要从根目录获取文件夹，您可以使用整数参数2，它将向上移动1级，依此类推|unstyled|241714|echo+dirname(__FILE__,+2);|241715|在此之前|241716|C:\laragon\www\x\includes\reports\charts|offset|length|241717|之后|241718|C:\laragon\www\x\reports\charts|241719|reports是根目录x中的文件夹|241720|entityMap|0|LINK|mutability|MUTABLE|url|http://C:%255Claragon%255Cwww%255Cx%255Cincludes%255Creports%255Ccharts|1|http://C:%255Claragon%255Cwww%255Cx%255Creports%255Ccharts^0|0|0|0|0|0|14|0|0|0|0|V|1|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|15|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|16|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|17|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|18|8|@]|9|@$M|19|N|1A|1|1B]]|A|$]]|$1|O|3|P|5|F|7|1C|8|@]|9|@]|A|$]]|$1|Q|3|R|5|F|7|1D|8|@]|9|@$M|1E|N|1F|1|1G]]|A|$]]|$1|S|3|T|5|F|7|1H|8|@]|9|@]|A|$]]|$1|U|3|-4|5|F|7|1I|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]|12|$5|X|Y|Z|A|$10|13]]]]

<pre><code>dirname(__FILE__)
</code></pre>
is useful but will get the current path relative to the current file URL you in incase you are in other directory far from root like includes and you need get folder from the root you can use integer parameter 2 will go 1 level up and so on
<pre><code>echo dirname(__FILE__, 2);
</code></pre>
before
<a href="http://C:%5Claragon%5Cwww%5Cx%5Cincludes%5Creports%5Ccharts" rel="nofollow noreferrer">C:\laragon\www\x\includes\reports\charts</a>
after
<a href="http://C:%5Claragon%5Cwww%5Cx%5Creports%5Ccharts" rel="nofollow noreferrer">C:\laragon\www\x\reports\charts</a>
reports is folder inside the root directory x

blocks|key|241701|text|这对我很有效，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|241702|realpath("../")|code-block|syntax|javascript|241703|您可以使用此../参数来指向。它将指向返回到实际工作文件的1步|offset|length|style|CODE|241704|entityMap^0|0|0|6|3|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

This worked for me,
<pre class="lang-php prettyprint-override"><code>realpath(&quot;../&quot;)
</code></pre>
you can use this <code>../</code> param to point. It will point to 1 step back to your actual working file

I have this folder structure in my PHP project.
(this is as shown in eclips) 

<pre><code>-MySystem
 +Code
 +Data_Access
 -Public_HTML
 +css
 +js
 +Templates
 -resources
</code></pre>

When I try this code

<pre><code>echo $_SERVER['DOCUMENT_ROOT']
</code></pre>

output is

<blockquote>
 D:/workspace
</blockquote>

How can I get the path to RootDirectory of the system (<code>MySystem</code>), without hardcoding the Folder Name?

Get Root Directory Path of a PHP project

我在PHP项目中有这个文件夹结构。(如eclips所示)-MySystem    +Code    +Data_Access    -Public_HTML        +css        +js        +Templates    -resources当我尝试这段代码时echo $_SERVER['DOCUMENT_ROOT']输出为工作区D:/ 如何在不硬编码文件夹名的情况下获得系

问获取PHP项目的根目录路径
EN

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