blocks|key|46701|text|一个简单的解决方案是剥离时间或将其设置为00:00:00，这将始终为您提供所需的结果：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|46702|$date1+=+new+DateTime("2013-08-07");
$date2+=+new+DateTime("2013-08-08");
echo+$date1->diff($date2)->days;|code-block|syntax|javascript|46703|或|46704|$date1+=+new+DateTime("2013-08-07+00:00:00");
$date2+=+new+DateTime("2013-08-08+00:00:00");
echo+$date1->diff($date2)->days;|46705|时间在这里并不重要|46706|entityMap^0|K|8|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

a simple solution to this to strip the time or set it to <code>00:00:00</code>, that should always give you the desired result:

<pre><code>$date1 = new DateTime("2013-08-07");
$date2 = new DateTime("2013-08-08");
echo $date1-&gt;diff($date2)-&gt;days;
</code></pre>

or 

<pre><code>$date1 = new DateTime("2013-08-07 00:00:00");
$date2 = new DateTime("2013-08-08 00:00:00");
echo $date1-&gt;diff($date2)-&gt;days;
</code></pre>

the time doesnt really matter here

blocks|key|46723|text|您可以忽略日期字符串的时间部分|type|unstyled|depth|inlineStyleRanges|entityRanges|data|46724|$date1+=+new+DateTime(date('Y-m-d',+strtotime("2013-08-07+13:00:00")));
$date2+=+new+DateTime(date('Y-m-d',+strtotime("2013-08-08+12:00:00")));
echo+$date1->diff($date2)->days;+//+1|code-block|syntax|javascript|46725|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could ignore the time portion of the date string

<pre><code>$date1 = new DateTime(date('Y-m-d', strtotime("2013-08-07 13:00:00")));
$date2 = new DateTime(date('Y-m-d', strtotime("2013-08-08 12:00:00")));
echo $date1-&gt;diff($date2)-&gt;days; // 1
</code></pre>

blocks|key|263270|text|此示例可帮助您：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|263271|+++$date1+=+date_create($d1);
$date2+=+date_create($d2);
//$FromFullDateTime=$from.$FromTime;

$date1_month+=+date_format($date1,+'d');
$date2_month+=+date_format($date2,+'d');
$dif+=+$date2_month+-+$date1_month;|code-block|syntax|javascript|263272|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

this example can help you:

<pre><code> $date1 = date_create($d1);
$date2 = date_create($d2);
//$FromFullDateTime=$from.$FromTime;

$date1_month = date_format($date1, 'd');
$date2_month = date_format($date2, 'd');
$dif = $date2_month - $date1_month;
</code></pre>

blocks|key|46793|text|请注意，DateInterval->days始终为正。因此使用了->invert。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|46794|/**
+*+return+amount+of+days+between+dt1+and+dt2+
+*+(how+many+midnights+pass+going+from+dt1+to+dt2)
+*++0+=+same+day,+
+*+-1+=+dt2+is+1+day+before+dt1,+
+*++1+=+dt2+is+1+day+after++dt1,+etc.
+*
+*+@param+\DateTime+$dt1
+*+@param+\DateTime+$dt2
+*+@return+int%7Cfalse+
+*/
function+getNightsBetween(\DateTime+$dt1,+\DateTime+$dt2){
++++if(!$dt1+%7C%7C+!$dt2){
++++++++return+false;
++++}
++++$dt1->setTime(0,0,0);
++++$dt2->setTime(0,0,0);
++++$dti+=+$dt1->diff($dt2);++++//+DateInterval
++++return+$dti->days+*+(+$dti->invert+?+-1+:+1);+++//+nb:+->days+always+positive
}|code-block|syntax|javascript|46795|使用示例：|46796|$dt1+=+\DateTime::createFromFormat('Y-m-d',+'2014-03-03'+);
$dt2+=+\DateTime::createFromFormat('Y-m-d',+'2014-02-20'+);
getNightsBetween($dt1,+$dt2);+++++++//+-11

$dt1+=+\DateTime::createFromFormat('Y-m-d+H:i:s',+'2014-01-01+23:59:59'+);
$dt2+=+\DateTime::createFromFormat('Y-m-d+H:i:s',+'2014-01-02+00:00:01'+);
getNightsBetween($dt1,+$dt2);+++++++//+1+(only+2+seconds+later,+but+still+the+next+day)

$dt1+=+\DateTime::createFromFormat('Y-m-d',+'2014-04-09'+);
$dt2+=+new+\DateTime();
getNightsBetween($dt1,+$dt2);+++++++//+xx+(how+many+days+(midnights)+passed+since+I+wrote+this)|46797|一些文本魔术的例子：|46798|function+getRelativeDay(\DateTime+$dt2){
++++if(!$dt2){
++++++++return+false;
++++}
++++$n+=+getNightsBetween(+new+\DateTime(),+$dt2);
++++switch($n){
++++++++case++0:+return+"today";
++++++++case++1:+return+"tomorrow";
++++++++case+-1:+return+"yesterday";
++++++++default:+
++++++++++++return+$n+.+(abs($n)>1?"days":"day")+.+($n<0?"+ago":"+from+now");
++++}
}|46799|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

note that DateInterval->days is always positive. hence the use of ->invert.

<pre><code>/**
 * return amount of days between dt1 and dt2 
 * (how many midnights pass going from dt1 to dt2)
 * 0 = same day, 
 * -1 = dt2 is 1 day before dt1, 
 * 1 = dt2 is 1 day after dt1, etc.
 *
 * @param \DateTime $dt1
 * @param \DateTime $dt2
 * @return int|false 
 */
function getNightsBetween(\DateTime $dt1, \DateTime $dt2){
 if(!$dt1 || !$dt2){
 return false;
 }
 $dt1-&gt;setTime(0,0,0);
 $dt2-&gt;setTime(0,0,0);
 $dti = $dt1-&gt;diff($dt2); // DateInterval
 return $dti-&gt;days * ( $dti-&gt;invert ? -1 : 1); // nb: -&gt;days always positive
}
</code></pre>

usage examples:

<pre><code>$dt1 = \DateTime::createFromFormat('Y-m-d', '2014-03-03' );
$dt2 = \DateTime::createFromFormat('Y-m-d', '2014-02-20' );
getNightsBetween($dt1, $dt2); // -11

$dt1 = \DateTime::createFromFormat('Y-m-d H:i:s', '2014-01-01 23:59:59' );
$dt2 = \DateTime::createFromFormat('Y-m-d H:i:s', '2014-01-02 00:00:01' );
getNightsBetween($dt1, $dt2); // 1 (only 2 seconds later, but still the next day)

$dt1 = \DateTime::createFromFormat('Y-m-d', '2014-04-09' );
$dt2 = new \DateTime();
getNightsBetween($dt1, $dt2); // xx (how many days (midnights) passed since I wrote this)
</code></pre>

example of some text magic:

<pre><code>function getRelativeDay(\DateTime $dt2){
 if(!$dt2){
 return false;
 }
 $n = getNightsBetween( new \DateTime(), $dt2);
 switch($n){
 case 0: return "today";
 case 1: return "tomorrow";
 case -1: return "yesterday";
 default: 
 return $n . (abs($n)&gt;1?"days":"day") . ($n&lt;0?" ago":" from now");
 }
}
</code></pre>

What is the simplest way to get the difference in days between two PHP <code>DateTimes</code>, considering midnight as a day change (just like the <code>DATEDIFF(DAY)</code> SQL function does)?

For example, between today at 13:00 and tomorrow at 12:00, I should get 1 (day), even though the interval is less than 24 hours.

<pre><code>$date1 = new DateTime("2013-08-07 13:00:00");
$date2 = new DateTime("2013-08-08 12:00:00");
echo $date1-&gt;diff($date2)-&gt;days; // 0
</code></pre>

Get a PHP DateTime difference in days, considering midnight as a day change

考虑到午夜是一天的变化(就像DATEDIFF(DAY) DateTimes函数一样)，那么获取两个PHP之间的天数差的最简单方法是什么？例如，从今天的13:00到明天的12:00，我应该得到1(天)，即使间隔不到24小时。$date1 = new DateTime("2013-08-07 13:00:00");$dat...

问获取以天为单位的PHP DateTime差异，将午夜视为一天的变化
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