blocks|key|1100832|text|如果你需要在php数据结构中使用一个数字键，一个对象就可以了。和对象保持顺序，所以你可以迭代。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1100833|$obj+=+new+stdClass();
$key+=+'3';
$obj->$key+=+'abc';|code-block|syntax|javascript|1100834|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you need to use a numeric key in a php data structure, an object will work. And objects preserve order, so you can iterate.

<pre><code>$obj = new stdClass();
$key = '3';
$obj-&gt;$key = 'abc';
</code></pre>

blocks|key|1100943|text|我的解决方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1100944|$id+=+55;
$array+=+array(
++"+$id"+=>+$value
);|code-block|syntax|javascript|1100945|空格char+(前缀)是一个很好的解决方案，因为保留int转换：|1100946|foreach(+$array+as+$key+=>+$value+)+{
++echo+$key;
}|1100947|您将看到55为int。|1100948|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

My workaround is:

<pre><code>$id = 55;
$array = array(
 " $id" =&gt; $value
);
</code></pre>

The space char (prepend) is a good solution because keep the int conversion:

<pre><code>foreach( $array as $key =&gt; $value ) {
 echo $key;
}
</code></pre>

You'll see 55 as int.

blocks|key|886171|text|我在尝试合并同时具有字符串键和整型键的数组时遇到了这个问题。很重要的一点是，整数也将作为字符串处理，因为这些是输入字段的名称(如鞋码等)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|886172|当我使用$data+=+array_merge($data,+$extra);时，PHP会对键进行“重新排序”。在尝试进行排序时，整数键(我尝试使用6+-+'6'-+"6"甚至(string)"6"作为键)从0重命名为n+...如果你仔细想想，在大多数情况下，这是你想要的行为。|offset|length|style|CODE|886173|您可以通过使用$data+=+$data+%2B+$extra;来解决此问题。非常直截了当，但我一开始并没有想到%5E%5E。|886174|entityMap^0|0|4|Z|22|1|26|3|2B|3|2G|B|31|1|0|7|N|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]|$D|P|E|Q|F|G]|$D|R|E|S|F|G]|$D|T|E|U|F|G]|$D|V|E|W|F|G]|$D|X|E|Y|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|Z|8|@$D|10|E|11|F|G]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|K|$]]

I had this problem trying to merge arrays which had both string and integer keys. It was important that the integers would also be handled as string since these were names for input fields (as in shoe sizes etc,..)

When I used <code>$data = array_merge($data, $extra);</code> PHP would 're-order' the keys. In an attempt doing the ordering, the integer keys (I tried with <code>6</code> - <code>'6'</code>- <code>"6"</code> even <code>(string)"6"</code> as keys) got renamed from 0 to <code>n</code> ... If you think about it, in most cases this would be the desired behaviour.

You can work around this by using <code>$data = $data + $extra;</code> instead.
Pretty straight forward, but I didn't think of it at first ^^.

blocks|key|886087|text|我在一个同时使用'0‘和'’作为键的数组上遇到了这个问题。这意味着我不能用==或===检查我的数组密钥。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|886088|$array=array(''=>'empty',+'0'=>'zero',+'1'=>'one');
echo+"Test+1\n";
foreach+($array+as+$key=>$value)+{
++++if+($key+==+'')+{+//+Error+-+wrongly+finds+'0'+as+well
++++++++echo+"$value\n";
++++}
}
echo+"Test+2\n";
foreach+($array+as+$key=>$value)+{
++++if+($key+===+'0')+{+//+Error+-+doesn't+find+'0'
++++++++echo+"$value\n";
++++}
}|code-block|syntax|javascript|886089|解决方法是在使用前将数组键转换回字符串。|886090|echo+"Test+3\n";
foreach+($array+as+$key=>$value)+{
++++if+((string)$key+==+'')+{+//+Cast+back+to+string+-+fixes+problem
++++++++echo+"$value\n";
++++}
}
echo+"Test+4\n";
foreach+($array+as+$key=>$value)+{
++++if+((string)$key+===+'0')+{+//+Cast+back+to+string+-+fixes+problem
++++++++echo+"$value\n";
++++}
}|886091|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I ran into this problem on an array with both '0' and '' as keys. It meant that I couldn't check my array keys with either == or ===.

<pre><code>$array=array(''=&gt;'empty', '0'=&gt;'zero', '1'=&gt;'one');
echo "Test 1\n";
foreach ($array as $key=&gt;$value) {
 if ($key == '') { // Error - wrongly finds '0' as well
 echo "$value\n";
 }
}
echo "Test 2\n";
foreach ($array as $key=&gt;$value) {
 if ($key === '0') { // Error - doesn't find '0'
 echo "$value\n";
 }
}
</code></pre>

The workaround is to cast the array keys back to strings before use.

<pre><code>echo "Test 3\n";
foreach ($array as $key=&gt;$value) {
 if ((string)$key == '') { // Cast back to string - fixes problem
 echo "$value\n";
 }
}
echo "Test 4\n";
foreach ($array as $key=&gt;$value) {
 if ((string)$key === '0') { // Cast back to string - fixes problem
 echo "$value\n";
 }
}
</code></pre>

blocks|key|886346|text|作为解决方法，您可以使用JSON_FORCE_OBJECT选项将PHP数组编码为json对象。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|886347|也就是说，这个例子：|886348|+++++$a+=+array('foo','bar','baz');
+++++echo+"RESULT:+",+json_encode($a,+JSON_FORCE_OBJECT);|code-block|syntax|javascript|886349|将导致：|886350|+++++RESULT:+{"0"+:+"foo",+"1":+"bar",+"2"+:+"baz"}|886351|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

As workaround, you can encode PHP array into json object, with JSON_FORCE_OBJECT option.

i.e., This example:

<pre><code> $a = array('foo','bar','baz');
 echo "RESULT: ", json_encode($a, JSON_FORCE_OBJECT);
</code></pre>

will result in:

<pre><code> RESULT: {"0" : "foo", "1": "bar", "2" : "baz"}
</code></pre>

blocks|key|886297|text|关于@david解决方案，请注意，当您尝试访问关联数组中的字符串值时，数字将不起作用。我的猜测是，它们在幕后被强制转换为整数(当访问数组时)，并且没有找到值。以整数形式访问这些值也不起作用。但是您可以使用array_shift()来获取值或迭代数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|886298|$data+=+new+stdClass;
$data->{"0"}+=+"Zero";
$data->{"1"}+=+"One";
$data->{"A"}+=+"A";
$data->{"B"}+=+"B";

$data+=+(array)$data;

var_dump($data);
/*
Note+the+key+"0"+is+correctly+saved+as+a+string:
array(3)+{
++["0"]=>
++string(4)+"Zero"
++["A"]=>
++string(1)+"A"
++["B"]=>
++string(1)+"B"
}
*/

//Now+let's+access+the+associative+array+via+the+values+
//given+from+var_dump()+above:
var_dump($data["0"]);+//+NULL+->+Expected+string(1)+"0"
var_dump($data[0]);+//+NULL+(as+expected)
var_dump($data["1"]);+//+NULL+->+Expected+string(1)+"1"
var_dump($data[1]);+//+NULL+(as+expected)
var_dump($data["A"]);+//+string(1)+"A"+(as+expected)
var_dump($data["B"]);+//+string(1)+"B"+(as+expected)|code-block|syntax|javascript|886299|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Regarding @david solution, please note that when you try to access the string values in the associative array, the numbers will not work. My guess is that they are casted to integers behind the scenes (when accessing the array) and no value is found. Accessing the values as integers won't work either. But you can use array_shift() to get the values or iterate the array.

<pre><code>$data = new stdClass;
$data-&gt;{"0"} = "Zero";
$data-&gt;{"1"} = "One";
$data-&gt;{"A"} = "A";
$data-&gt;{"B"} = "B";

$data = (array)$data;

var_dump($data);
/*
Note the key "0" is correctly saved as a string:
array(3) {
 ["0"]=&gt;
 string(4) "Zero"
 ["A"]=&gt;
 string(1) "A"
 ["B"]=&gt;
 string(1) "B"
}
*/

//Now let's access the associative array via the values 
//given from var_dump() above:
var_dump($data["0"]); // NULL -&gt; Expected string(1) "0"
var_dump($data[0]); // NULL (as expected)
var_dump($data["1"]); // NULL -&gt; Expected string(1) "1"
var_dump($data[1]); // NULL (as expected)
var_dump($data["A"]); // string(1) "A" (as expected)
var_dump($data["B"]); // string(1) "B" (as expected)
</code></pre>

blocks|key|886256|text|在尝试对需要十六进制sha1的排序关键字的数组进行排序时，我遇到了这个问题。当得到的PHP值没有字母时，sha1会将键值转换为整数。但我需要按字符串的相对顺序对数组进行排序。因此，我需要找到一种方法，在不改变排序顺序的情况下将键强制为字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|886257|看一下ASCII图表(https://en.wikipedia.org/wiki/ASCII)，感叹号的排序与空格几乎相同，而且肯定比所有的数字和字母都低。|offset|length|886258|所以我在键字符串的末尾附加了一个感叹号。|886259|for(...)+{

++++$database[$sha.'!']+=+array($sha,$name,$age);
}

ksort($database);
$row+=+reset($database);
$topsha+=+$row[0];|code-block|syntax|javascript|886260|entityMap|0|LINK|mutability|MUTABLE|url|https://en.wikipedia.org/wiki/ASCII^0|0|B|Z|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@$D|W|E|X|1|Y]]|A|$]]|$1|F|3|G|5|6|7|Z|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|10|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

I had this problem while trying to sort an array where I needed the sort key to be a hex sha1. When a resulting sha1 value has no letters, PHP turns the key into an integer. But I needed to sort the array on the relative order of the strings. So I needed to find a way to force the key to be a string without changing the sorting order. 

Looking at the ASCII chart (<a href="https://en.wikipedia.org/wiki/ASCII" rel="nofollow">https://en.wikipedia.org/wiki/ASCII</a>) the exclamation point sorts just about the same as space and certainly lower than all numbers and letters. 

So I appended an exclamation point at the end of the key string.

<pre><code>for(...) {

 $database[$sha.'!'] = array($sha,$name,$age);
}

ksort($database);
$row = reset($database);
$topsha = $row[0];
</code></pre>

Is it possible to use a numeric string like <code>"123"</code> as a key in a PHP array, without it being converted to an integer?

<pre><code>$blah = array('123' =&gt; 1);
var_dump($blah);
</code></pre>

prints

<pre><code>array(1) {
 [123]=&gt;
 int(1)
}
</code></pre>

I want

<pre><code>array(1) {
 ["123"]=&gt;
 int(1)
}
</code></pre>

A numeric string as array key in PHP

数据结构

有没有可能使用像"123"这样的数字字符串作为PHP数组中的键，而不将其转换为整数？$blah = array('123' => 1);var_dump($blah);打印array(1) {  [123]=>  int(1)}我想要array(1) {  ["123"]=>  int(1)}

问PHP中作为数组键的数字字符串
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回答 7

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