blocks|key|520393|text|如果需要返回值，请使用del按索引删除元素，使用pop()按索引删除元素，使用remove()按值删除元素。最后一个需要搜索列表，如果列表中没有出现这样的值，则引发ValueError。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|520394|当从n元素列表中删除索引i时，这些方法的计算复杂性为|520395|del+++++O(n+-+i)
pop+++++O(n+-+i)
remove++O(n)|code-block|syntax|javascript|520396|entityMap^0|B|3|O|5|13|8|2A|A|0|2|1|C|1|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|N|$]]

Use <code>del</code> to remove an element by index, <code>pop()</code> to remove it by index if you need the returned value, and <code>remove()</code> to delete an element by value. The last requires searching the list, and raises <code>ValueError</code> if no such value occurs in the list.
When deleting index <code>i</code> from a list of <code>n</code> elements, the computational complexities of these methods are
<pre><code>del O(n - i)
pop O(n - i)
remove O(n)
</code></pre>

blocks|key|520504|text|由于没有人提到它，请注意，由于列表切片，del+(与pop不同)允许删除一定范围的索引：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|520505|>>>+lst+=+[3,+2,+2,+1]
>>>+del+lst[1:]
>>>+lst
[3]|code-block|syntax|javascript|520506|这还允许在索引不在列表中时避免IndexError：|520507|>>>+lst+=+[3,+2,+2,+1]
>>>+del+lst[10:]
>>>+lst
[3,+2,+2,+1]|520508|entityMap^0|K|3|Q|3|0|0|F|A|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|P|$]]

Since no-one else has mentioned it, note that <code>del</code> (unlike <code>pop</code>) allows the removal of a range of indexes because of list slicing:

<pre><code>&gt;&gt;&gt; lst = [3, 2, 2, 1]
&gt;&gt;&gt; del lst[1:]
&gt;&gt;&gt; lst
[3]
</code></pre>

This also allows avoidance of an <code>IndexError</code> if the index is not in the list:

<pre><code>&gt;&gt;&gt; lst = [3, 2, 2, 1]
&gt;&gt;&gt; del lst[10:]
&gt;&gt;&gt; lst
[3, 2, 2, 1]
</code></pre>

blocks|key|303895|text|其他人已经回答得很好了。来自我这一端的这一条:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|303896|​|303897|📷|atomic|offset|length|303898|303899|显然，pop是唯一返回值的程序，remove是唯一搜索对象的程序，而del将自己限制为一个简单的删除。|style|CODE|303900|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/1aebaa475ca4649cc69c952dea42d84e.png|imageAlt^0|0|0|0|1|0|0|0|3|3|G|6|Y|3|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@$G|Z|H|10|1|11]]|A|$]]|$1|I|3|C|5|6|7|12|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|13|8|@$G|14|H|15|L|M]|$G|16|H|17|L|M]|$G|18|H|19|L|M]]|9|@]|A|$]]|$1|N|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]]|O|$P|$5|Q|R|S|A|$T|U|V|-4]]]]

Already answered quite well by others. This one from my end :)
<a href="https://i.stack.imgur.com/9Yzgv.png" rel="noreferrer"><img src="https://i.stack.imgur.com/9Yzgv.png" alt="remove vs pop vs del" /></a>
Evidently, <code>pop</code> is the only one which returns the value, and <code>remove</code> is the only one which searches the object, while <code>del</code> limits itself to a simple deletion.

blocks|key|303760|text|而pop和delete都采用索引来移除上述注释中所述的元素。一个关键的区别是它们的时间复杂性。不带索引的pop()的时间复杂度为O(1)，但与删除最后一个元素的情况不同。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|303761|如果您的用例总是删除最后一个元素，那么使用pop()总是比使用delete()更可取。有关时间复杂性的更多解释，可以参考https://www.ics.uci.edu/~pattis/ICS-33/lectures/complexitypython.txt|offset|length|303762|entityMap|0|LINK|mutability|MUTABLE|url|https://www.ics.uci.edu/~pattis/ICS-33/lectures/complexitypython.txt^0|0|1O|1W|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@$D|P|E|Q|1|R]]|A|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|M]]]]

While pop and delete both take indices to remove an element as stated in above comments. A key difference is the time complexity for them. The time complexity for pop() with no index is O(1) but is not the same case for deletion of last element.

If your use case is always to delete the last element, it's always preferable to use pop() over delete(). For more explanation on time complexities, you can refer to <a href="https://www.ics.uci.edu/~pattis/ICS-33/lectures/complexitypython.txt" rel="nofollow">https://www.ics.uci.edu/~pattis/ICS-33/lectures/complexitypython.txt</a>

blocks|key|520684|text|列表上的remove操作被赋予一个要删除的值。它搜索列表以查找具有该值的项，并删除找到的第一个匹配项。如果没有匹配项，则为错误，并引发ValueError。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|520685|>>>+x+=+[1,+0,+0,+0,+3,+4,+5]
>>>+x.remove(4)
>>>+x
[1,+0,+0,+0,+3,+5]
>>>+del+x[7]
Traceback+(most+recent+call+last):
++File+"<pyshell#1>",+line+1,+in+<module>
++++del+x[7]
IndexError:+list+assignment+index+out+of+range|code-block|syntax|javascript|520686|del语句可用于删除整个列表。如果你有一个特定的列表项作为del的参数(例如，listname7专门引用列表中的第8项)，它将直接删除该项。甚至可以从列表中删除“切片”。如果存在超出范围的索引，则会引发IndexError。|520687|>>>+x+=+[1,+2,+3,+4]
>>>+del+x[3]
>>>+x
[1,+2,+3]
>>>+del+x[4]
Traceback+(most+recent+call+last):
++File+"<pyshell#1>",+line+1,+in+<module>
++++del+x[4]
IndexError:+list+assignment+index+out+of+range|520688|pop的通常用法是删除列表中的最后一项，因为您将列表用作堆栈。与del不同，pop返回它从列表中弹出的值。你可以有选择地给出一个索引值来弹出，而不是从列表的末尾弹出(例如，listname.pop(0)将从列表中删除第一项并返回第一项作为其结果)。您可以使用它来使列表表现得像一个队列，但是有一些库例程可以提供比pop(0)更好的性能的队列操作。如果存在超出范围的索引，则会引发IndexError。|520689|>>>+x+=+[1,+2,+3]+
>>>+x.pop(2)+
3+
>>>+x+
[1,+2]
>>>+x.pop(4)
Traceback+(most+recent+call+last):
++File+"<pyshell#1>",+line+1,+in+<module>
++++x.pop(4)
IndexError:+pop+index+out+of+range|520690|有关更多详细信息，请参阅collections.deque。|520691|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/collections.html#collections.deque.remove|1|https://docs.python.org/3/library/exceptions.html#ValueError|2|https://docs.python.org/3/tutorial/datastructures.html#the-del-statement|3|https://docs.python.org/3/library/exceptions.html#IndexError|4|https://docs.python.org/3/library/collections.html#collections.deque.pop|5|6|https://docs.python.org/3/library/collections.html#collections.deque^0|4|6|0|1V|A|1|0|0|0|3|2|2T|A|3|0|0|0|3|4|59|A|5|0|0|C|H|6|0^^$0|@$1|2|3|4|5|6|7|1B|8|@]|9|@$A|1C|B|1D|1|1E]|$A|1F|B|1G|1|1H]]|C|$]]|$1|D|3|E|5|F|7|1I|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|1J|8|@]|9|@$A|1K|B|1L|1|1M]|$A|1N|B|1O|1|1P]]|C|$]]|$1|K|3|L|5|F|7|1Q|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|1R|8|@]|9|@$A|1S|B|1T|1|1U]|$A|1V|B|1W|1|1X]]|C|$]]|$1|O|3|P|5|F|7|1Y|8|@]|9|@]|C|$G|H]]|$1|Q|3|R|5|6|7|1Z|8|@]|9|@$A|20|B|21|1|22]]|C|$]]|$1|S|3|-4|5|6|7|23|8|@]|9|@]|C|$]]]|T|$U|$5|V|W|X|C|$Y|Z]]|10|$5|V|W|X|C|$Y|11]]|12|$5|V|W|X|C|$Y|13]]|14|$5|V|W|X|C|$Y|15]]|16|$5|V|W|X|C|$Y|17]]|18|$5|V|W|X|C|$Y|15]]|19|$5|V|W|X|C|$Y|1A]]]]

The <a href="https://docs.python.org/3/library/collections.html#collections.deque.remove" rel="nofollow noreferrer">remove</a> operation on a list is given a value to remove. It searches the list to find an item with that value and deletes the first matching item it finds. It is an error if there is no matching item, raises a <a href="https://docs.python.org/3/library/exceptions.html#ValueError" rel="nofollow noreferrer">ValueError</a>.

<pre><code>&gt;&gt;&gt; x = [1, 0, 0, 0, 3, 4, 5]
&gt;&gt;&gt; x.remove(4)
&gt;&gt;&gt; x
[1, 0, 0, 0, 3, 5]
&gt;&gt;&gt; del x[7]
Traceback (most recent call last):
 File "&lt;pyshell#1&gt;", line 1, in &lt;module&gt;
 del x[7]
IndexError: list assignment index out of range
</code></pre>

The <a href="https://docs.python.org/3/tutorial/datastructures.html#the-del-statement" rel="nofollow noreferrer">del</a> statement can be used to delete an entire list. If you have a specific list item as your argument to del (e.g. listname[7] to specifically reference the 8th item in the list), it'll just delete that item. It is even possible to delete a "slice" from a list. It is an error if there index out of range, raises a <a href="https://docs.python.org/3/library/exceptions.html#IndexError" rel="nofollow noreferrer">IndexError</a>.

<pre><code>&gt;&gt;&gt; x = [1, 2, 3, 4]
&gt;&gt;&gt; del x[3]
&gt;&gt;&gt; x
[1, 2, 3]
&gt;&gt;&gt; del x[4]
Traceback (most recent call last):
 File "&lt;pyshell#1&gt;", line 1, in &lt;module&gt;
 del x[4]
IndexError: list assignment index out of range
</code></pre>

The usual use of <a href="https://docs.python.org/3/library/collections.html#collections.deque.pop" rel="nofollow noreferrer">pop</a> is to delete the last item from a list as you use the list as a stack. Unlike del, pop returns the value that it popped off the list. You can optionally give an index value to pop and pop from other than the end of the list (e.g listname.pop(0) will delete the first item from the list and return that first item as its result). You can use this to make the list behave like a queue, but there are library routines available that can provide queue operations with better performance than pop(0) does. It is an error if there index out of range, raises a <a href="https://docs.python.org/3/library/exceptions.html#IndexError" rel="nofollow noreferrer">IndexError</a>.

<pre><code>&gt;&gt;&gt; x = [1, 2, 3] 
&gt;&gt;&gt; x.pop(2) 
3 
&gt;&gt;&gt; x 
[1, 2]
&gt;&gt;&gt; x.pop(4)
Traceback (most recent call last):
 File "&lt;pyshell#1&gt;", line 1, in &lt;module&gt;
 x.pop(4)
IndexError: pop index out of range
</code></pre>

See <a href="https://docs.python.org/3/library/collections.html#collections.deque" rel="nofollow noreferrer">collections.deque</a> for more details.

blocks|key|520782|text|Remove基本上作用于该值。删除并弹出索引上的工作|type|unstyled|depth|inlineStyleRanges|entityRanges|data|520783|Remove基本上删除了第一个匹配值。Delete从特定的索引中删除项Pop基本上获取一个索引并返回该索引处的值。下次打印列表时，不会显示该值。|520784|​|520785|📷|atomic|offset|length|520786|520787|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/95d7ad66b883b04cd0d6d8fddc69eb7e.png|imageAlt^0|0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@$I|Y|J|Z|1|10]]|A|$]]|$1|K|3|E|5|6|7|11|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|M|$N|$5|O|P|Q|A|$R|S|T|-4]]]]

Remove basically works on the value .
Delete and pop work on the index

Remove basically removes the first matching value.
Delete deletes the item from a specific index
Pop basically takes an index and returns the value at that index. Next time you print the list the value doesnt appear.

<a href="https://i.stack.imgur.com/ExsEy.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/ExsEy.png" alt="Example:"></a>

blocks|key|303713|text|您还可以使用remove按索引移除值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|303714|n+=+[1,+3,+5]

n.remove(n[1])|code-block|syntax|javascript|303715|然后，n将引用1，5|303716|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can also use remove to remove a value by index as well. 

<pre><code>n = [1, 3, 5]

n.remove(n[1])
</code></pre>

n would then refer to [1, 5]

<pre><code>&gt;&gt;&gt; a=[1,2,3]
&gt;&gt;&gt; a.remove(2)
&gt;&gt;&gt; a
[1, 3]
&gt;&gt;&gt; a=[1,2,3]
&gt;&gt;&gt; del a[1]
&gt;&gt;&gt; a
[1, 3]
&gt;&gt;&gt; a= [1,2,3]
&gt;&gt;&gt; a.pop(1)
2
&gt;&gt;&gt; a
[1, 3]
&gt;&gt;&gt; 
</code></pre>

Is there any difference between the above three methods to remove an element from a list?

Difference between del, remove, and pop on lists

>>> a=[1,2,3]>>> a.remove(2)>>> a[1, 3]>>> a=[1,2,3]>>> del a[1]>>> a[1, 3]>>> a= [1,2,3]>>> a.pop(1)2>>> a[1, 3]>>> 上面三种从列表中删除元素的方法有什么不同吗？

问del、remove和pop在列表上的区别
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