TypeError:需要类似字节的对象,而不是“str”
执行以下python代码以将HTML表数据保存在Csv文件中时出现上述错误。不知道怎么让rideup.pls帮我。
import csv
import requests
from bs4 import BeautifulSoup
url='http://www.mapsofindia.com/districts-india/'
response=requests.get(url)
html=response.content
soup=BeautifulSoup(html,'html.parser')
table=soup.find('table', attrs={'class':'tableizer-table'})
list_of_rows=[]
for row in table.findAll('tr')[1:]:
list_of_cells=[]
for cell in row.findAll('td'):
list_of_cells.append(cell.text)
list_of_rows.append(list_of_cells)
outfile=open('./immates.csv','wb')
writer=csv.writer(outfile)
writer.writerow(["SNo", "States", "Dist", "Population"])
writer.writerows(list_of_rows)
在最后一行的上方。
发布于 2015-12-15 16:12:09
您正在使用Python 2方法,而不是Python 3。
更改:
outfile=open('./immates.csv','wb')
至:
outfile=open('./immates.csv','w')
然后您将获得一个包含以下输出的文件:
SNo,States,Dist,Population
1,Andhra Pradesh,13,49378776
2,Arunachal Pradesh,16,1382611
3,Assam,27,31169272
4,Bihar,38,103804637
5,Chhattisgarh,19,25540196
6,Goa,2,1457723
7,Gujarat,26,60383628
.....
在Python3中,csv以文本模式接受输入,而在Python2中,它以二进制模式接受输入。
编辑以添加
下面是我运行的代码:
url='http://www.mapsofindia.com/districts-india/'
html = urllib.request.urlopen(url).read()
soup = BeautifulSoup(html)
table=soup.find('table', attrs={'class':'tableizer-table'})
list_of_rows=[]
for row in table.findAll('tr')[1:]:
list_of_cells=[]
for cell in row.findAll('td'):
list_of_cells.append(cell.text)
list_of_rows.append(list_of_cells)
outfile = open('./immates.csv','w')
writer=csv.writer(outfile)
writer.writerow(['SNo', 'States', 'Dist', 'Population'])
writer.writerows(list_of_rows)
发布于 2016-12-23 05:20:56
我和Python3也有同样的问题。我的代码正在写入io.BytesIO()
。
替换为io.StringIO()
已解决。
发布于 2019-09-18 14:02:37
只需将wb更改为w
outfile=open('./immates.csv','wb')
至
outfile=open('./immates.csv','w')
https://stackoverflow.com/questions/34283178
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