blocks|key|500177|text|根据http://api.jquery.com/jQuery.isNumeric/的说法|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|500178|是:jQuery.isNumeric(value)|style|CODE|500179|因此，它应该是$.isNumeric($("#EmpNum").val())|500180|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/jQuery.isNumeric/^0|2|13|0|0|2|N|0|7|V|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@$A|S|B|T|1|U]]|C|$]]|$1|D|3|E|5|6|7|V|8|@$A|W|B|X|F|G]]|9|@]|C|$]]|$1|H|3|I|5|6|7|Y|8|@$A|Z|B|10|F|G]]|9|@]|C|$]]|$1|J|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|K|$L|$5|M|N|O|C|$P|Q]]]]

according to <a href="http://api.jquery.com/jQuery.isNumeric/" rel="noreferrer">http://api.jquery.com/jQuery.isNumeric/</a>

it's :<code>jQuery.isNumeric(value)</code>

so, it should be <code>$.isNumeric($("#EmpNum").val())</code>

blocks|key|500089|text|不是应该更像..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|500090|if($.isNumeric($('#EmpNum').val()))|code-block|syntax|javascript|500091|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Shouldn't it be more like...

<pre><code>if($.isNumeric($('#EmpNum').val()))
</code></pre>

blocks|key|715749|text|将该值作为参数传递给isNumeric。还要确保您使用的是jQuery版本1.7，因为它是在1.7中添加的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|715750|$.isNumeric(+$('#EmpNum').val()+)|code-block|syntax|javascript|715751|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Pass in the value as an argument to isNumeric. Also make sure you are using jQuery version 1.7 as this was added in 1.7.

<pre><code>$.isNumeric( $('#EmpNum').val() )
</code></pre>

blocks|key|715759|text|应该是这样的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|715760|$.isNumeric($('#EmpNum').val());|code-block|syntax|javascript|715761|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

it should be like this

<pre><code>$.isNumeric($('#EmpNum').val());
</code></pre>

blocks|key|715828|text|你应该使用简单和容易的方法，比如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|715829|.val+value=$(‘#txtNumber’)+var+()；|715830|if($.isNumeric(值))|715831|{|715832|//在这里写代码|715833|}|715834|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|P|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|Q|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|R|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|S|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|M|$]]

You Should use simple and easy way like:

var value=$('#txtNumber').val();

if($.isNumeric(value))

{

//write your code here

}

blocks|key|715658|text|尝试以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|715659|$.isNumeric($('#EmpNum').text())|code-block|syntax|javascript|715660|另外，isNumeric+method是在1.7版本中添加的，您使用的是哪个版本？|offset|length|715661|See+here+for+jsFiddle.|715662|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/jQuery.isNumeric/|1|http://jsfiddle.net/mupTA/^0|0|0|3|G|0|0|0|M|1|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@$I|Z|J|10|1|11]]|A|$]]|$1|K|3|L|5|6|7|12|8|@]|9|@$I|13|J|14|1|15]]|A|$]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]|U|$5|P|Q|R|A|$S|V]]]]

Try the following:

<pre><code>$.isNumeric($('#EmpNum').text())
</code></pre>

Also the <a href="http://api.jquery.com/jQuery.isNumeric/" rel="nofollow">isNumeric method</a> was only added in version 1.7, which version are you using?

<a href="http://jsfiddle.net/mupTA/" rel="nofollow">See here for jsFiddle.</a>

blocks|key|715775|text|对我来说，$.isNumeric($('#EmpNum').val());不起作用。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|715776|我不得不使用这个：|715777|var+temp+=+$('#EmpNum').val();

$.isNumeric(temp);|code-block|syntax|javascript|715778|entityMap^0|5|W|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

For me <code>$.isNumeric($('#EmpNum').val());</code> did not work.

I had to use this:

<pre><code>var temp = $('#EmpNum').val();

$.isNumeric(temp);
</code></pre>

blocks|key|500366|text|这取决于你使用的jQuery版本，但由于"$.isNumeric()“函数在jQuery+Core3.0更新后被弃用(https://jquery.com/upgrade-guide/3.0/#breaking-change-jquery-isnumeric-and-custom-tostring)，我为这个问题找到了一个自定义的解决方案(最初发布在这里：https://stackoverflow.com/a/9716488/3323790)：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|500367|function+isNumeric(n)+{
++++return+!isNaN(parseFloat(n))+&&+isFinite(n);
}|code-block|syntax|javascript|500368|entityMap|0|LINK|mutability|MUTABLE|url|https://jquery.com/upgrade-guide/3.0/#breaking-change-jquery-isnumeric-and-custom-tostring|1|https://stackoverflow.com/a/9716488/3323790^0|1N|2I|0|4Z|17|1|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]|$A|W|B|X|1|Y]]|C|$]]|$1|D|3|E|5|F|7|Z|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|10|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]|Q|$5|L|M|N|C|$O|R]]]]

Depending on what version of jQuery you are using, but as "$.isNumeric()" function is deprecated (<a href="https://jquery.com/upgrade-guide/3.0/#breaking-change-jquery-isnumeric-and-custom-tostring" rel="nofollow noreferrer">https://jquery.com/upgrade-guide/3.0/#breaking-change-jquery-isnumeric-and-custom-tostring</a>) since jQuery Core 3.0 Update, I found a custom solution for this problem (originally posted here: <a href="https://stackoverflow.com/a/9716488/3323790">https://stackoverflow.com/a/9716488/3323790</a>): 

<pre><code>function isNumeric(n) {
 return !isNaN(parseFloat(n)) &amp;&amp; isFinite(n);
}
</code></pre>

I have a text box with an id of EmpNum. I cannot figure out how to use jQuery's isNumeric to check to see if the value is numeric or not.

I tried:

<pre><code> ('#.EmpNum').IsNumeric 
</code></pre>

but that did not work.

JQuery .isNumeric

我有一个id为EmpNum的文本框。我不知道如何使用jQuery的isNumeric来检查该值是否为数字。我试过了：    ('#.EmpNum').IsNumeric 但这并不管用。

问JQuery .isNumeric
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回答 8

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