blocks|key|869071|text|使用您的JSON并对其进行.stringify()。然后使用.replace()方法并将所有出现的\n替换为\\n。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|869072|编辑：|869073|据我所知，没有众所周知的JS库可以转义字符串中的所有特殊字符。但是，您可以链接.replace()方法并替换所有特殊字符，如下所示：|869074|var+myJSONString+=+JSON.stringify(myJSON);
var+myEscapedJSONString+=+myJSONString.replace(/\\n/g,+"\\n")
++++++++++++++++++++++++++++++++++++++.replace(/\\'/g,+"\\'")
++++++++++++++++++++++++++++++++++++++.replace(/\\"/g,+'\\"')
++++++++++++++++++++++++++++++++++++++.replace(/\\&/g,+"\\&")
++++++++++++++++++++++++++++++++++++++.replace(/\\r/g,+"\\r")
++++++++++++++++++++++++++++++++++++++.replace(/\\t/g,+"\\t")
++++++++++++++++++++++++++++++++++++++.replace(/\\b/g,+"\\b")
++++++++++++++++++++++++++++++++++++++.replace(/\\f/g,+"\\f");
//+myEscapedJSONString+is+now+ready+to+be+POST'ed+to+the+server.+|code-block|syntax|javascript|869075|但这真的很糟糕，不是吗？函数的美妙之处在于，它们允许您将代码拆分成片断，并保持脚本的主要流程干净，并且不需要8个链接的.replace()调用。因此，让我们将该功能放入一个名为escapeSpecialChars()的函数中。让我们继续将它附加到String对象的prototype+chain，这样我们就可以直接在String对象上调用escapeSpecialChars()。|869076|如下所示：|869077|String.prototype.escapeSpecialChars+=+function()+{
++++return+this.replace(/\\n/g,+"\\n")
+++++++++++++++.replace(/\\'/g,+"\\'")
+++++++++++++++.replace(/\\"/g,+'\\"')
+++++++++++++++.replace(/\\&/g,+"\\&")
+++++++++++++++.replace(/\\r/g,+"\\r")
+++++++++++++++.replace(/\\t/g,+"\\t")
+++++++++++++++.replace(/\\b/g,+"\\b")
+++++++++++++++.replace(/\\f/g,+"\\f");
};|869078|一旦我们定义了这个函数，代码的主体就像下面这样简单：|869079|var+myJSONString+=+JSON.stringify(myJSON);
var+myEscapedJSONString+=+myJSONString.escapeSpecialChars();
//+myEscapedJSONString+is+now+ready+to+be+POST'ed+to+the+server|869080|entityMap^0|D|C|U|A|1D|2|1I|3|0|0|13|A|0|0|1N|A|2G|K|3F|6|3O|F|4P|K|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|19|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|1D|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|1E|8|@$9|1F|A|1G|B|C]|$9|1H|A|1I|B|C]|$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]|$9|1N|A|1O|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1P|8|@]|D|@]|E|$]]|$1|S|3|T|5|L|7|1Q|8|@]|D|@]|E|$M|N]]|$1|U|3|V|5|6|7|1R|8|@]|D|@]|E|$]]|$1|W|3|X|5|L|7|1S|8|@]|D|@]|E|$M|N]]|$1|Y|3|-4|5|6|7|1T|8|@]|D|@]|E|$]]]|Z|$]]

Take your JSON and <code>.stringify()</code> it. Then use the <code>.replace()</code> method and replace all occurrences of <code>\n</code> with <code>\\n</code>. 

EDIT:

As far as I know of, there are no well-known JS libraries for escaping all special characters in a string. But, you could chain the <code>.replace()</code> method and replace all of the special characters like this:

<pre><code>var myJSONString = JSON.stringify(myJSON);
var myEscapedJSONString = myJSONString.replace(/\\n/g, "\\n")
 .replace(/\\'/g, "\\'")
 .replace(/\\"/g, '\\"')
 .replace(/\\&amp;/g, "\\&amp;")
 .replace(/\\r/g, "\\r")
 .replace(/\\t/g, "\\t")
 .replace(/\\b/g, "\\b")
 .replace(/\\f/g, "\\f");
// myEscapedJSONString is now ready to be POST'ed to the server. 
</code></pre>

But that's pretty nasty, isn't it? Enter the beauty of functions, in that they allow you to break code into pieces and keep the main flow of your script clean, and free of 8 chained <code>.replace()</code> calls. So let's put that functionality into a function called, <code>escapeSpecialChars()</code>. Let's go ahead and attach it to the <code>prototype chain</code> of the <code>String</code> object, so we can call <code>escapeSpecialChars()</code> directly on String objects.

Like so:

<pre><code>String.prototype.escapeSpecialChars = function() {
 return this.replace(/\\n/g, "\\n")
 .replace(/\\'/g, "\\'")
 .replace(/\\"/g, '\\"')
 .replace(/\\&amp;/g, "\\&amp;")
 .replace(/\\r/g, "\\r")
 .replace(/\\t/g, "\\t")
 .replace(/\\b/g, "\\b")
 .replace(/\\f/g, "\\f");
};
</code></pre>

Once we have defined that function, the main body of our code is as simple as this:

<pre><code>var myJSONString = JSON.stringify(myJSON);
var myEscapedJSONString = myJSONString.escapeSpecialChars();
// myEscapedJSONString is now ready to be POST'ed to the server
</code></pre>

blocks|key|1083880|text|按照user667073的建议，除了先对反斜杠替换进行重新排序，然后修复引号替换|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1083881|escape+=+function+(str)+{
++return+str
++++.replace(/[\\]/g,+'\\\\')
++++.replace(/[\"]/g,+'\\\"')
++++.replace(/[\/]/g,+'\\/')
++++.replace(/[\b]/g,+'\\b')
++++.replace(/[\f]/g,+'\\f')
++++.replace(/[\n]/g,+'\\n')
++++.replace(/[\r]/g,+'\\r')
++++.replace(/[\t]/g,+'\\t');
};|code-block|syntax|javascript|1083882|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

As per user667073 suggested, except reordering the backslash replacement first, and fixing the quote replacement

<pre><code>escape = function (str) {
 return str
 .replace(/[\\]/g, '\\\\')
 .replace(/[\"]/g, '\\\"')
 .replace(/[\/]/g, '\\/')
 .replace(/[\b]/g, '\\b')
 .replace(/[\f]/g, '\\f')
 .replace(/[\n]/g, '\\n')
 .replace(/[\r]/g, '\\r')
 .replace(/[\t]/g, '\\t');
};
</code></pre>

blocks|key|869110|text|在JSON.stringify上还有第二个参数。因此，更优雅的解决方案应该是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|869111|function+escape+(key,+val)+{
++++if+(typeof(val)!="string")+return+val;
++++return+val
++++++.replace(/[\"]/g,+'\\"')
++++++.replace(/[\\]/g,+'\\\\')
++++++.replace(/[\/]/g,+'\\/')
++++++.replace(/[\b]/g,+'\\b')
++++++.replace(/[\f]/g,+'\\f')
++++++.replace(/[\n]/g,+'\\n')
++++++.replace(/[\r]/g,+'\\r')
++++++.replace(/[\t]/g,+'\\t')
++++;+
}

var+myJSONString+=+JSON.stringify(myJSON,escape);|code-block|syntax|javascript|869112|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

There is also second parameter on JSON.stringify. So, more elegant solution would be:

<pre><code>function escape (key, val) {
 if (typeof(val)!="string") return val;
 return val
 .replace(/[\"]/g, '\\"')
 .replace(/[\\]/g, '\\\\')
 .replace(/[\/]/g, '\\/')
 .replace(/[\b]/g, '\\b')
 .replace(/[\f]/g, '\\f')
 .replace(/[\n]/g, '\\n')
 .replace(/[\r]/g, '\\r')
 .replace(/[\t]/g, '\\t')
 ; 
}

var myJSONString = JSON.stringify(myJSON,escape);
</code></pre>

blocks|key|869127|text|单引号的小更新|type|unstyled|depth|inlineStyleRanges|entityRanges|data|869128|function+escape+(key,+val)+{
++++if+(typeof(val)!="string")+return+val;
++++return+val++++++
++++++++.replace(/[\\]/g,+'\\\\')
++++++++.replace(/[\/]/g,+'\\/')
++++++++.replace(/[\b]/g,+'\\b')
++++++++.replace(/[\f]/g,+'\\f')
++++++++.replace(/[\n]/g,+'\\n')
++++++++.replace(/[\r]/g,+'\\r')
++++++++.replace(/[\t]/g,+'\\t')
++++++++.replace(/[\"]/g,+'\\"')
++++++++.replace(/\\'/g,+"\\'");+
}

var+myJSONString+=+JSON.stringify(myJSON,escape);|code-block|syntax|javascript|869129|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

A small update for single quotes

<pre><code>function escape (key, val) {
 if (typeof(val)!="string") return val;
 return val 
 .replace(/[\\]/g, '\\\\')
 .replace(/[\/]/g, '\\/')
 .replace(/[\b]/g, '\\b')
 .replace(/[\f]/g, '\\f')
 .replace(/[\n]/g, '\\n')
 .replace(/[\r]/g, '\\r')
 .replace(/[\t]/g, '\\t')
 .replace(/[\"]/g, '\\"')
 .replace(/\\'/g, "\\'"); 
}

var myJSONString = JSON.stringify(myJSON,escape);
</code></pre>

blocks|key|869172|text|我在一次Ajax调用中遇到了同样的情况，由于Textarea字段中的换行符，JSON抛出了一个错误。这里给出的解决方案对我不起作用。所以我使用了Javascript的.escape函数，它工作得很好。然后，为了从JSON中检索值，我只使用.unescape对其进行了非转义。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|869173|entityMap^0|12|4|2B|7|2Y|4|3B|9|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|G|$]]

I got same situation in one of my Ajax calls, where <code>JSON</code> was throwing an error due to the newline in the Textarea field. The solution given here didn't worked for me.
So i used Javascript's <code>.escape</code> function and it worked fine. Then to retrieve the value from <code>JSON</code>, I just unescaped using <code>.unescape</code>.

blocks|key|1083990|text|这是一个古老的问题，但这个解决方案对我来说并不是很有效，因为它并没有解决所有的情况。我终于找到了一个可以完成这项工作的答案here|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1083991|我将发布我使用转义和编码uri组件的组合解决方案：|1083992|//+implement+JSON+stringify+serialization
JSON.stringify+=+JSON.stringify+%7C%7C+function+(obj)+{
++++var+t+=+typeof+(obj);
++++if+(t+!=+"object"+%7C%7C+obj+===+null)+{
++++++++//+simple+data+type
++++++++if+(t+==+"string")+obj+=+'"'%2Bobj%2B'"';
++++++++return+String(obj);
++++}
++++else+{
++++++++//+recurse+array+or+object
++++++++var+n,+v,+json+=+[],+arr+=+(obj+&&+obj.constructor+==+Array);
++++++++for+(n+in+obj)+{
++++++++++++v+=+obj[n];+t+=+typeof(v);
++++++++++++if+(t+==+"string")+v+=+'"'%2Bv%2B'"';
++++++++++++else+if+(t+==+"object"+&&+v+!==+null)+v+=+JSON.stringify(v);
++++++++++++json.push((arr+?+""+:+'"'+%2B+n+%2B+'":')+%2B+String(v));
++++++++}
++++++++var+rawString+=+(arr+?+"["+:+"{")+%2B+String(json)+%2B+(arr+?+"]"+:+"}");
+++++++return+rawString;
++++}
};
function+escape+(key,+val)+{
++++if+(typeof(val)!="string")+return+val;

++++var+replaced+=+encodeURIComponent(val);
++++return+replaced;
}

JSON.stringifyEscaped+=+function(obj){
++++return+JSON.stringify(obj,escape);
}|code-block|syntax|javascript|1083993|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/5506000/javascript-json-stringify-doesnt-escape^0|1P|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

This is an old question but the solution did not work well for me as it did not solve all cases. I finally found an answer that did the job <a href="https://stackoverflow.com/questions/5506000/javascript-json-stringify-doesnt-escape">here</a>

I will post my combined solution of both using escape and encode uri component:

<pre><code>// implement JSON stringify serialization
JSON.stringify = JSON.stringify || function (obj) {
 var t = typeof (obj);
 if (t != "object" || obj === null) {
 // simple data type
 if (t == "string") obj = '"'+obj+'"';
 return String(obj);
 }
 else {
 // recurse array or object
 var n, v, json = [], arr = (obj &amp;&amp; obj.constructor == Array);
 for (n in obj) {
 v = obj[n]; t = typeof(v);
 if (t == "string") v = '"'+v+'"';
 else if (t == "object" &amp;&amp; v !== null) v = JSON.stringify(v);
 json.push((arr ? "" : '"' + n + '":') + String(v));
 }
 var rawString = (arr ? "[" : "{") + String(json) + (arr ? "]" : "}");
 return rawString;
 }
};
function escape (key, val) {
 if (typeof(val)!="string") return val;

 var replaced = encodeURIComponent(val);
 return replaced;
}

JSON.stringifyEscaped = function(obj){
 return JSON.stringify(obj,escape);
}
</code></pre>

blocks|key|1084166|text|在使用任何形式的Ajax时，从CGI服务器接收的响应的格式的详细文档在Web上似乎是缺乏的。这里的一些条目指出，返回的文本或json数据中的换行符必须转义，以防止JSON转换中的无限循环(挂起)(可能是由抛出未捕获的异常创建的)，无论是由jQuery自动完成还是使用Javascript系统或库JSON解析调用手动完成。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1084167|在程序员发布此问题的每一种情况下，都会提出不适当的解决方案(最常见的是在发送端将\n替换为\n+)，并放弃该问题。当传递意外嵌入控件转义序列的字符串值时，它们的不足就会暴露出来。例如"C:\Chris\Roberts.php"，它包含控制字符%5Ec和%5Er，这会导致字符串{"file":"C:\Chris\Roberts.php"}的JSON转换永远循环。生成这些值的一种方法是故意尝试将PHP警告和错误消息从服务器传递到客户端，这是一个合理的想法。|1084168|根据定义，Ajax在幕后使用HTTP连接。这类连接使用GET和POST传递数据，这两种连接都需要对发送的数据进行编码，以避免错误的语法，包括控制字符。|1084169|这给出了一个足够的线索来构造一个似乎是解决方案(它需要更多的测试)：在PHP+(发送)端使用rawurlencode来编码数据，在Javascript+(接收)端使用un转义来解码数据。在某些情况下，您将把它们应用于整个文本字符串，而在其他情况下，您将只将它们应用于JSON中的值。|1084170|如果这个想法被证明是正确的，那么可以构建简单的示例来帮助所有级别的程序员一劳永逸地解决这个问题。|1084171|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|N|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|O|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|K|$]]

When using any form of Ajax, detailed documentation for the format of responses received from the CGI server seems to be lacking on the Web. Some entries here point out that newlines in returned text or json data must be escaped to prevent infinite loops (hangs) in JSON conversion (possibly created by throwing an uncaught exception), whether done automatically by jQuery or manually using Javascript system or library JSON parsing calls.

In each case where programmers post this problem, inadequate solutions are presented (most often replacing \n by \\n on the sending side) and the matter is dropped. Their inadequacy is revealed when passing string values that accidentally embed control escape sequences, such as Windows pathnames. An example is "C:\Chris\Roberts.php", which contains the control characters ^c and ^r, which can cause JSON conversion of the string {"file":"C:\Chris\Roberts.php"} to loop forever. One way of generating such values is deliberately to attempt to pass PHP warning and error messages from server to client, a reasonable idea.

By definition, Ajax uses HTTP connections behind the scenes. Such connections pass data using GET and POST, both of which require encoding sent data to avoid incorrect syntax, including control characters.

This gives enough of a hint to construct what seems to be a solution (it needs more testing): to use rawurlencode on the PHP (sending) side to encode the data, and unescape on the Javascript (receiving) side to decode the data. In some cases, you will apply these to entire text strings, in other cases you will apply them only to values inside JSON.

If this idea turns out to be correct, simple examples can be constructed to help programmers at all levels solve this problem once and for all.

blocks|key|1084202|text|这是一个老帖子。但对于那些使用angular.fromJson和JSON.stringify的人来说，它可能仍然是有帮助的。转义()已弃用。用这个来代替，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1084203|var+uri_enc+=+encodeURIComponent(uri);+//before+you+post+the+contents
var+uri_dec+=+decodeURIComponent(uri_enc);+//before+you+display/use+the+contents.|code-block|syntax|javascript|1084204|参考http://www.w3schools.com/jsref/jsref_decodeuricomponent.asp|offset|length|1084205|entityMap|0|LINK|mutability|MUTABLE|url|http://www.w3schools.com/jsref/jsref_decodeuricomponent.asp^0|0|0|2|1N|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

this is an old post. but it may still be helpful for those using angular.fromJson, and JSON.stringify.
escape() is deprecated.
use this instead,

<pre><code>var uri_enc = encodeURIComponent(uri); //before you post the contents
var uri_dec = decodeURIComponent(uri_enc); //before you display/use the contents.
</code></pre>

ref <a href="http://www.w3schools.com/jsref/jsref_decodeuricomponent.asp">http://www.w3schools.com/jsref/jsref_decodeuricomponent.asp</a>

blocks|key|1084255|text|我使用内置的jQuery.serialize()从文本区域提取值来对输入进行urlencode。有利的部分是，你不必自己搜索替换每个特殊的字符，我也保留了换行符和转义html。为了让serialize工作，似乎输入字段需要有一个name属性，而且它还向转义的字符串添加了相同的属性，需要替换掉。这可能不是你想要的，但它对我很有效。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1084256|var+myinputfield+=+jQuery("#myinputfield");+
var+text+=+myinputfield.serialize();
text+=+text.replace(myinputfield.attr('name')+%2B+'=','');|code-block|syntax|javascript|1084257|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/serialize/^0|6|I|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

I used the built in <a href="http://api.jquery.com/serialize/" rel="nofollow">jQuery.serialize()</a> to extract the value from a textarea to urlencode the input. The pro part is that you don't have to search replace every special char on your own and i also keep the newlines and escapes html. For serialize to work it seems the input field needs to have a name attribute though and it also adds same attribute to the escaped string which needs to be replaced away. Might not be what you are looking for but it works for me.

<pre><code>var myinputfield = jQuery("#myinputfield"); 
var text = myinputfield.serialize();
text = text.replace(myinputfield.attr('name') + '=','');
</code></pre>

blocks|key|869536|text|和你一样，我也一直在研究一些评论和帖子，以替换我的JSON中包含html对象的特殊转义字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|869537|我的目标是删除JSON对象中的特殊字符，并呈现json对象中的html。|869538|这是我所做的，希望它使用起来非常简单。|869539|首先，我对json对象执行JSON.stringify操作，并对结果执行JSON.parse操作。|869540|例如：|869541|JSON.parse(JSON.stringify(jsonObject));|code-block|syntax|javascript|869542|它解决了我的问题，并使用纯Javascript完成。|869543|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|U|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|V|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|W|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|X|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Like you, I have been looking into several comments and post to replace special escape characters in my JSON which contains html object inside that. 

My object is to remove the special characters in JSON object and also render the html which is inside the json object.

Here is what I did and hope its very simple to use.

First I did JSON.stringify my json object and JSON.parse the result.

For eg:

<pre><code>JSON.parse(JSON.stringify(jsonObject));
</code></pre>

And it solves my problem and done using Pure Javascript.

blocks|key|869621|text|看起来这真的是一个古老的帖子:-)但是伙计们，我有的最好的变通办法是100%25的工作，没有复杂的代码，是使用编码/解码到base64的两个函数。它们是atob()和btoa()。到目前为止，最简单和最好的方法是，如果您遗漏了任何要转义的字符，则无需担心。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|869622|乔治|869623|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

Looks like this is an ancient post really :-) But guys, the best workaround I have for this, to be 100% that it works without complicated code, is to use both functions of encoding/decoding to base64. These are atob() and btoa(). By far the easiest and best way, no need to worry if you missed any characters to be escaped.

George

blocks|key|869632|text|最好使用JSON.parse(yourUnescapedJson);|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|869633|entityMap^0|4|U|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

It's better to use <code>JSON.parse(yourUnescapedJson);</code>

blocks|key|869670|text|使用encodeURIComponent()对字符串进行编码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|869671|例如：var+myEscapedJSONString+=+encodeURIComponent(JSON.stringify(myJSON))；|869672|你不需要解码它，因为web服务器会自动解码。|869673|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

Use encodeURIComponent() to encode the string.

Eg. var myEscapedJSONString = encodeURIComponent(JSON.stringify(myJSON));

You don't need to decode it since the web server automatically do the same.

blocks|key|869685|text|RegExp单行，使用以下函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|869686|function+escapeJSON(string)+{
++++return+string.replace(/[\n"\&\r\t\b\f]/g,+'\\$&');
}|code-block|syntax|javascript|869687|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

RegExp single line, use this function:
<pre><code>function escapeJSON(string) {
 return string.replace(/[\n&quot;\&amp;\r\t\b\f]/g, '\\$&amp;');
}
</code></pre>

I have to form a JSON string in which a value is having new line character. This has to be escaped and then posted using AJAX call. Can any one suggest a way to escape the string with JavaScript. I am not using jQuery.

How to escape a JSON string containing newline characters using JavaScript?

我必须形成一个JSON字符串，其中的值包含换行符。这必须转义，然后使用AJAX调用发布。有没有人能建议一种用JavaScript转义字符串的方法。我没有使用jQuery。

问如何使用JavaScript对包含换行符的JSON字符串进行转义？
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