blocks|key|792285|text|使用raw_input()而不是input()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|792286|testVar+=+raw_input("Ask+user+for+something.")|code-block|syntax|javascript|792287|input()实际上将输入计算为Python代码。我建议永远不要使用它。raw_input()返回用户输入的逐字字符串。|792288|entityMap^0|2|B|G|7|0|0|0|7|10|B|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|N|$]]

Use <code>raw_input()</code> instead of <code>input()</code>:

<pre><code>testVar = raw_input("Ask user for something.")
</code></pre>

<code>input()</code> actually evaluates the input as Python code. I suggest to never use it. <code>raw_input()</code> returns the verbatim string entered by the user.

blocks|key|1006271|text|函数input还将计算它作为python代码读取的数据，这并不是您真正想要的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1006272|一般的方法是像对待任何其他文件一样对待用户输入(来自sys.stdin)。试一试|1006273|import+sys
sys.stdin.readline()|code-block|syntax|javascript|1006274|如果想保持简短，可以使用与input相同但省略求值的raw_input。|1006275|entityMap^0|2|5|0|Q|9|0|0|D|5|Q|9|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|P|$]]

The function <code>input</code> will also evaluate the data it just read as python code, which is not really what you want.

The generic approach would be to treat the user input (from <code>sys.stdin</code>) like any other file. Try

<pre><code>import sys
sys.stdin.readline()
</code></pre>

If you want to keep it short, you can use <code>raw_input</code> which is the same as <code>input</code> but omits the evaluation.

blocks|key|1006305|text|testVar+=+raw_input("Ask+user+for+something.")|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1006306|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>testVar = raw_input("Ask user for something.")
</code></pre>

blocks|key|792416|text|该问题似乎已在Python版本3.4.2中得到解决。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|792417|testVar+=+input("Ask+user+for+something.")|code-block|syntax|javascript|792418|都会工作得很好。|792419|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The issue seems to be resolved in Python version 3.4.2.

<pre><code>testVar = input("Ask user for something.")
</code></pre>

Will work fine.

blocks|key|1006397|text|如果您想在Python2.x中使用input而不是raw_input，那么这个技巧将非常有用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1006398|++++if+hasattr(__builtins__,+'raw_input'):
++++++input=raw_input|code-block|syntax|javascript|1006399|之后，|1006400|testVar+=+input("Ask+user+for+something.")|1006401|将会工作得很好。|1006402|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

If you want to use input instead of raw_input in python 2.x,then this trick will come handy

<pre><code> if hasattr(__builtins__, 'raw_input'):
 input=raw_input
</code></pre>

After which,

<pre><code>testVar = input("Ask user for something.")
</code></pre>

will work just fine.

blocks|key|1006432|text|我的修复工作代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1006433|import+random
import+math
print+"Welcome+to+Sam's+Math+Test"
num1=+random.randint(1,+10)
num2=+random.randint(1,+10)
num3=+random.randint(1,+10)
list=[num1,+num2,+num3]
maxNum=+max(list)
minNum=+min(list)
sqrtOne=+math.sqrt(num1)

correct=+False
while(correct+==+False):
++++guess1=+input("Which+number+is+the+highest?+"%2B+str(list)+%2B+":+")
++++if+maxNum+==+guess1:
++++++++print("Correct!")
++++++++correct+=+True
++++else:
++++++++print("Incorrect,+try+again")

correct=+False
while(correct+==+False):
guess2=+input("Which+number+is+the+lowest?+"+%2B+str(list)+%2B":+")
if+minNum+==+guess2:
+++++print("Correct!")
+++++correct+=+True
else:
++++print("Incorrect,+try+again")

correct=+False
while(correct+==+False):
++++guess3=+raw_input("Is+the+square+root+of+"+%2B+str(num1)+%2B+"+greater+than+or+equal+to+2?+(y/n):+")
++++if+sqrtOne+>=+2.0+and+str(guess3)+==+"y":
++++++++print("Correct!")
++++++++correct+=+True
++++elif+sqrtOne+<+2.0+and+str(guess3)+==+"n":
++++++++print("Correct!")
++++++++correct+=+True
++++else:
++++++++print("Incorrect,+try+again")

print("Thanks+for+playing!")|code-block|syntax|javascript|1006434|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

My Working code with fixes:

<pre><code>import random
import math
print "Welcome to Sam's Math Test"
num1= random.randint(1, 10)
num2= random.randint(1, 10)
num3= random.randint(1, 10)
list=[num1, num2, num3]
maxNum= max(list)
minNum= min(list)
sqrtOne= math.sqrt(num1)

correct= False
while(correct == False):
 guess1= input("Which number is the highest? "+ str(list) + ": ")
 if maxNum == guess1:
 print("Correct!")
 correct = True
 else:
 print("Incorrect, try again")

correct= False
while(correct == False):
guess2= input("Which number is the lowest? " + str(list) +": ")
if minNum == guess2:
 print("Correct!")
 correct = True
else:
 print("Incorrect, try again")

correct= False
while(correct == False):
 guess3= raw_input("Is the square root of " + str(num1) + " greater than or equal to 2? (y/n): ")
 if sqrtOne &gt;= 2.0 and str(guess3) == "y":
 print("Correct!")
 correct = True
 elif sqrtOne &lt; 2.0 and str(guess3) == "n":
 print("Correct!")
 correct = True
 else:
 print("Incorrect, try again")

print("Thanks for playing!")
</code></pre>

blocks|key|792549|text|这是我的工作，以防将来我需要迁移到python3时的故障安全。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|792550|def+_input(msg):
++return+raw_input(msg)|code-block|syntax|javascript|792551|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is my work around to fail safe in case if i will need to move to python 3 in future.

<pre><code>def _input(msg):
 return raw_input(msg)
</code></pre>

blocks|key|1006552|text|我们可以在Python2中使用raw_input()函数，在Python3中使用input()函数。默认情况下，input函数接受字符串格式的输入。对于其他数据类型，您必须强制转换用户输入。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1006553|在Python2中，我们使用raw_input()函数。它等待用户键入一些输入并按下return，我们需要通过强制转换为我们想要的数据类型来将值存储在一个变量中。使用类型转换时要小心|1006554|x+=+raw_input("Enter+a+number:+")+#String+input

x+=+int(raw_input("Enter+a+number:+"))+#integer+input

x+=+float(raw_input("Enter+a+float+number:+"))+#float+input

x+=+eval(raw_input("Enter+a+float+number:+"))+#eval+input|code-block|syntax|javascript|1006555|在Python3中，我们使用input()函数，它返回一个用户输入值。|1006556|x+=+input("Enter+a+number:+")+#String+input|1006557|如果你输入一个字符串，int，float，eval，它将被当作字符串输入|1006558|x+=+int(input("Enter+a+number:+"))+#integer+input|1006559|如果您为int+cast+ValueError:+invalid+literal+for+int()+with+base+10:输入字符串|1006560|x+=+float(input("Enter+a+float+number:+"))+#float+input|1006561|如果为浮点型转换ValueError:+could+not+convert+string+to+float输入字符串|1006562|x+=+eval(input("Enter+a+float+number:+"))+#eval+input|1006563|如果您为eval+cast+NameError:+name+'+'+is+not+defined输入一个字符串，这些错误也适用于Python2。|1006564|entityMap^0|F|B|14|7|0|E|B|16|6|0|0|0|0|0|0|D|1F|0|0|8|19|0|0|E|Y|0^^$0|@$1|2|3|4|5|6|7|16|8|@$9|17|A|18|B|C]|$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1B|8|@$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|1G|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1H|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|1I|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|1J|8|@]|D|@]|E|$]]|$1|S|3|T|5|J|7|1K|8|@]|D|@]|E|$K|L]]|$1|U|3|V|5|6|7|1L|8|@$9|1M|A|1N|B|C]]|D|@]|E|$]]|$1|W|3|X|5|J|7|1O|8|@]|D|@]|E|$K|L]]|$1|Y|3|Z|5|6|7|1P|8|@$9|1Q|A|1R|B|C]]|D|@]|E|$]]|$1|10|3|11|5|J|7|1S|8|@]|D|@]|E|$K|L]]|$1|12|3|13|5|6|7|1T|8|@$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|14|3|-4|5|6|7|1W|8|@]|D|@]|E|$]]]|15|$]]

We can use the <code>raw_input()</code> function in Python 2 and the <code>input()</code> function in Python 3.
By default the input function takes an input in string format. For other data type you have to cast the user input.

In Python 2 we use the <code>raw_input()</code> function. It waits for the user to type some input and press <code>return</code> and we need to store the value in a variable by casting as our desire data type. Be careful when using type casting

<pre><code>x = raw_input("Enter a number: ") #String input

x = int(raw_input("Enter a number: ")) #integer input

x = float(raw_input("Enter a float number: ")) #float input

x = eval(raw_input("Enter a float number: ")) #eval input
</code></pre>

In Python 3 we use the input() function which returns a user input value.

<pre><code>x = input("Enter a number: ") #String input
</code></pre>

If you enter a string, int, float, eval it will take as string input

<pre><code>x = int(input("Enter a number: ")) #integer input
</code></pre>

If you enter a string for int cast <code>ValueError: invalid literal for int() with base 10:</code>

<pre><code>x = float(input("Enter a float number: ")) #float input
</code></pre>

If you enter a string for float cast <code>ValueError: could not convert string to float</code>

<pre><code>x = eval(input("Enter a float number: ")) #eval input
</code></pre>

If you enter a string for eval cast <code>NameError: name ' ' is not defined</code>
 Those error also applicable for Python 2.

I want to get a string from a user, and then to manipulate it.

<pre><code>testVar = input("Ask user for something.")
</code></pre>

Is there a way for testVar to be a string without me having the user type his response in quotes? i.e. "Hello" vs. Hello

If the user types in Hello, I get the following error:

NameError: name 'Hello' is not defined

Python 2.7 getting user input and manipulating as string without quotations

Python

我想从用户那里获取一个字符串，然后对其进行操作。testVar = input("Ask user for something.")有没有办法让testVar成为一个字符串，而不是让用户在引号中输入响应？即" Hello“vs. Hello如果用户输入Hello，我会得到以下错误：NameError:未定义名称“Hel...

问Python 2.7获取用户输入并将其作为不带引号的字符串进行操作
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