如何检查浏览器是否有挂起的请求(Ajax及其变体
如何检查浏览器是否有挂起的请求(Ajax及其变体
提问于 2014-06-19 12:42:36
我处理的一些站点有繁重的ajax请求。我计划在单击断言for元素之前等待Ajax请求完成。目前我使用的是
try {
if (driver instanceof JavascriptExecutor) {
JavascriptExecutor jsDriver = (JavascriptExecutor)driver;
for (int i = 0; i< timeoutInSeconds; i++)
{
Object numberOfAjaxConnections = jsDriver.executeScript("return jQuery.active");
// return should be a number
if (numberOfAjaxConnections instanceof Long) {
Long n = (Long)numberOfAjaxConnections;
System.out.println("Number of active jquery ajax calls: " + n);
if (n.longValue() == 0L) break;
}
Thread.sleep(1000);
}
}
else {
System.out.println("Web driver: " + driver + " cannot execute javascript");
}
}
catch (InterruptedException e) {
System.out.println(e);
}但是对于Ajax请求，它工作得很好，但对于任何使用jQuery库变体的类似请求，它都不能很好地工作。
注意：
document.readyState == 'complete'它不适用于Ajax请求或任何其他类似的替代方案。
这两个测试都不是我写的，也不属于单一的webapp。所以我不能编辑网络应用。
回答 2
Stack Overflow用户
回答已采纳
发布于 2014-06-26 18:49:38
我找到了答案，它适用于我检查过的少数Ajax和非ajax站点。在这个补丁之后，我不再需要做隐式等待，即使是ajax繁重的页面，LeGac在他对这个问题的一条评论中指出了以下代码。
public static void checkPendingRequests(FirefoxDriver driver) {
int timeoutInSeconds = 5;
try {
if (driver instanceof JavascriptExecutor) {
JavascriptExecutor jsDriver = (JavascriptExecutor)driver;
for (int i = 0; i< timeoutInSeconds; i++)
{
Object numberOfAjaxConnections = jsDriver.executeScript("return window.openHTTPs");
// return should be a number
if (numberOfAjaxConnections instanceof Long) {
Long n = (Long)numberOfAjaxConnections;
System.out.println("Number of active calls: " + n);
if (n.longValue() == 0L) break;
} else{
// If it's not a number, the page might have been freshly loaded indicating the monkey
// patch is replaced or we haven't yet done the patch.
monkeyPatchXMLHttpRequest(driver);
}
Thread.sleep(1000);
}
}
else {
System.out.println("Web driver: " + driver + " cannot execute javascript");
}
}
catch (InterruptedException e) {
System.out.println(e);
}
}
public static void monkeyPatchXMLHttpRequest(FirefoxDriver driver) {
try {
if (driver instanceof JavascriptExecutor) {
JavascriptExecutor jsDriver = (JavascriptExecutor)driver;
Object numberOfAjaxConnections = jsDriver.executeScript("return window.openHTTPs");
if (numberOfAjaxConnections instanceof Long) {
return;
}
String script = " (function() {" +
"var oldOpen = XMLHttpRequest.prototype.open;" +
"window.openHTTPs = 0;" +
"XMLHttpRequest.prototype.open = function(method, url, async, user, pass) {" +
"window.openHTTPs++;" +
"this.addEventListener('readystatechange', function() {" +
"if(this.readyState == 4) {" +
"window.openHTTPs--;" +
"}" +
"}, false);" +
"oldOpen.call(this, method, url, async, user, pass);" +
"}" +
"})();";
jsDriver.executeScript(script);
}
else {
System.out.println("Web driver: " + driver + " cannot execute javascript");
}
}
catch (Exception e) {
System.out.println(e);
}
}在每一步之后，您都需要调用
checkPendingRequests(driver);Stack Overflow用户
发布于 2014-06-26 04:34:21
这不起作用？http://api.jquery.com/ajaxstop/
$(document).ajaxStop(function() {
// Do stuff here...
});页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/24298925
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