blocks|key|1344|text|datetime模块是您的好朋友：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1345|import+datetime
now+=+datetime.datetime.now()
print(now.year,+now.month,+now.day,+now.hour,+now.minute,+now.second)
#+2015+5+6+8+53+40|code-block|syntax|javascript|1346|您不需要单独的变量，返回的datetime对象上的属性具有您需要的所有内容。|1347|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/2/library/datetime.html#datetime.datetime.now^0|0|8|0|8|0|0|0|D|8|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

The <a href="https://docs.python.org/2/library/datetime.html#datetime.datetime.now" rel="noreferrer"><code>datetime</code></a> module is your friend:
<pre><code>import datetime
now = datetime.datetime.now()
print(now.year, now.month, now.day, now.hour, now.minute, now.second)
# 2015 5 6 8 53 40
</code></pre>
You don't need separate variables, the attributes on the returned <code>datetime</code> object have all you need.

blocks|key|1385|text|通过解压datetime对象的timetuple，你应该会得到你想要的：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1386|from+datetime+import+datetime

n+=+datetime.now()
t+=+n.timetuple()
y,+m,+d,+h,+min,+sec,+wd,+yd,+i+=+t|code-block|syntax|javascript|1387|entityMap^0|F|9|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

By unpacking <code>timetuple</code> of datetime object, you should get what you want:

<pre><code>from datetime import datetime

n = datetime.now()
t = n.timetuple()
y, m, d, h, min, sec, wd, yd, i = t
</code></pre>

blocks|key|4509020|text|tzaman的datetime答案要简洁得多，但您可以使用原始的python+time模块来完成：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4509021|import+time
strings+=+time.strftime("%25Y,%25m,%25d,%25H,%25M,%25S")
t+=+strings.split(',')
numbers+=+[+int(x)+for+x+in+t+]
print+numbers|code-block|syntax|javascript|4509022|输出：|4509023|[2016,+3,+11,+8,+29,+47]|4509024|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/30071999/3596187^0|7|8|13|4|0|6|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]]|E|$]]|$1|F|3|G|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|15|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

The <code>datetime</code> answer by <a href="https://stackoverflow.com/a/30071999/3596187">tzaman</a> is much cleaner, but you can do it with the original python <code>time</code> module:

<pre><code>import time
strings = time.strftime("%Y,%m,%d,%H,%M,%S")
t = strings.split(',')
numbers = [ int(x) for x in t ]
print numbers
</code></pre>

Output:

<pre><code>[2016, 3, 11, 8, 29, 47]
</code></pre>

blocks|key|4509055|text|这是一个最多80个字符的一行代码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4509056|import+time
year,+month,+day,+hour,+min+=+map(int,+time.strftime("%25Y+%25m+%25d+%25H+%25M").split())|code-block|syntax|javascript|4509057|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here's a one-liner that comes in just under the 80 char line max.

<pre><code>import time
year, month, day, hour, min = map(int, time.strftime("%Y %m %d %H %M").split())
</code></pre>

blocks|key|4509080|text|三个用于访问和操作日期和时间的库，即日期时间、箭头和钟摆，都使这些项在命名元组中可用，其元素可以通过名称或索引访问。此外，可以通过完全相同的方式访问这些项。(我想，如果我更聪明，我也不会感到惊讶。)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4509081|>>>+YEARS,+MONTHS,+DAYS,+HOURS,+MINUTES+=+range(5)
>>>+import+datetime
>>>+import+arrow
>>>+import+pendulum
>>>+[datetime.datetime.now().timetuple()[i]+for+i+in+[YEARS,+MONTHS,+DAYS,+HOURS,+MINUTES]]
[2017,+6,+16,+19,+15]
>>>+[arrow.now().timetuple()[i]+for+i+in+[YEARS,+MONTHS,+DAYS,+HOURS,+MINUTES]]
[2017,+6,+16,+19,+15]
>>>+[pendulum.now().timetuple()[i]+for+i+in+[YEARS,+MONTHS,+DAYS,+HOURS,+MINUTES]]
[2017,+6,+16,+19,+16]|code-block|syntax|javascript|4509082|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Three libraries for accessing and manipulating dates and times, namely datetime, arrow and pendulum, all make these items available in namedtuples whose elements are accessible either by name or index. Moreover, the items are accessible in precisely the same way. (I suppose if I were more intelligent I wouldn't be surprised.)

<pre><code>&gt;&gt;&gt; YEARS, MONTHS, DAYS, HOURS, MINUTES = range(5)
&gt;&gt;&gt; import datetime
&gt;&gt;&gt; import arrow
&gt;&gt;&gt; import pendulum
&gt;&gt;&gt; [datetime.datetime.now().timetuple()[i] for i in [YEARS, MONTHS, DAYS, HOURS, MINUTES]]
[2017, 6, 16, 19, 15]
&gt;&gt;&gt; [arrow.now().timetuple()[i] for i in [YEARS, MONTHS, DAYS, HOURS, MINUTES]]
[2017, 6, 16, 19, 15]
&gt;&gt;&gt; [pendulum.now().timetuple()[i] for i in [YEARS, MONTHS, DAYS, HOURS, MINUTES]]
[2017, 6, 16, 19, 16]
</code></pre>

blocks|key|4509107|text|这是一个较老的问题，但我想出了一个解决方案，我认为其他人可能会喜欢。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4509108|def+get_current_datetime_as_dict():
n+=+datetime.now()
t+=+n.timetuple()
field_names+=+["year",
+++++++++++++++"month",
+++++++++++++++"day",
+++++++++++++++"hour",
+++++++++++++++"min",
+++++++++++++++"sec",
+++++++++++++++"weekday",
+++++++++++++++"md",
+++++++++++++++"yd"]
return+dict(zip(field_names,+t))|code-block|syntax|javascript|4509109|timetuple()可以与另一个数组压缩在一起，后者创建带标签的元组。将其转换为字典，生成的产品可以通过get_current_datetime_as_dict()['year']使用。|offset|length|style|CODE|4509110|这比这里的一些其他解决方案有更多的开销，但我发现能够在代码中访问命名值是非常好的。|4509111|entityMap^0|0|0|1H|12|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

This is an older question, but I came up with a solution I thought others might like.

<pre><code>def get_current_datetime_as_dict():
n = datetime.now()
t = n.timetuple()
field_names = ["year",
 "month",
 "day",
 "hour",
 "min",
 "sec",
 "weekday",
 "md",
 "yd"]
return dict(zip(field_names, t))
</code></pre>

timetuple() can be zipped with another array, which creates labeled tuples. Cast that to a dictionary and the resultant product can be consumed with <code>get_current_datetime_as_dict()['year']</code>.

This has a little more overhead than some of the other solutions on here, but I've found it's so nice to be able to access named values for clartiy's sake in the code.

blocks|key|4509119|text|import+time
year+=+time.strftime("%25Y")+#+or+"%25y"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4509120|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import time
year = time.strftime("%Y") # or "%y"
</code></pre>

blocks|key|1495|text|您可以使用gmtime|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1496|from+time+import+gmtime

detailed_time+=+gmtime()+
#returns+a+struct_time+object+for+current+time

year+=+detailed_time.tm_year
month+=+detailed_time.tm_mon
day+=+detailed_time.tm_mday
hour+=+detailed_time.tm_hour
minute+=+detailed_time.tm_min|code-block|syntax|javascript|1497|注意:时间戳可以传递给gmtime，默认是time()返回的当前时间|1498|eg.
gmtime(1521174681)|1499|请参阅struct_time|offset|length|1500|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/time.html#time.struct_time^0|0|0|0|0|3|B|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

You can use gmtime

<pre><code>from time import gmtime

detailed_time = gmtime() 
#returns a struct_time object for current time

year = detailed_time.tm_year
month = detailed_time.tm_mon
day = detailed_time.tm_mday
hour = detailed_time.tm_hour
minute = detailed_time.tm_min
</code></pre>

Note: A time stamp can be passed to gmtime, default is current time as 
returned by time()

<pre><code>eg.
gmtime(1521174681)
</code></pre>

See <a href="https://docs.python.org/3/library/time.html#time.struct_time" rel="nofollow noreferrer">struct_time</a>

blocks|key|1516|text|让我们看看如何从当前时间获取并打印python中的日、月、年：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1517|import+datetime

now+=+datetime.datetime.now()
year+=+'{:02d}'.format(now.year)
month+=+'{:02d}'.format(now.month)
day+=+'{:02d}'.format(now.day)
hour+=+'{:02d}'.format(now.hour)
minute+=+'{:02d}'.format(now.minute)
day_month_year+=+'{}-{}-{}'.format(year,+month,+day)

print('day_month_year:+'+%2B+day_month_year)|code-block|syntax|javascript|1518|结果：|1519|day_month_year:+2019-03-26|1520|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Let's see how to get and print day,month,year in python from current time:

<pre><code>import datetime

now = datetime.datetime.now()
year = '{:02d}'.format(now.year)
month = '{:02d}'.format(now.month)
day = '{:02d}'.format(now.day)
hour = '{:02d}'.format(now.hour)
minute = '{:02d}'.format(now.minute)
day_month_year = '{}-{}-{}'.format(year, month, day)

print('day_month_year: ' + day_month_year)
</code></pre>

result:

<pre><code>day_month_year: 2019-03-26
</code></pre>

I would like to get the current time in Python and assign them into variables like <code>year</code>, <code>month</code>, <code>day</code>, <code>hour</code>, <code>minute</code>. How can this be done in Python 2.7?

How to get current time in python and break up into year, month, day, hour, minute?

Python

我想在Python语言中获取当前时间，并将其赋值为变量，如year、month、day、hour、minute。在Python2.7中如何做到这一点呢？

问如何在python中获取当前时间，并将其分解为年、月、日、小时、分钟？
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问如何在python中获取当前时间，并将其分解为年、月、日、小时、分钟？EN

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问如何在python中获取当前时间，并将其分解为年、月、日、小时、分钟？
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