blocks|key|1356921|text|import+os
def+get_immediate_subdirectories(a_dir):
++++return+[name+for+name+in+os.listdir(a_dir)
++++++++++++if+os.path.isdir(os.path.join(a_dir,+name))]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1356922|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import os
def get_immediate_subdirectories(a_dir):
 return [name for name in os.listdir(a_dir)
 if os.path.isdir(os.path.join(a_dir, name))]
</code></pre>

blocks|key|1357054|text|为什么没有人提到glob？glob允许你使用Unix风格的路径名扩展，并且是我的go函数，几乎可以用来查找多个路径名。这让它变得非常简单：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1357055|from+glob+import+glob
paths+=+glob('*/')|code-block|syntax|javascript|1357056|请注意，glob将返回带有最后一个斜杠的目录(就像unix一样)，而大多数基于path的解决方案将省略最后一个斜杠。|1357057|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/2/library/glob.html^0|8|4|D|4|8|4|0|0|0|4|4|13|4|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@$9|14|A|15|B|C]|$9|16|A|17|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

Why has no one mentioned <a href="https://docs.python.org/2/library/glob.html" rel="noreferrer"><code>glob</code></a>? <code>glob</code> lets you use Unix-style pathname expansion, and is my go to function for almost everything that needs to find more than one path name. It makes it very easy:

<pre><code>from glob import glob
paths = glob('*/')
</code></pre>

Note that <code>glob</code> will return the directory with the final slash (as unix would) while most <code>path</code> based solutions will omit the final slash.

blocks|key|1357106|text|检查"Getting+a+list+of+all+subdirectories+in+the+current+directory“。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1357107|以下是Python+3的一个版本：|1357108|import+os

dir_list+=+next(os.walk('.'))[1]

print(dir_list)|code-block|syntax|javascript|1357109|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/973473/getting-a-list-of-all-subdirectories-in-the-current-directory/973488#973488^0|3|1P|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

Check "<a href="https://stackoverflow.com/questions/973473/getting-a-list-of-all-subdirectories-in-the-current-directory/973488#973488">Getting a list of all subdirectories in the current directory</a>".

Here's a Python 3 version:

<pre><code>import os

dir_list = next(os.walk('.'))[1]

print(dir_list)
</code></pre>

blocks|key|1357159|text|这个方法很好地一次完成了所有的工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1357160|from+glob+import+glob
subd+=+[s.rstrip("/")+for+s+in+glob(parent_dir%2B"*/")]|code-block|syntax|javascript|1357161|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This method nicely does it all in one go.

<pre><code>from glob import glob
subd = [s.rstrip("/") for s in glob(parent_dir+"*/")]
</code></pre>

blocks|key|1572157|text|我只是编写了一些代码来移动vmware虚拟机，最后使用os.path和shutil来完成子目录之间的文件复制。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1572158|def+copy_client_files+(file_src,+file_dst):
++++for+file+in+os.listdir(file_src):
++++++++++++print+"Copying+file:+%25s"+%25+file
++++++++++++shutil.copy(os.path.join(file_src,+file),+os.path.join(file_dst,+file))|code-block|syntax|javascript|1572159|它不是非常优雅，但它确实可以工作。|1572160|entityMap^0|R|7|Z|6|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

I just wrote some code to move vmware virtual machines around, and ended up using <code>os.path</code> and <code>shutil</code> to accomplish file copying between sub-directories.

<pre><code>def copy_client_files (file_src, file_dst):
 for file in os.listdir(file_src):
 print "Copying file: %s" % file
 shutil.copy(os.path.join(file_src, file), os.path.join(file_dst, file))
</code></pre>

It's not terribly elegant, but it does work.

blocks|key|1572089|text|这里有一种方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1572090|import+os
import+shutil

def+copy_over(path,+from_name,+to_name):
++for+path,+dirname,+fnames+in+os.walk(path):
++++for+fname+in+fnames:
++++++if+fname+==+from_name:
++++++++shutil.copy(os.path.join(path,+from_name),+os.path.join(path,+to_name))


copy_over('.',+'index.tpl',+'index.html')|code-block|syntax|javascript|1572091|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here's one way:

<pre><code>import os
import shutil

def copy_over(path, from_name, to_name):
 for path, dirname, fnames in os.walk(path):
 for fname in fnames:
 if fname == from_name:
 shutil.copy(os.path.join(path, from_name), os.path.join(path, to_name))


copy_over('.', 'index.tpl', 'index.html')
</code></pre>

blocks|key|1357196|text|def+get_folders_in_directories_recursively(directory,+index=0):
++++folder_list+=+list()
++++parent_directory+=+directory

++++for+path,+subdirs,+_+in+os.walk(directory):
++++++++if+not+index:
++++++++++++for+sdirs+in+subdirs:
++++++++++++++++folder_path+=+"{}/{}".format(path,+sdirs)
++++++++++++++++folder_list.append(folder_path)
++++++++elif+path[len(parent_directory):].count('/')+%2B+1+==+index:
++++++++++++for+sdirs+in+subdirs:
++++++++++++++++folder_path+=+"{}/{}".format(path,+sdirs)
++++++++++++++++folder_list.append(folder_path)

++++return+folder_list|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1357197|可以按如下方式调用以下函数：|unstyled|1357198|get_folders_in_directories_recursively(directory，index=1)+->提供了第一级的文件夹列表|1357199|get_folders_in_directories_recursively(directory)+->提供了所有子文件夹|1357200|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|F|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>def get_folders_in_directories_recursively(directory, index=0):
 folder_list = list()
 parent_directory = directory

 for path, subdirs, _ in os.walk(directory):
 if not index:
 for sdirs in subdirs:
 folder_path = &quot;{}/{}&quot;.format(path, sdirs)
 folder_list.append(folder_path)
 elif path[len(parent_directory):].count('/') + 1 == index:
 for sdirs in subdirs:
 folder_path = &quot;{}/{}&quot;.format(path, sdirs)
 folder_list.append(folder_path)

 return folder_list
</code></pre>
The following function can be called as:
get_folders_in_directories_recursively(directory, index=1) -&gt; gives the list of folders in first level
get_folders_in_directories_recursively(directory) -&gt; gives all the sub folders

blocks|key|1572356|text|import+pathlib


def+list_dir(dir):
++++path+=+pathlib.Path(dir)
++++dir+=+[]
++++try:
++++++++for+item+in+path.iterdir():
++++++++++++if+item.is_dir():
++++++++++++++++dir.append(item)
++++++++return+dir
++++except+FileNotFoundError:
++++++++print('Invalid+directory')|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1572357|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre class="lang-py prettyprint-override"><code>import pathlib


def list_dir(dir):
 path = pathlib.Path(dir)
 dir = []
 try:
 for item in path.iterdir():
 if item.is_dir():
 dir.append(item)
 return dir
 except FileNotFoundError:
 print('Invalid directory')
</code></pre>

blocks|key|1572409|text|一个使用pathlib的线性程序：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1572410|list_subfolders_with_paths+=+[p+for+p+in+pathlib.Path(path).iterdir()+if+p.is_dir()]|code-block|syntax|javascript|1572411|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

One liner using pathlib:

<pre><code>list_subfolders_with_paths = [p for p in pathlib.Path(path).iterdir() if p.is_dir()]
</code></pre>

I'm trying to write a simple Python script that will copy a index.tpl to index.html in all of the subdirectories (with a few exceptions). 

I'm getting bogged down by trying to get the list of subdirectories.

How to get all of the immediate subdirectories in Python

我正在尝试编写一个简单的Python脚本，它会将一个index.tpl复制到所有子目录中的index.html中(有几个例外)。我在尝试获取子目录的列表时陷入了困境。

问如何在Python中获取所有的直接子目录
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回答 9

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问如何在Python中获取所有的直接子目录
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