blocks|key|445458|text|path+=+path.substring(0,+path.length()+-+5);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|445459|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>path = path.substring(0, path.length() - 5);
</code></pre>

blocks|key|659904|text|如果您想删除最后5个字符，您可以使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|659905|path.substring(0,path.length()+-+5)|code-block|syntax|javascript|659906|(可以包含一个错误;)|659907|如果你想删除一些变量字符串：|659908|path.substring(0,path.lastIndexOf('yoursubstringtoremove));|659909|(也可以包含一个错误;)|659910|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

If you like to remove last 5 characters, you can use:

<pre><code>path.substring(0,path.length() - 5)
</code></pre>

( could contain off by one error ;) ) 

If you like to remove some variable string:

<pre><code>path.substring(0,path.lastIndexOf('yoursubstringtoremove));
</code></pre>

(could also contain off by one error ;) )

blocks|key|659972|text|令我惊讶的是，所有其他答案(截至2013年9月8日)要么涉及计算子字符串".null"中的字符数，要么在没有找到子串的情况下抛出StringIndexOutOfBoundsException。或两者兼而有之：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|659973|我的建议如下：|659974|public+class+Main+{

++++public+static+void+main(String[]+args)+{

++++++++String+path+=+"file.txt";
++++++++String+extension+=+".doc";

++++++++int+position+=+path.lastIndexOf(extension);

++++++++if+(position!=-1)
++++++++++++path+=+path.substring(0,+position);
++++++++else
++++++++++++System.out.println("Extension:+"%2Bextension%2B"+not+found");

++++++++System.out.println("Result:+"%2Bpath);
++++}

}|code-block|syntax|javascript|659975|如果没有找到子字符串，则不会发生任何操作，因为没有要截断的内容。你不会得到StringIndexOutOfBoundsException的。此外，您不必自己计算子字符串中的字符。|659976|entityMap^0|10|7|1S|V|0|0|0|11|V|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|P|$]]

I am surprised to see that all the other answers (as of Sep 8, 2013) either involve counting the number of characters in the substring <code>".null"</code> or throw a <code>StringIndexOutOfBoundsException</code> if the substring is not found. Or both :( 

I suggest the following:

<pre><code>public class Main {

 public static void main(String[] args) {

 String path = "file.txt";
 String extension = ".doc";

 int position = path.lastIndexOf(extension);

 if (position!=-1)
 path = path.substring(0, position);
 else
 System.out.println("Extension: "+extension+" not found");

 System.out.println("Result: "+path);
 }

}
</code></pre>

If the substring is not found, nothing happens, as there is nothing to cut off. You won't get the <code>StringIndexOutOfBoundsException</code>. Also, you don't have to count the characters yourself in the substring.

blocks|key|445609|text|import+org.apache.commons.lang3.StringUtils;

//+path+=+"http://cdn.gs.com/new/downloads/Q22010MVR_PressRelease.pdf.null"
StringUtils.removeEnd(path,+".null");
//+path+=+"http://cdn.gs.com/new/downloads/Q22010MVR_PressRelease.pdf"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|445610|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import org.apache.commons.lang3.StringUtils;

// path = "http://cdn.gs.com/new/downloads/Q22010MVR_PressRelease.pdf.null"
StringUtils.removeEnd(path, ".null");
// path = "http://cdn.gs.com/new/downloads/Q22010MVR_PressRelease.pdf"
</code></pre>

blocks|key|660035|text|另一种方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|660036|if+(s.size+>+5)+s.reverse.substring(5).reverse|code-block|syntax|javascript|660037|顺便说一句，这是Scala代码。可能需要括号才能在Java中工作。|660038|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Another way:

<pre><code>if (s.size &gt; 5) s.reverse.substring(5).reverse
</code></pre>

BTW, this is Scala code. May need brackets to work in Java.

A java String variable whose value is

<pre><code>String path = "http://cdn.gs.com/new/downloads/Q22010MVR_PressRelease.pdf.null"
</code></pre>

I want to remove the last four characters i.e., <code>.null</code>. Which method I can use in order to split.

Remove the last chars of the Java String variable

Java

java字符串变量，其值为String path = "http://cdn.gs.com/new/downloads/Q22010MVR_PressRelease.pdf.null"我想删除最后四个字符，即.null。我可以使用哪种方法来拆分。

问删除Java字符串变量的最后一个字符
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