我使用的是Java,我有一个JSON字符串:
{
"name" : "abc" ,
"email id " : ["abc@gmail.com","def@gmail.com","ghi@gmail.com"]
}
然后是my Map in Java:
Map<String, Object> retMap = new HashMap<String, Object>();
我希望将JSONObject中的所有数据存储在该HashMap中。
有人能提供这方面的代码吗?我想使用org.json
库。
发布于 2014-06-03 17:49:08
几天前我用递归写了这段代码。
public static Map<String, Object> jsonToMap(JSONObject json) throws JSONException {
Map<String, Object> retMap = new HashMap<String, Object>();
if(json != JSONObject.NULL) {
retMap = toMap(json);
}
return retMap;
}
public static Map<String, Object> toMap(JSONObject object) throws JSONException {
Map<String, Object> map = new HashMap<String, Object>();
Iterator<String> keysItr = object.keys();
while(keysItr.hasNext()) {
String key = keysItr.next();
Object value = object.get(key);
if(value instanceof JSONArray) {
value = toList((JSONArray) value);
}
else if(value instanceof JSONObject) {
value = toMap((JSONObject) value);
}
map.put(key, value);
}
return map;
}
public static List<Object> toList(JSONArray array) throws JSONException {
List<Object> list = new ArrayList<Object>();
for(int i = 0; i < array.length(); i++) {
Object value = array.get(i);
if(value instanceof JSONArray) {
value = toList((JSONArray) value);
}
else if(value instanceof JSONObject) {
value = toMap((JSONObject) value);
}
list.add(value);
}
return list;
}
使用Jackson库:
import com.fasterxml.jackson.databind.ObjectMapper;
TypeReference<HashMap<String, Object>> typeRef = new TypeReference<>() {};
Map<String, Object> mapping = new ObjectMapper().readValue(jsonStr, typeRef);
发布于 2014-02-12 15:06:25
使用Gson,您可以执行以下操作:
Map<String, Object> retMap = new Gson().fromJson(
jsonString, new TypeToken<HashMap<String, Object>>() {}.getType()
);
发布于 2017-06-08 23:41:41
希望这能起作用,试试这个:
import com.fasterxml.jackson.databind.ObjectMapper;
Map<String, Object> response = new ObjectMapper().readValue(str, HashMap.class);
str,您的JSON字符串
就这么简单,如果你想要emailid,
String emailIds = response.get("email id").toString();
https://stackoverflow.com/questions/21720759
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