blocks|key|1054579|text|Math.ceil()是要调用的正确函数。我猜a是一个int，它会让a+/+100执行整数运算。请尝试使用Math.ceil(a+/+100.0)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1054580|int+a+=+142;
System.out.println(a+/+100);
System.out.println(Math.ceil(a+/+100));
System.out.println(a+/+100.0);
System.out.println(Math.ceil(a+/+100.0));
System.out.println((int)+Math.ceil(a+/+100.0));|code-block|syntax|javascript|1054581|输出：|1054582|1
1.0
1.42
2.0
2|1054583|请参阅http://ideone.com/yhT0l|1054584|entityMap|0|LINK|mutability|MUTABLE|url|http://download.oracle.com/javase/6/docs/api/java/lang/Math.html#ceil(double)|1|http://ideone.com/yhT0l^0|0|B|N|1|R|3|Y|7|1H|K|0|B|0|0|0|0|0|3|N|1|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]|$9|17|A|18|B|C]|$9|19|A|1A|B|C]]|D|@$9|1B|A|1C|1|1D]]|E|$]]|$1|F|3|G|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1F|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|1G|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1H|8|@]|D|@$9|1I|A|1J|1|1K]]|E|$]]|$1|Q|3|-4|5|6|7|1L|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]|Y|$5|T|U|V|E|$W|Z]]]]

<a href="http://download.oracle.com/javase/6/docs/api/java/lang/Math.html#ceil(double)" rel="noreferrer"><code>Math.ceil()</code></a> is the correct function to call. I'm guessing <code>a</code> is an <code>int</code>, which would make <code>a / 100</code> perform integer arithmetic. Try <code>Math.ceil(a / 100.0)</code> instead.

<pre><code>int a = 142;
System.out.println(a / 100);
System.out.println(Math.ceil(a / 100));
System.out.println(a / 100.0);
System.out.println(Math.ceil(a / 100.0));
System.out.println((int) Math.ceil(a / 100.0));
</code></pre>

Outputs:

<pre><code>1
1.0
1.42
2.0
2
</code></pre>

See <a href="http://ideone.com/yhT0l" rel="noreferrer">http://ideone.com/yhT0l</a>

blocks|key|1054633|text|我不知道为什么你要除以100，但这里我的假设是int+a;|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1054634|int+b+=+(int)+Math.ceil(+((double)a)+/+100);|code-block|syntax|javascript|1054635|或|1054636|int+b+=+(int)+Math.ceil(+a+/+100.0);|1054637|entityMap^0|N|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

I don't know why you are dividing by 100 but here my assumption <code>int a;</code>

<pre><code>int b = (int) Math.ceil( ((double)a) / 100);
</code></pre>

or 

<pre><code>int b = (int) Math.ceil( a / 100.0);
</code></pre>

blocks|key|1054689|text|int+RoundedUp+=+(int)+Math.ceil(RandomReal);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1054690|这似乎完成了完美的工作。每次都很有效。|unstyled|1054691|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>int RoundedUp = (int) Math.ceil(RandomReal);
</code></pre>

This seemed to do the perfect job. Worked everytime.

blocks|key|840010|text|假设a是双精度的，我们需要一个不带小数位的四舍五入的数字。使用Math.round()函数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|840011|这是我的解决方案。|840012|double+a+=+0.99999;
int+rounded_a+=+(int)Math.round(a);
System.out.println("a:"%2Brounded_a+);

Output+:+
a:1|code-block|syntax|javascript|840013|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Assuming a as double and we need a rounded number with no decimal place . Use Math.round() function. 
This goes as my solution . 

<pre><code>double a = 0.99999;
int rounded_a = (int)Math.round(a);
System.out.println("a:"+rounded_a );

Output : 
a:1
</code></pre>

blocks|key|1054795|text|最简单的方法是:你将收到一个浮点数或双精度数，并希望它转换为最接近的四舍五入，然后执行System.out.println((int)Math.ceil(yourfloat));，它会完美地工作|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1054796|entityMap^0|17|1A|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

The easiest way to do this is just: 
You will receive a float or double and want it to convert it to the closest round up then just do <code> System.out.println((int)Math.ceil(yourfloat)); </code>
it'll work perfectly

blocks|key|840144|text|10年后，这个问题仍然困扰着我。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|840145|因此，这就是对像我这样为时已晚的人的答案。|840146|这不起作用|840147|int+b+=+(int)+Math.ceil(a+/+100);|code-block|syntax|javascript|840148|因为结果a+/+100是一个整数，而且是四舍五入的，所以Math.ceil对此无能为力。|offset|length|style|CODE|840149|您必须使用以下代码避免四舍五入操作|840150|int+b+=+(int)+Math.ceil((float)+a+/+100);|840151|现在它起作用了。|840152|entityMap^0|0|0|0|0|4|7|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|11|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|12|8|@$M|13|N|14|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|15|8|@]|9|@]|A|$]]|$1|S|3|T|5|H|7|16|8|@]|9|@]|A|$I|J]]|$1|U|3|V|5|6|7|17|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|X|$]]

10 years later but that problem still caught me.

So this is the answer to those that are too late as me.

This does not work

<pre><code>int b = (int) Math.ceil(a / 100);
</code></pre>

Cause the result <code>a / 100</code> turns out to be an integer and it's rounded so Math.ceil 
can't do anything about it.

You have to avoid the rounded operation with this 

<pre><code>int b = (int) Math.ceil((float) a / 100);
</code></pre>

Now it works.

blocks|key|1054897|text|只是另一种选择。使用数学基础知识：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1054898|Math.ceil(p+/+K)与((p-1)+//+K)+%2B+1相同|offset|length|style|CODE|1054899|entityMap^0|0|0|G|H|G|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]|$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|I|$]]

Just another option. Use basics of math:
<code>Math.ceil(p / K)</code> is same as <code>((p-1) // K) + 1</code>

I can't seem to find the answer I'm looking for regarding a simple question: how do I round up any number to the nearest <code>int</code>?

For example, whenever the number is 0.2, 0.7, 0.2222, 0.4324, 0.99999 I would want the outcome to be 1.

So far I have

<pre><code>int b = (int) Math.ceil(a / 100);
</code></pre>

It doesn't seem to be doing the job, though.

Java Round up Any Number

对于一个简单的问题，我似乎找不到我想要的答案:如何将任何数字四舍五入到最接近的int例如，当数字是0.20.7，0.2222，0.4324，0.99999时，我希望结果是1。到目前为止，我已经int b = (int) Math.ceil(a / 100);不过，它似乎没有做到这一点。

问Java向上舍入任意数字
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